Quantitative Aptitude: Quadratic Equations Set 13

Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly –

  1. I. 20x2 – 31x + 12 = 0,
    II. 3y2 – 5y + 2 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option E
    Solution:

    20x2 – 31x + 12 = 0
    20x2 – 16x – 15x + 12 = 0
    So x = 3/4, 4/5
    3y2 – 5y + 2 = 0
    3y2 – 3y – 2y + 2 = 0
    So y = 1, 2/3
  2. I. 3x2 – 19x + 30 = 0,
    II. 3y2 – 10y + 3 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option C
    Solution:

    3x2 – 19x + 30 = 0
    3x2 – 9x – 10x + 30 = 0
    So x = 3, 10/3
    3y2 – 10y + 3 = 0
    3y2 – 9y – y + 3 = 0
    So y = 1/3, 3
  3. I. 3x2 – 25x + 52 = 0,
    II. 5y2 – 18y + 9 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option A
    Solution:

    3x2 – 25x + 52 = 0
    3x2 – 12x – 13x + 52 = 0
    So x = 4, 13/3
    5y2 – 18y + 9 = 0
    5y2 – 15y – 3y + 9 = 0
    So y = 3/5, 3
    Put on number line
    -1/2 …. 3/5 ….2/3 …. 3
  4. I. 4x2 – 5x – 6 = 0,
    II. 5y2 – 7y – 6 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option E
    Solution:

    4x2 – 5x – 6 = 0
    4x2 – 8x + 3x – 6 = 0
    So x = -3/4, 2
    5y2 – 7y – 6 = 0
    5y2 – 10y + 3y – 6 = 0
    So y = -3/5, 2
  5. I. 3x2 – 10x + 8 = 0,
    II. 3y2 – 14y + 16 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option D
    Solution:

    3x2 – 10x + 8 = 0
    3x2 – 6x – 4x + 8 = 0
    So x = 2, 4/3
    3y2 – 14y + 16 = 0
    3y2 – 6y – 8y + 16 = 0
    So y = 2, 8/3
  6. I. 2x2 + 17x + 30 = 0,
    II. 4y2 – 7y – 15 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option B
    Solution:

    2x2 + 17x + 30 = 0
    2x2 + 12x + 5x + 30 = 0
    So x = -6, -5/2
    4y2 – 7y – 15 = 0
    4y2 – 12y + 5y – 15 = 0
    So y = -5/4, 3
  7. I. 3x2 + 16x + 20 = 0,
    II. 5y2 + 8y – 4 = 0
    A) x > y
    B) x < y
    C) x ≥ y
    D) x ≤ y
    E) x = y or relationship cannot be determined
    View Answer
    Option D
    Solution:

    3x2 + 16x + 20 = 0
    3x2 + 6x + 10x + 20 = 0
    So x = -10/3, -2
    5y2 + 8y – 4 = 0
    5y2 + 10y – 2y – 4 = 0
    So y = -2, 2/5
  8. I. 2x2 + 17x + 21 = 0,
    II. 2y2 + 13y + 15 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option E
    Solution:

    2x2 + 17x + 21 = 0
    2x2 + 14x + 3x + 21 = 0
    So x = -7, -3/2
    2y2 + 13y + 15 = 0
    2y2 + 10y + 3y + 15 = 0
    So y = -5, -3/2
  9. I. 5x2 – 7x – 6 = 0,
    II. 3y2 – 19y + 28 = 0
    A) If x > y
    B) If x < y
    C) If x ≥ y
    D) If x ≤ y
    E) If x = y or relation cannot be established
    View Answer
    Option B
    Solution:

    5x2 – 7x – 6 = 0
    5x2 – 10x + 3x – 6 = 0
    So x = -3/5, 2
    3y2 – 19y + 28 = 0
    3y2 – 12y – 7y + 28 = 0
    So y = 7/3, 4
  10. I. 8x2 + 6x – 5 = 0,
    II. 2y2 + 7y – 4 = 0
    A) x > y
    B) x < y
    C) x ≥ y
    D) x ≤ y
    E) x = y or relationship cannot be determined
    View Answer
    Option E
    Solution:

    8x2 + 6x – 5 = 0
    8x2 – 4x + 10x – 5 = 0
    So x = -5/4, 1/2
    2y2 + 7y – 4 = 0
    2y2 + 8y – y – 4 = 0
    So y = -4, 1/2

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39 Thoughts to “Quantitative Aptitude: Quadratic Equations Set 13”

  1. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

    mam last ques …plz check E ans hai na uska

    1. PHOENIX

      hey dear, have u attempted PM’s 13th ST…if yes,pls let me know the approach to solve Q81-85 & in Q64,23 came from where.. ??

      1. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

        no dear i had 5 st only :pp u can post here i ll try

          1. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            see it is very simple type of ques just keep in mind the conditions given …….like the first number is 12 its is an even no and followed by odd no viz. 21 so . so we will apply condition no. 3

            means 12 + 21 = 33 ok…… now move further…we have to take this result means 33 as the next value to be considered so 33 is now followed by 11 so here we ll apply condition no.2 i.e 33-11 = 22
            now.. 22 is followed by 8 so here comes the condition no. 1 means 22 * 8/ 4 = 44
            then 44 is the value of X here now with 3 we ll use condition no.3 so 44 + 3 = 47 then for 23 we ll use no. 2 so 47 – 23 = 24 then last we ll apply condition no. 3 so the answer is 24 + 11 = 35 …..:))

            these ques were introduced last year in sbi po mains …see if u get it

          2. MiMi

            okkk i got it..bohat esy qstn :0

          3. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            :)) hmmm hai to easy but jab new type ke ques aa jayen exam main to boht panic ho jate hain hum chahe easy hi hon

          4. MiMi

            haa right sis…

          5. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            :))

          6. MiMi

            sbi po main ka previous year qstns paper hai tmhara pass?

          7. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            hmm sab hain

          8. MiMi

            muje pls mail kar do

          9. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            hmm kar deti hun

          10. MiMi

            thnk u sis ;))

          11. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            :)) id do mere pass hai nhi

          12. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            ok kar do remove

          13. Enrique

            Hi, Ambika 🙂 Mujhe bhi chahiye previous year questions ,pls mail
            ashu.agarwal64@gmail.com

          14. !!angry bird !!

            mam plz aap kya muje de sekte h sbi k paper ?

          15. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            sure dear no pblm

          16. !!angry bird !!

            Ty so much mam gn

          17. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            remove it dear i ll mail u

          18. !!angry bird !!

            OK tyyyyyy 🙂

          19. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            see u got the mail ????

          20. !!angry bird !!

            yes mam ty 🙂

          21. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            🙂 SURE

          22. PHOENIX

            TY understood…so easy:)

          23. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

            :))

    2. MiMi

      hmm E hoga ansr..

      1. (¯·.¸¸.-> °º åɱβȋ º° <-.¸¸.·¯)

        hmmm

  2. golden girl

    thanku 🙂

  3. !!angry bird !!

    ty 🙂 9/10 🙁

  4. Enrique

    10/10 in 7:47 mins.
    Thanks Shubhra Ma’am 🙂

  5. "sandeep "'''Mission 2017'''

    thnx mam

  6. jaga

    Thank u mam 🙂

  7. Giridhar katti

    Hello mam
    6 ans E hona chahiye please ek baar check karke ans bataiye mam

    1. No its correct

      Put the values on number line

      -6… -5/2…. -5/4….3

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