- A, B and C alone can do a work in 8 days , 12 days and 6 days respectively. Find how many days they take together to complete work ?
6 days8 days2 2/3 days4 days3 daysOption C

LCM of 8 , 12 and 6 = 24

total work = 24

efficiency of A = 24/8 = 3

efficiency of B = 24/12 = 2

efficiency of C = 24/6 = 4

time taken = 24/9 = 2 2/3 days - P and Q alone can do a work in 30 days and 20 days respectively. P works for 15 days and left the work, remaining work done by B. Find how many days required to complete the remaining work ?
10 days8 days20 days18 days16 daysOption A

LCM of 30 and 20 = 60

total work = 60

efficiency of P = 60/30 = 2

efficiency of Q = 60/20 = 3

P completed work in 15 days = 15 * 2 = 30

time taken by Q to complete remaining work = 60 – 30 /3 = 10 days - A can complete 40% of work in 8 hours and while B alone can do the same work in 24 hours. Find the time taken by A and B together to complete the 60% of the work ?
5 2/3 days8 3/5 days4 days6 6/11 days8 daysOption D

A alone can do all work = 8/40 * 100 = 20 days

LCM of 20 and 24 = 120

efficiency of A = 120/20 = 6

efficiency of B = 120/24 = 5

time taken by A and B together to complete 60% of the work = 120/11 * 60/100 = 6 6/11 days - A and B alone can do a piece of work in 12 hours and 15 hours respectively. If they do the work alternatively for 1 hours each starting with A, then find how many hours will the work be completed ?
5 hours3 hours8 1/5 hours12 1/4 hours13 1/4 hoursOption E

LCM of 12 and 15 = 60

total work = 60

efficiency of A = 60/12 = 5

efficiency of B = 60/15 = 4

work completed in 2 hours = 5 + 4 = 9 works

(2 * 6) hours = (9 * 6) work

12 hours = 54 works

A works in another hours = 5 work

remaining 1 work completed by B = 14 hours

total time = 12 + 1 + 1/4 = 13 1/4 hours - A, B and C alone can do a piece of work in 3 days. If A alone can do in 6 days and C alone can do it in 18 days, how long will B alone take to complete the work ?
8 days9 days18 days6 days4 daysOption B

LCM of 3, 6 and 18 = 18

total work = 18

efficiency of A, B and C = 18/3 = 6

efficiency of A = 18/6 = 3

efficiency of C = 18/18 = 1

efficiency of B = 6 – ( 3 + 1 ) = 2

B alone can do the work = 18/2 = 9 days - P and Q undertook to do a piece of work for rs.3500. P alone can do it in 12 days and Q alone in 20 days. If they finished the work with the help of R in 6 days. What is share of R ?
800700850650725Option B

LCM of 12, 20 and 6 = 60

efficiency of P = 60/12 = 5

efficiency of Q = 60/20 = 3

efficiency of P, Q and R = 60/6 = 10

efficiency of R = 10 – ( 5 + 3 ) = 2

share of R = 3500 * 2 / 10 = 700 - Rita and Gita can do a piece of work individually in 40 days and 60 days respectively. If they work on alternate days starting with Gita, then in how many days will the work get finished ?
28 days24 days17 days48 days46 daysOption D

LCM of 40 and 60 = 120

efficiency of Rita = 120/40 = 3

efficiency of Gita = 120/60 = 2

starting with Gita work completed in 2 days = 5

time required to complete total work = 24 * 2 = 48 days - A and B can do a work in 12 days. B and C can do the same work in 20 days. A and C can also do the same work in 30 days. If they all work together in how many days will they complete the work ?
10 days14 days12 days13 days15 daysOption C

LCM of 12, 20 and 30 = 120

efficiency of A and B = 120/12 = 10

efficiency of B and C = 120/20 = 6

efficiency of A and C = 120/30 = 4

A + B + B + C + A + C = 10 + 6 + 4 = 20

2(A + B + C) = 20

A + B + C = 10

time 120/10 = 12 days - 8 men or 12 women can finish a work in 25 days. How many days will 6 men ad 11 women can finish the same work ?
15 days14 days28 days30 days32 daysOption A

8 men = 12 women

men/women = 12/8 = 3/2

total work = 8 * 3 * 25 = 600

time required = 600 /(6 * 3 + 11 * 2) = 600/40 = 15 days - A, B and C can complete a job in 9 days, 10 days and 15 days respectively. A, B and C start the work together and after 2 days B and C leave the work. Find how many days taken by A to complete the remaining work ?
6 days18 days14 days4 days8 daysOption D

LCM of 9, 10 and 15 = 90

efficiency of A = 90/9 = 10

efficiency of B = 90/10 = 9

efficiency of C = 90/15 = 6

A, B and C complete work in 2 days = 2(10 + 9 + 6) = 50

remaining work = 90 – 50 = 40

time taken by A to complete remaining work = 40/10 = 4 days

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Would you advise starting with a free platform like

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Cheers!

228784 901575You can surely see your enthusiasm in the work you write. The world hopes for more passionate writers like you who arent afraid to say how they believe. Always go following your heart. 260992

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Youve got an awful lot of text for only having one or

2 images. Maybe you could space it out better?