# Mixed Quantitative Aptitude Questions Set 227

1. A, B and C entered into a partnership business and A gets profit rs.960 out of total profit rs.5120. C invested rs.14000 for 8 months and B invested rs. 8000. If A invested rs.4000 more than that of B and 4 months less that of C, then find what is the profit share of C ?
2120
1345
1240
2240
1050
Option D
Investment of A = 8000 + 4000 = 12000
time period for investment of A = 8 – 4 = 4months
profit sharing ratio of A, B and C = (12000 * 4) : (8000 * 12) : (14000 * 8) = 3 : 6 : 7
profit share of C = 5120 * 7/16 = 2240

2. Amit invested rs.22500 in scheme X offering 10% compound interest for 2 years. If he invested 40% of the money received by him from scheme X in another scheme Y offering 20% simple interest for 4 years, then how much amount received by him from scheme Y ?
12340
38450
19602
20505
23420
Option C
CI received after 2 years = 22500 * 10/100 * 10/100 = 4725
total amount = 22500 + 4725 = 27225
40 % of 27225 = 10890
SI received after 4 years = 27225 * 40/100 * 4 * 20/100 = 8712
total amount = 10890 + 8712 = 19602

3. The monthly income of A is rs.28000 and he saves 28 4/7% of his monthly income. If the monthly expenditure of B is rs.4000 more than A and also expenditure of B is 20% less than his income, then find saving of B is how much percent more or less than savings of A ?
20%
30%
15%
25%
22%
Option D
Income of A = 28000
savings of A = 28000 * 2/7 = 8000
expenditure of A = 28000 – 8000 = 20000
expenditure of B = 20000 + 4000 = 24000
income of B = 24000/4 * 5 = 30000
saving of B = 30000 – 24000 = 6000
% less = 8000 – 6000/8000 * 100 = 25%

4. The ratio of male to female in a company is 5 : 3 and the number of male in the company is 1250. If the number of female and male is increased by 10% and 8% respectively, then find what percent change in total population ?
5.2%
6%
8%
7.25%
8.75%
Option E
The number of male = 1250
the number of female = 1250/5 * 3 = 750
the number of male after increased = 1250 * 108/100 = 1350
the number of female after increased = 750 * 110/100 = 825
total population = 1250 + 750 = 2000
total population after increased = 1350 + 825 = 2175
change in population = 2175 – 2000/2000 = 8.75%

5. A man travels 150 km to a place in 3 hours 20 minutes and he returns to the starting point in 4 hours 10 minutes. Let x be the rate for the entire trip. Then in how many kilometers per hour more or less than x ?
4 km/hr
2 km/hr
4.5 km/hr
5 km/hr
8 km/hr
Option D
Time taken to cover 150 km in going trip
3 hours 20 minutes = 3 20/60 = 3 1/3 hours
speed in going trip = 150 *3/10 = 45 km/hr
time taken to cover 150 km in return trip = 4 hours 10 minutes = 4 1/6 hours
speed in return trip = 150 * 6/25 = 36 km/hr
average speed = 2 * 45 * 36/ 45 + 36 = 40 km/hr
required difference = 45 – 40 = 5 km/hr

6. Direction : What will come in place of question(?) mark in the following questions given below ?
60% of 1800 + 24% of 3500 – 32% of 150 = ?
1992
1872
2092
1532
1240
Option B
1080 + 840 – 48 = ?
? = 1872

7. 3/5 * 4/7 * 5/12 * 1015 = ?
120
145
167
89
52
Option B
? = 3/5 * 4/7 * 5/12 * 1015
? = 145

8. 4545 + 4320 – 2540 + 320 = ?
3642
2720
4520
6645
3435
Option D
4545 + 4320 + 320 – 2540 = ?
? = 6645

9. 330 – 345 + 421 – 22% of 1500 = ?
76
32
45
52
65
Option A
330 + 421 – 345 – 330 = ?
? = 76

10. 552 ÷ 24 * 5 + 113 – 85 = ?
144
143
320
245
145
Option B
23 * 5 + 113 – 85 = ?
? = 143