# Quantitative Aptitude: Data Interpretation Questions Set 58

Quantitative Aptitude Questions for IBPS RRB/PO/Clerk, SBI PO, UICL, OICL, NIACL, NICL, RBI Grade B/Assistant, and other competitive exams.

Directions(1-5): Study the following table to answer the given questions. 1. What is the difference between total number posts and clerks?
A) 42563
B) 45278
C) 32690
D) 25478
E) 52480
Option C
Solution:
Number of posts = 72760
Number of clerks = 105450
Difference = 105450 – 72760 = 32690
2. In Kolkata , number of Specialist Officers is approximately what per cent of that of Officers?
A) 12%
B) 10%
C) 6%
D) 8%
E) 11%
Option D
Solution:
Required % = (1200/14900)*100 = 8%
3. In Chennai, the number of Clerks is approximately how much per cent more than that of Officers?
A)  10%
B) 22%
C) 18%
D) 21%
E) 30%
Option B
Solution:
Required % = (2000/9000)*100 = 22%
4. Which centre has the highest number of candidates?
A) Delhi
B) Bangalore
C) Mumbai
D) Kolkata
E) Chennai
Option C
Solution:
Number of candidates:
Bangalore -> 2000 + 5000 + 50 + 2050 + 750 = 9850
Delhi -> 15000 + 17000 + 160 + 11000 + 750 = 43910
Mumbai -> 170000 + 19500 + 70 + 7000 + 900 = 44470
Kolkata -> 14900 + 17650 + 70 + 1300 + 1200 = 35120
5. Which centre has 300% more number of Clerks as compared to Bangalore?
A) Delhi
B) Mumbai
C) Bangalore
D) Chennai
Option E
Solution:
Number of Clerks in Hyderabad  = 20000 which is 300% more than 5000 at Bangalore.

Directions(6-10): Study the following table and answer the given questions. Note:
I). Data relate to the number of students studying in colleges A,B, C and D in the year 2009. The mentioned colleges offer courses in three streams only – Arts, Commerce and
Science.
II). Total students strength = students studying (Arts + Commerce + Science)

1. Number of students studying Arts in college C is what percent of number of students studying Arts in college D?
A) 18(2/3)
B) 21(2/3)
C) 17(1/2)
D) 20(3/2)
E) 11(1/3)
Option B
Solution:
In college C , Percentage of students who study science = 100 – 25 – 25 = 50%
Therefore , 50% == 1040
Then, Students who study Arts = (1040/50)*25 = 520
In college D , Percentage of students who study Science  = 100 – 50 – 30 = 20
Therefore, 20% == 960
Then, Students who study Arts  = (960/20)*50 = 2400
Required % = (520/2400)*100 = 65/3 = 21(2/3)
2. What is the total number of students studying Commerce in colleges C and D together?
A) 1078
B) 2000
C)1850
D) 1960
E) 2144
Option D
Solution:
Students who study Commerce :
College C = (1040/50)*25 = 520
College D = (960/20)*30 = 1440
Sum = 520 + 1440 = 1960
3. What is the average number of students studying Science in all the mentioned colleges?
A) 780
B) 875
C) 750
D) 800
E) 700
Option B
Solution:
Average number of students who study Science = (750 + 750 + 1040 + 960)/4
= 3500/4 = 875

4. What is the difference between the total student strength of college A and B together and that of colleges C and D together ?
A) 1850
B) 1999
C) 1480
D) 2250
E) 2380
Option E
Solution:
Total number of students:
College A ,
Therefore , 25% == 750
Then, 100% == (750/25)*100 = 3000
College B,
Therefore, 50% == 750
Then, 100% == (750/50)*100 = 1500
College C,
50%== 1040
Then , 100% == 1040*2 = 2080
College D,
20% == 960
Then, 100% == (960/20)*100 = 4800
Required difference  = (4800+2080) – (3000+1500)
= 6880 – 4500 = 2380
5. Total number of students studying Arts and Commerce together in college A is what percent more than that of college B ?
A) 156
B) 110
C) 200
D) 150
E) 198
Option C
Solution:
In college A,
Percentage of students who study Science = 100 – 20 – 55 = 25%
Therefore, 25% == 750
Students who study Arts = (750/25)*20 = 600
Students who study Commerce  = (750/25)*55 = 1650
Sum = 600+1650 = 2250
In college B,
Percentage of students who study in Science = 100 – 30 – 20 = 50%
Therefore , 50% == 750
Students who study Arts = (750/50)*30 = 450
Students who study Commerce  = (750/50)*20 = 300
Sum = 450+300 = 750
Required % = [(2250-750)/750]*100 = 200

## 9 Thoughts to “Quantitative Aptitude: Data Interpretation Questions Set 58”

1. Jellyfish

10/10
Thx banya mam

1. komal

In question 1 total no. Of officer kaise kiya batao plz

2. Soniya Nagpal

How post is assumed as officer???

1. ****

mistyping

3. Jitu

ty..))

4. jaga

thank u mam……

5. vamsy

Thank you mam, please upload chapter based DI for po mains it is requisite, no website is providing such questions, please help

6. Sylvester

Madam.. in question first you mentioned officer – clrk … But why u add post also…
Mam u don’t know mind get fuzzy

7. जय तिवारी ??

THNX AZ