Quantitative Aptitude: Data Interpretation Questions Set 58

Quantitative Aptitude Questions for IBPS RRB/PO/Clerk, SBI PO, UICL, OICL, NIACL, NICL, RBI Grade B/Assistant, and other competitive exams.

Directions(1-5): Study the following table to answer the given questions.

1. What is the difference between total number posts and clerks?
   A) 42563
   B) 45278
   C) 32690
   D) 25478
   E) 52480
   
   View Answer

     Option C
   Solution:
   Number of posts = 72760
   Number of clerks = 105450
   Difference = 105450 – 72760 = 32690
   
2. In Kolkata , number of Specialist Officers is approximately what per cent of that of Officers?
   A) 12%
   B) 10%
   C) 6%
   D) 8%
   E) 11%
   
   View Answer

     Option D
   Solution:
   Required % = (1200/14900)*100 = 8%
   
3. In Chennai, the number of Clerks is approximately how much per cent more than that of Officers?
   A)  10%
   B) 22%
   C) 18%
   D) 21%
   E) 30%
   
   View Answer

     Option B
   Solution:
   Required % = (2000/9000)*100 = 22%
   
4. Which centre has the highest number of candidates?
   A) Delhi
   B) Bangalore
   C) Mumbai
   D) Kolkata
   E) Chennai
   
   View Answer

     Option C
   Solution:
   Number of candidates:
   Bangalore -> 2000 + 5000 + 50 + 2050 + 750 = 9850
   Delhi -> 15000 + 17000 + 160 + 11000 + 750 = 43910
   Mumbai -> 170000 + 19500 + 70 + 7000 + 900 = 44470
   Kolkata -> 14900 + 17650 + 70 + 1300 + 1200 = 35120
   
5. Which centre has 300% more number of Clerks as compared to Bangalore?
   A) Delhi
   B) Mumbai
   C) Bangalore
   D) Chennai
   E) Hyderabad
   
   View Answer

     Option E
   Solution:
   Number of Clerks in Hyderabad  = 20000 which is 300% more than 5000 at Bangalore.
   

Directions(6-10): Study the following table and answer the given questions.

Note:
I). Data relate to the number of students studying in colleges A,B, C and D in the year 2009. The mentioned colleges offer courses in three streams only – Arts, Commerce and
Science.
II). Total students strength = students studying (Arts + Commerce + Science)

1. Number of students studying Arts in college C is what percent of number of students studying Arts in college D?
   A) 18(2/3)
   B) 21(2/3)
   C) 17(1/2)
   D) 20(3/2)
   E) 11(1/3)
   
   View Answer

     Option B
   Solution:
   In college C , Percentage of students who study science = 100 – 25 – 25 = 50%
   Therefore , 50% == 1040
   Then, Students who study Arts = (1040/50)*25 = 520
   In college D , Percentage of students who study Science  = 100 – 50 – 30 = 20
   Therefore, 20% == 960
   Then, Students who study Arts  = (960/20)*50 = 2400
   Required % = (520/2400)*100 = 65/3 = 21(2/3)
   
2. What is the total number of students studying Commerce in colleges C and D together?
   A) 1078
   B) 2000
   C)1850
   D) 1960
   E) 2144
   
   View Answer

     Option D
   Solution:
   Students who study Commerce :
   College C = (1040/50)*25 = 520
   College D = (960/20)*30 = 1440
   Sum = 520 + 1440 = 1960
   
3. What is the average number of students studying Science in all the mentioned colleges?
   A) 780
   B) 875
   C) 750
   D) 800
   E) 700
   
   View Answer

     Option B
   Solution:
   Average number of students who study Science = (750 + 750 + 1040 + 960)/4
   = 3500/4 = 875
   
4. What is the difference between the total student strength of college A and B together and that of colleges C and D together ?
   A) 1850
   B) 1999
   C) 1480
   D) 2250
   E) 2380
   
   View Answer

     Option E
   Solution:
   Total number of students:
   College A ,
   Therefore , 25% == 750
   Then, 100% == (750/25)*100 = 3000
   College B,
   Therefore, 50% == 750
   Then, 100% == (750/50)*100 = 1500
   College C,
   50%== 1040
   Then , 100% == 1040*2 = 2080
   College D,
   20% == 960
   Then, 100% == (960/20)*100 = 4800
   Required difference  = (4800+2080) – (3000+1500)
   = 6880 – 4500 = 2380
   
5. Total number of students studying Arts and Commerce together in college A is what percent more than that of college B ?
   A) 156
   B) 110
   C) 200
   D) 150
   E) 198
   
   View Answer

     Option C
   Solution:
   In college A,
   Percentage of students who study Science = 100 – 20 – 55 = 25%
   Therefore, 25% == 750
   Students who study Arts = (750/25)*20 = 600
   Students who study Commerce  = (750/25)*55 = 1650
   Sum = 600+1650 = 2250
   In college B,
   Percentage of students who study in Science = 100 – 30 – 20 = 50%
   Therefore , 50% == 750
   Students who study Arts = (750/50)*30 = 450
   Students who study Commerce  = (750/50)*20 = 300
   Sum = 450+300 = 750
   Required % = [(2250-750)/750]*100 = 200
   

         Click here for more questions on Data Interpretation