 I. 2x^{2} – 15√3x + 84 = 0
II. 3y^{2} – 10√3y + 9 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
 I. x^{2} + √5x – 10 = 0
II. 2y^{2} + 9√5y + 50 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
 I. 2x^{2} – (8+√3)x + 4√3 = 0
II. 3y^{2} – (6+2√3)y + 4√3 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
 I. x^{2} – (2+√5)x + 2√5 = 0
II. 2y^{2} – (6+3√5)y + 9√5 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
 I. 3x^{2} + 5√2x – 24 = 0
II. y^{2} – 6√2y + 16 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
 I. 3x^{2} – 23x + 40 = 0
II. 3y^{2} – 8y + 4 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
 I. 5x^{2} – 17x + 6 = 0
II. 4y^{2} – 16y + 7 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
 I. 3x^{2} – 14x + 8 = 0
II. 3y^{2} – 20y + 12 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
 I. 12x^{2} + 25x + 12 = 0
II. 3y^{2} + 22y + 24 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
 I. 6x^{2} + x – 2 = 0
II. 3y^{2} – 22y + 40 = 0
A) x > y
B) x < y
C) x ≥ y
D) x ≤ y
E) x = y or relation cannot be established
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Ty Maam _____________________/____________________
🙂
sir exam ke point of viwe se ap dusre logo se bahut acha mattarial dete hai thank u sir
agar question hindi me mil jaaye to bahut aur bhi 4 star lag jayege…….
Sorry. Hindi me abi to available nhi ho paega
5th ques me ans e ni hoga??
3√2……. 4√2/3…… 2√2….. 4√2
3√2 2 or 4 k mid me ayega na.. scaling me
Shubra mam first five Kaise karne hai. First tyme dekhe aise ques
read the explanation
tell me in which step u get doubt, i ll explain
Ye squre root karne Kaise hai ques main
Solution me explain kiya h. Vo dekho ek bar
Provide a complete ebook on this topic