Type of Quadratic Equations Questions Asked in All Exams – Bank PO, Insurance and Other related Exams.

**Directions: In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-**

- I. 20x
^{2}– 31x + 12 = 0

II. 3y^{2}– 16y + 16 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established

- I. 3x
^{2}+ 22 x + 24 = 0

II. 2y^{2}– 5y – 12 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established

- I. 2x
^{2}– 9x + 4 = 0

II. 4y^{2}– 13y – 12 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established

- I. 5x
^{2}+ 23x + 12 = 0

II. 5y^{2}– 7y – 6 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established

- I. 7x
^{2}+ 19x – 6 = 0,

II. 2y^{2}– 7y + 3 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established

- I. 4x
^{2}– 12x + 5 = 0,

II. 2y^{2}– 19y + 35 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established

- I. 2x
^{2}+ 5x ¬– 12 = 0,

II. 4y^{2}+ 13y – 12 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established

- I. 3x
^{2}+ 22x + 24 = 0,

II. 4y^{2}– 9y – 9 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established

- I. 20x
^{2}– 31x + 12 = 0,

II. 4y^{2}+ 9y – 9 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established

- I. 6x
^{2}– 7x – 3 = 0,

II. 4y^{2}+ 5y – 6 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relation cannot be established