Mixed Quantitative Aptitude Questions Set 73

Banya
  1. Hetal is twice as good workman as Nikki and finished a piece of work in 5 hrs less than Hetal. In how many hrs, they together could finish that piece of work?
    2.52 hrs.
    4.2 hrs.
    3.33 hrs .
    1.15 hrs.
    None of these
    Option C
    Let the time taken by Nikki be x and by Hetal be x/2. Then, x-x/2 = 5
    => x = 10
    Time taken by both of them to finish the work = 1/10+ 1/5 = 3.33 hrs.

     

  2. A man’s downstream swimming rate is thrice of his upstream swimming rate .The rate of stream is 3 kmph. If he covers 12 km upstream in 2.5 hours, what distance he will cover in 5 hours downstream?
    60 km
    72 km
    55 km
    75 km
    80 km
    Option B
    Rate of man in upstream direction = 12/2.5 = 4.8km/hr.
    Hence, required distance = 3 *4.8 *5 = 72km

     

  3. A water tank has two inlet taps which fill it in 20 minutes and 30 minutes, respectively and an outlet tap. When all the three taps are opened together, it takes 60 minutes to fill an empty cistern. How long will the outlet tap take to empty it?
    1.5 mins.
    2 mins.
    3.2 mins.
    5 mins.
    4.4 mins.
    Option A
    Let x be the time taken by outlet tap.
    Required time = (1/20 + 1/30 – 1/x) = 1/60
    => x = 1.5 mins.

     

  4. The ratio of the present age of Arav to that of Anil is 3 : 11. Anil is 12 years younger than Anuj. Anuj’s age after 7 years will be 85 years. What is the present age of Arav’s father, who is 25 years older than Arav?
    43 yrs.
    38 yrs.
    50 yrs.
    45 yrs.
    55 yrs.
    Option A
    Let the present age of Arav and Anil be 3x and 11x.
    11x = 85 – 7 – 12
    => x = 6
    Present age of Arav = 18 years
    Present age of Arav father = 18 + 25 = 43 years

     

  5. 10 boys can complete any work in 32 days. 15 girls can complete the same piece of work in 64 days. 8 boys and 18 girls work together for 20 days. If only the girls were to complete the remaining work in 12 days, then how many girls would be required?
    20 girls
    15 girls
    12 girls
    25 girls
    10 girls
    Option E
    10 boys × 32 days = 15 girls × 64 days
    => 1 boy= 3 girls
    => (8 boys + 18 girls) × 20 days + x girls × 12 days = 15 girls × 64 days
    =>(24+18)*20 + 12x = 15*64
    => x = 10 girls

     

  6. There are two trains of same lengths one take 20 seconds and 30 seconds respectively to cross a telegraph post. Trains are travelling in opposite direction if the length of each train be 150 metres.In what time (in seconds) will they cross each other ?
    30 sec.
    24 sec.
    40 sec.
    20 sec.
    35 sec.
    Option B
    Relative speed = 150/20 + 150/30
    = 7.5 + 5 = 12.5 m/sec.
    Therefore, the required time= (150 + 150)/12.5 = 24 sec.

     

  7. A seller bought 100 tables at the rate of 250 each. He spends 2000 rupees on transportation. He marked the price of each chair at 500 rupees. On the marked price he gives 10% discount. Find the profit incurred by the seller?
    66.67
    41.15
    52.25
    60
    None of these
    Option A
    Cost price of each tables = 250 + 2000/100 = Rs.270 Selling Price = (500 * 90 )/100 = 450
    %profit = (450-270)/270 = 66.67

     

  8. The perimeter of a rectangular field is 120 m and the difference between its two adjacent sides is 40 m. The sides of the square field whose area is equal to this rectangular field ?
    10root(3)
    4root(2)
    10root(5)
    5root(5)
    11root(6)
    Option C
    Perimeter of rectangle = 2(l + b) = 120 l + b = 60m — (1) l – b = 40m –(2)
    From (1) and (2) l = 50 m
    b = 10m
    Area of rectangle = 500m² = Area of Square
    Side of a square = 10√5

     

  9. How many 4-letter words with or without meaning, can be formed out of the letters of the word, ‘ARITHMETIC’, if repetition of letters is not allowed?
    5040 ways
    4500 ways
    5000 ways
    3250 ways
    1024 ways
    Option A
    Required ways = 10P4 = 10*9*8*7 = 5040 ways

     

  10. Out of 5 girls and 4 boys, an assignment of three members is to be formed in such a way that at least one member is girl. In how many different ways can this be done?
    60 ways
    70 ways
    80 ways
    90 ways
    50 ways
    Option C
    5C1 × 4C2 + 5C2 × 4C1 +5C3 5 × 4*3/2 + 5*4*4/2 + 5*4*3/3*2
    = 30 + 40 + 10 = 80 ways

     


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