Quantitative Aptitude: Data Interpretation Questions Set 49

Directions(1-5): The table shows the number of people staying in five different localities and the percentage-wise breakup of Men,Women and Children. Study the table carefully and answer the related questions.

1. If 20% of the men staying in locality D are working in Infosys and the 40% of the women staying in locality B are working in HCL, then what is the difference between the number of men staying in locality D who are working in Infosys and the number of women staying in locality B who are working in HCL?
   A) 900
   B) 1300
   C)1000
   D)1400
   E) 800
   
   View Answer

     Option D
   Solution:
   Number of men staying in locality D who are working in Infosys = 12000*(35/100)*(20/100) = 840
   Number of women staying in locality B who are working in HCL = 16000*(35/100)*(40/100) = 2240
   Required difference = 2240 – 840 = 1400
   
2. Number of children staying in localities A and B together is approximately what percent of the number of children staying in localities D & E together?
   A)  48%
   B) 68.42%
   C)50%
   D) 42.54%
   E) 60.15%
   
   View Answer

     Option B
   Solution:
   Number of children staying in A and B together = 18000*(20/100) + 16000*(10/100) = 5200
   Number of children staying in D & E together = 12000*(25/100) + 2000*(23/100) = 7600
   Required % = (5200/7600)*100= 68.42%
   
3. If  40% of the women staying in locality C are graduate and 60% of the men staying in locality E are post graduate then what is the ratio between the number of graduate women staying in locality C and the number of post graduate men staying  in locality E?
   A) 1:2
   B) 3:2
   C)1:4
   D) 5:2
   E) 4:5
   
   View Answer

     Option A
   Solution:
   Number of graduate women  staying in C = 15000*(45/100)*(40/100)= 2700
   Number of post graduate men staying in E = 20000*(45/100)*(60/100)= 5400
   Required ratio = 1:2
   
4. What is the difference between the total number of men staying in all the localities together and that of women staying in all the localities together ?
   A) 6500
   B) 6300
   C) 6000
   D) 6500
   E) 6250
   
   View Answer

     Option E
   Solution:
   Number of men staying in A, B, C, D and E =
   18000*(45/100) + 16000*(55/100) + 15000*(40/100) + 12000*(35/100) + 20000*(45/100) = 8100+8800+6000+4200+9000= 36100
   Number of women staying in A, B, C, D and E =18000*(35/100) + 16000*(35/100)  + 15000*(45/100) + 12000*(40/100) + 20000*(32/100) = 6300+5600+6750+4800+6400 = 29850
   Required Difference = 36100 – 29850 = 6250
   
5. If 40% of the men staying in locality A are self employed, then the self employed men staying in locality A is approximately what percent of the number of women staying in locality B ?
   A) 60%
   B)58%
   C)45%
   D) 42%
   E) 55%
   
   View Answer

     Option B
   Solution:
   Number of self-employed men staying in locality A = 18000*(45/100)*(40/100) = 3240
   Number of women staying in locality B = 16000*(35/100) = 5600
   Required % = (3240/5600)*100 = 57.86%= 58%(approx.)
   

Directions(6-10): The table shows the distribution of total number of phones manufactured and percentage of defective phones in five different companies in six different years . Study the table carefully and answer the related questions.

6. Number of non-defected phones manufactured by company D in 2017 is approximately what % of the number of non-defected phones manufactured by company C in 2014?
   A) 60%
   B) 58%
   C) 74%
   D) 55%
   E) 42%
   
   View Answer

     Option B
   Solution:
   Number of non-defected phones manufactured by company D in 2017 = 17800*(98.5/100) = 17533
   Number of non-defected phones manufactured by company C in 2014
   = 31000*(98/100) = 30380
   Required % = (17533/30380)*100 = 57.71% = 58%(approx.)
   
7. What is the ratio between the number of non-defected phones manufactured by company B in 2013 and that of company D in 2016?
   A) 8347:15826
   B) 8475:10457
   C) 4757:7458
   D) 5784:8453
   E) 6456:11450
   
   View Answer

     Option A
   Solution:
   Number of non-defected phones manufactured by company B in 2013 = 17000*(98.2/100) = 16694
   Number of non-defected phones manufactured by company D in 2016 = 32800*(96.5/100) = 31652
   Required ratio = 8347:15826
   
8. What is the total number of non-defective phones manufactured by company B in all the years together?
   A) 147855
   B) 247850
   C) 221748
   D) 117500
   E) 117147
   
   View Answer

     Option E
   Solution:
   Number of non-defective phones manufactured by B in all the  years = 15000*(98.4/100)+ 17000*(98.2/100)+ 14000*(99/100)+ 22000(98.5/100)+ 26000*(98.8/100)+ 25000*(97.9/100)
   = 14760+ 16694+ 13860+ 21670+ 25688+ 24475 = 117147
9. What is the difference between the total number of phones manufactured by company C and that of company E in all the years together?
   A) 17650
   B) 15000
   C) 16600
   D) 15850
   E) 18570
   
   View Answer

     Option C
   Solution:
   Required difference = 186000 – 169400 = 16600
   
10. Total number of defective phones manufactured by company A is approximately what % of the total number of defective phones manufactured by company D in all the  years together?
    A) 75%
    B) 80%
    C) 50%
    D) 100%
    E) 60%
    
    View Answer

      Option B
    Solution:
    Total number of defective phones by A in all the years = 12000*(2/100)+ 64000*(1.4/100)+ 72000*(2.1/100)+ 8000*(2.4/100)+ 16000*(1.8/100)+ 7800*(1/100)
    = 240+896+1512+192+288+78 = 3206
    Total number of defective phones by D in all the years = 41000*(2.3/100)+ 28500*(3/100)+ 27500*(2/100)+ 24500*(1/100)+ 32800*(3.5/100)+ 17800*(1.5/100)
    =943+855+550+245+1148+267 = 4008
    Required % = (3206/4008)*100 =79.99%= 80%
    

Click here for Data Interpretation Practice Sets