Quantitative Aptitude: Problems on Ages Set 22

  1. A person is 30 years older than his son . After 6 years , the age of that person is four times the age of son that time. What is age of his son after 10 years from now ?
    14 years
    16 years
    18 years
    18 years
    14.5 years
    Option A
    Let the age of his son = x
    age of person = x + 30
    after 6 years ,
    4 (x + 6) = x + 30 + 6
    3x = 12
    x = 4
    age of son after 10 years = 10 + 4 = 14 years

     

  2. The sum of age of A and B is 38 years. After 8 years the age of B is 2 years more than A. What is the age of B before 5 years ?
    13 years
    14 years
    15 years
    20 years
    18 years
    Option C
    Let the age of A = x years
    age of B = (38 – x) years
    after 8 years,
    (38 – x + 8) – (x + 8) = 2
    x = 18
    age of B before 5 years = 38 – x – 5 = 15 years

     

  3. The age of B is 8 years more than A, the age of C is 11 years less than B and the age of A is 5 years less than D. If the sum of age of A , B ,C and D is 70 years, then find the sum of age of A and B after 2 years ?
    40 years
    15 years
    45 years
    38 years
    23 years
    Option D
    Let the age of D = x years
    the age of A = (x – 5) years
    the age of B = ( x – 5 + 8 ) = x + 3 years
    the age of C = (x + 3 – 11) = x – 8 years
    total sum of age of A , B ,C and D = 70
    x + ( x – 5) + (x +3) + (x -8) = 70
    4x – 10 = 70
    x = 20 years
    The age of A = 20 – 5 = 15 years
    The age of B = 20 + 3 = 23 years
    sum = 15 + 23 = 38 years

     

  4. The age of son is one-third of his father. If after 5 years the age of father and son becomes 5 : 2, then find the sum of age of father and son.
    50 years
    60 years
    55 years
    45 years
    46 years
    Option B
    Let the age of father = 3x
    the age of son = x
    after 5 years,
    3x + 5/x + 5 = 5/2
    6x + 10 = 5x + 25
    x = 25
    sum = 3x + x = 4x = 4 * 15 = 60 years

     

  5. The average present age of A , B and C is 30 years and the ratio between the present age of A and C is 4 : 5. If the age of B is 8 years less than the age of C, then what is age of B after 2 years ?
    26 years
    29 years
    23 years
    25 years
    30 years
    Option B
    Let the A and C 4x and 5x respectively
    the age of B = 5x – 8
    total age of A , B and C = 30 * 3 = 90 years
    4x + 5x + 5x – 8 = 90
    14x = 98
    x = 7
    the age of B after 2 years = (5x – 8) + 2 = 29 years

     

  6. The sum of present age of A , B and C is 52 years and the age of A is 3/5th of age of B. If after 11 years the age of B is equal to the three times the present age of C, then find present of C ?
    26 years
    28 years
    30 years
    14 years
    25 years
    Option E
    Let the present age of B = 5x
    the age of A = 3x
    Let the present of C = y years
    5x + 11 = 3y
    y = 5x + 11/3
    3x + 5x + (5x + 11)/3 = 52
    9x + 15 x + 5x + 11 = 156
    29x = 145
    x = 5
    the present age of B = 5 * 5 = 25 years

     

  7. 10 years ago P was half of Q in age . At present the ratio of their ages is 3 : 4. Find the sum of their ages after 3 years.
    46 years
    35 years
    62 years
    41 years
    52 years
    Option D
    10 years ago , let the age of Q = 2x
    and the age of P = x
    at present , the age of P = x + 10
    the age of Q = 2x + 10
    x + 10/2x + 10 = 3/4
    6x + 30 = 4x + 40
    2x = 10
    x = 5
    sum of their ages after 3 years = 2x + 13 + x + 13 = 23 + 18 = 41 years

     

  8. The age of father is 40% more then his son. After 5 years the age of father is 16 years more than the age of son. Find the present age of father.
    45
    56
    42
    58
    56
    Option E
    Let age of son = 5x
    and father age = 5x * 140/100 = 7x
    after 5 years,
    (7x + 5) – (5x + 5) = 16
    2x = 16
    x = 8
    the age of father = 7x = 7 * 8 = 56 years

     

  9. The difference between the present age of A and B is 20 years. After 3 years their ages are in the ratio 9 : 19. Find the present age of B.
    40 years
    35 years
    26 years
    14 years
    46 years
    Option B
    Let present age of A = x years
    present age of B = x + 20 years
    after 3 years, the age of A = x + 3
    the age of B = x + 23
    x + 3 / x + 23 = 9/19
    19x + 57 = 9x + 207
    10x = 150
    x = 15
    the age of B = 15 + 20 = 35 years

     

  10. The present age of father is 5 times that of his son. After 4 years he will be 4 times that of his son. Find the age of father 3 years ago.
    34 years
    56 years
    42 years
    57 years
    48 years
    Option D
    Let the age of son = x years
    the age of father = 5x years
    After 4 years,
    the age of son = x + 4
    the age of father = 5x + 4
    4 (x + 4) = 5x + 4
    4x + 16 = 5x + 4
    x = 12 years
    the age of father 3 years ago = 5 * 12 – 3 = 57 years

     

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