Quantitative Aptitude: Inequalities Set 6 (Based on SBI PO Mains 2017)

New Pattern Inequalities Questions Type asked SBI PO for upcoming IBPS PO Mains 2017, NICL, LIC, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams. 

Directions: Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship among them. Mark your answer accordingly.

  1. Answer the question based on the figure given below: (figure not to scale)

    Quantity I: angle x
    Quantity II: 110
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
    Option C
    Solution
    :
    In triangle BCE, angle y= 180-(40+20)= 120
    Sum of exterior angle of a quadrilateral is 360 degree
    So in quadrilateral ABCD; 50 + y +x+90=360 [y=120]
    x=100 degree
  2. X and Y stand in a line at random with 5 other people
    Quantity I: Probability that there are 3 people between X and Y
    Quantity II: Probability that at least one from A or B qualifies the exam when probability of A qualifying the exam is 0.3 and probability of B qualifying the exam is 0.4
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
      Option C
    Solution
    :
    I: There are 7 people in total including X and Y; consider 7 position numbered 1,2,….,6,7
    When X is at 1, then Y is at 5 or vice versa; When X is at 2, Y is at 6 or vice versa and When X is at 3 then Y is at 7. Means there are 3 possible seating arrangement for X and Y when there is a gap of 3 people between them.
    total ways of X and Y sitting in any two position = 7C2= 21
    P=3/21=1/7II: P(either)= [1-P(None)]= [1-P(not A)*P(not B)]=[1- (0.7*0.6)]
    =0.56
    II>I
  3. AB is parallel to DC and AD is parallel to BC. BD is 4 cm greater than AC. AC and BD are the diagonal with O as point of intersection.

    Quantity I: AB
    Quantity II: 9 cm
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
    Option A
    Solution
    :
    I: ABCD is a parallelogram as opposite sides are parallel. In a parallelogram the diagonal are divided in equal part at the point of intersection. So Ac= 2OC=12
    BD=16 cm
    means OB=8 and OA= 6
    in triangle AOB; use Pythagoras theorem to find AB=10 cm
  4. It takes (X-2) men to do a work in 2Y days and it takes (X+6) men to do the same work in Y days.
    Quantity I: X
    Quantity II: Y
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
    Option E
    Solution
    :
    As the time is becoming half so means number of people have doubled; So (X+6)=2*(X-2)=>X=10
    Using M1D1=M2D2 the value of Y cannot be found. Y can take any value. So we cannot determine a unique value of Y
  5. A hemisphere of radius 4 cm is to be shipped in a shipping box of rectangular shape. The dimension of the box are consecutive odd numbers.
    Quantity I: Minimum volume of box required to have the shipment possible.
    Quantity II: 960 cm3
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
    Option A
    Solution
    :
    I: The minimum length of any side of rectangular box should be greater than the diameter of the hemisphere. Diameter of hemisphere=8; So for odd number, minimum length= 9, next side =11, next side=13
    Volume=9*11*13= 1287 cm3
  6. In a container there are 20 eggs out of which 5 are rotten. Two eggs are chosen at random.
    Quantity I: Probability that at least one egg is rotten
    Quantity II: Average of (1/2), (1/3) and (1/5)
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
      Option A
    Solution
    :
    I: Total way of selecting 2 eggs from 20 eggs = 20C2= 190
    For at least 1 rotten egg = (1 rotten and 1 good egg ) + 2 rotten egg = 15C1*5C1 + 5C2= 85
    P= 85/190=17/38
    II=[ ½ + 1/3 + 1/5]/3 = 0.34
  7. The figure shows a circle and a figure inscribed inside the circle. Angle a° is an acute angle

    Quantity I: Angle x°
    Quantity II: 70
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
    Option A
    Solution
    :
    a is an acute angle means less than 90° . In trangle ABC; Angle BAC + A + 20= 180
    => Angle BAC + A = 160
    As A is less than 90 hence BAC will be greater than 160-90=70
    and Angle x= Angle BAC (Angles in the same segment are equal)
    Hence x>70
  8. The speed of boat in still water is 4 kmph more than the speed of stream. The sum of distance covered by boat in 2 hours upstream and 2 hours downstream is 28 km.
    Quantity I: Distance travelled by boat downstream in 5 hours.
    Quantity II: Average speed of Siddharth while driving a car from home to office and back when travelling at a speed of 50 kmph from home to office and at a speed of 40 kmph from office to home.
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
    Option A
    Solution
    :
    Let y= speed of stream=a
    x= speed of boat in still water=a+4
    2(Upstream Speed) + 2(Downstream Speed) = 28
    2*4 + 2(2a+4)=28
    a=3
    Hence downstream speed=10
    Distance=5*10=50 km
    Average speed=2*50*40/(50+40)=44.44 kmph
  9. 3 racers A,B and C take part in a race. The racing track is in the form of concentric circles with 3 track one for A, one for B and one for C as shown in the figure. A has to start from a and reach back to a to complete his race. Similarly B and C will start and end at b and c respectively. The radius of outer most track is 77 m. and the distance between two consecutive track is 7 cm. Speed of A= 8 m/s, Speed of B= 9 m/s and Speed of C= 9.5 m/s

    Quantity I: Speed of the person who reaches his destination first.
    Quantity II: 9
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
    Option E
    Solution
    :
    I: circumference of circle c= 2πr=2π*77=484
    circumference of circle b= 2π*70=440
    circumference of circle a= 2π*63= 396
    Time taken by A= 396/8= 49.5 s
    Time taken by B= 440/9=48.88 s
    Time taken by C= 484/9.5= 50.94 s
    So B reaches first and his speed is 9 m/s
  10. A metal gate of dimension 5 m × 1.5 m (width* height) has some ‘n’ number of division each of equal dimension of 5 cm × 2 cm (width* height). One division is selected from this ‘n’ division.
    Quantity I: Probability that the selected division is in the topmost row
    Quantity II: Probability that the selected division in the leftmost column
    A) Quantity I > Quantity II
    B) Quantity I ≥ Quantity II
    C) Quantity II > Quantity I
    D) Quantity II ≥ Quantity I
    E) Quantity I = Quantity II or Relation cannot be established
    View Answer
    Option A
    Solution
    :

    Number of column= 500/5=100
    Number of rows= 150/2=75
    total division=100*75
    I: P (top row)= top row division/ total division= 100/75*100= 1/75
    II: P(left most column)= left row division/total division= 75/75*100=1/100

Click here for More Questions on New Pattern Inequalities

 

 

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34 Thoughts to “Quantitative Aptitude: Inequalities Set 6 (Based on SBI PO Mains 2017)”

  1. Overt

    thankyou sir :))

  2. Destiny : Ultimate

    thanku sir 🙂

  3. Ambika

    thankyou suraj sir :))

    1. ครђ

      Is tarah ke geometry wale ques the ambi mains me?

        1. ครђ

          🙂 Ok ambi …

    2. DEEP..!!

      back to karm bhoomi…:)

        1. DEEP..!!

          how r u dear?

          1. Ambika

            good :))
            u say …how was the exam ??/

          2. DEEP..!!

            disastrous i must say,never want to appear for it further.i am scared of future prospects,how to handle it without having question at par of SBI PO level and ST based on the questions likewise.

          3. Ambika

            yaa it was really bad :(((((
            just hope for the best ..all the best hi bol sakte ab to :))

          4. DEEP..!!

            der was nothing fortunate happen on that day and why would i hope unexpected as i know the fact…!!

          5. DEEP..!!

            hey ambi,is it any other forum to connect you rather disqus?

          6. Trisha

            Wow, U became MOD..
            nice..

          7. AMAZON

            Don’t worry , level was hard for all.

  4. AVI™ (Sinchen loveR)

    Thnxxss :'(

  5. Jenny

    Thnk yu suraj sir nd AZ 🙂

  6. PHOENIX

    ty suraj sir.

  7. MAYANK BHARADWAJ100%

    tks

    1. MAYANK BHARADWAJ100%

      concept same but data different

  8. ครђ

    Thankyou AZ team 🙂

  9. Sachin Shukla

    thankuu.)

  10. Jellyfish

    Thx sir /mam
    Pls if u have any notes in geometry provide me.

  11. KUCH B........

    nainai ye to bilkul galt h mam ji:((

      1. KUCH B........

        ye measuration ke sum sbi mains me aaye h wo:(

        1. Yes. 3 aae the geometry se

          1. PHENOMENAL

            maam new type k word prblm bhi provide kriye as came in sbi po mains from basic

          2. KUCH B........

            ibps po me chance h pher to 3 marks ku chodu me:( meansuration sikh leta hu

      2. Trisha

        couldn’t understand Q.10
        pls explain if possible

      3. AMAZON

        total ways of X and Y sitting in any two position = 7C2= 21
        sir in this question if 3 are the possible ways then why you took 7C2 rather 7C3. please explain

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