**Directions(1-5):** What will be the values of x and y and chose a correct option.

- I.63x – 94√x +35=0

II. 32y – 52√y + 21=0

y>=xx>yx>=yy>xNo RelationOption E

I.63x – 94√x +35=0

II. 32y – 52√y + 21=0

√x = 7/9 , 5/7

x = 49/ 81 , 25/ 49

√y = 3 /4 , 7 /8

y = 9 /16 , 49 /64

No Relation - I. 2x² + 17x + 35 = 0

II. 3y² + 17y + 24 = 0

x>yy>=xx>=yNo Relationy>xOption E

I. 2x² + 17x + 35 = 0

2x² + 10x+ 7x + 35 = 0

2x (x+ 5) +7 (x+ 5) = 0

(2x+ 7) (x+ 5) =0

x = (-7)/2, -5

II. 3y² + 17y + 24 = 0

3y² + 9y + 8y + 24 = 0

3y (y + 3) + 8 (y+ 3) = 0

(y+ 3) (3y + 8) = 0

y= -3, -8/3

y > x - I.x² – 17x + 72 = 0

II.y² – 27y + 180 = 0

x>yNo Relationx>=yy>xy>=xOption D

I.x² – 17x + 72 = 0

x² – 9x – 8x + 72 = 0

x(x – 9) – 8 (x – 9) = 0

(x – 8) (x – 9) = 0

x = 8, 9

II. y² – 27y + 180 = 0

y² – 12y – 15y + 180 = 0

y(y – 12) – 15 (y – 12) = 0

(y – 15) (y – 12) = 0

y = 15, 12

y > x - I. 2x² – 5x + 3 = 0

II. 3y² – 4y + 1 = 0

y>=xx>yNo Relationx>=yy>xOption D

I.2x² – 5x + 3 = 0

2x² – 2x – 3x + 3 = 0

2x (x – 1) – 3(x – 1) = 0

(x – 1) (2x – 3) = 0

x = 1, 3 /2

II. 3y² – 4y + 1 = 0

3y² – 3y – y + 1 = 0

3y(y – 1) –1 (y – 1) = 0

(3y – 1) (y – 1) = 0

𝑦 = 1/3 , 1

x≥y - I. x² + 2x – 35 = 0

II. y² + 15y + 56 = 0

y>=xx>=yx>yy>xNo RelationOption B

I.x² + 2x – 35 = 0

x² + 7x – 5x – 35 = 0

x (x + 7) – 5 (x + 7) = 0

(x – 5) (x + 7) = 0

x = 5, –7

II. y² + 15y + 56 = 0

y² + 7y + 8y + 56 = 0

y (y + 7) + 6 (y + 7) = 0

(y + 8) (y + 7) = 0

y = – 8, – 7

x ≥ y - I. 2x² + 7x + 5 = 0

II.3y² + 12y + 9 = 0

y>=xx>yy>xx>=yNo RelationOption E

I.2x² + 7x + 5 = 0

2x² + 2x + 5x + 5 = 0

2x (x + 1) + 5 (x + 1) = 0

(2x + 5) (x + 1) = 0

𝑥 = – 5/2 , – 1

II.3y² + 12y + 9 = 0

3y² + 9y + 3y + 9 = 0

3y (y + 3) +3 (y + 3) = 0

(3y + 3) (y + 3) = 0

y = –1, – 3

No relation - I. (x – 12)² = 0

II.y² – 21y + 108 = 0

x>yy>=xx>=yNo Relationy>xOption C

I.(x – 12)² = 0

x – 12 = 0

x = 12

II. y² – 21y + 108 = 0

y² – 12y – 9y + 108 = 0

y (y – 12) – 9 (y – 12) = 0

(y – 9) (y – 12) = 0

y = 9, 12

x ≥ y - I. x² + 72 = 108

II. y³ + 581 = 365

x>=yy>=xx>yy>xNo RelationOption A

I. x² + 72 = 108

x² =108 – 72 = 36

x = ±6

II. y³ + 581 = 365

y³ = –216

y = –6

x ≥ y - I. 8x² + 26x + 15 = 0

II. 4y² + 24y + 35 = 0

y>=xy>xx>yx>=yNo RelationOption D

I. 8x² + 26x + 15 = 0

8x^2 + 20x +6x + 15 = 0

4(2x+5)+3(2x+5) = 0

x = -5/2,-3/4

II. 4y² + 24y + 35 = 0

4y^2 + 10y + 14 y + 35 = 0

y = -5/2,-7/2

x >= y - I. 15x^2 – 46x+35

II. 4y^2 – 15y+14=0

x>yy>=xx>=yy>xNo RelationOption D

x = 7/5, 5/3

Y = 2, 7/4

x < y