Quantitative Aptitude: Time, Speed and Distance Set 15

Quantitative Aptitude Questions for IBPS RRB/PO/Clerk, SBI PO, NIACL, NICL, RBI Grade B/Assistant, BOI, Bank of Baroda and other competitive exams

1. Two trains starting at the same time from 2 stations 250 km apart and going in opposite direction cross each other at a distance of 130 km from one of the stations. What is the ratio of their speeds?
   13:12
   12:13
   7:9
   9:7
   None
   Option A
   Solution:
   For the same time speed and distance is inversely proportional.
   So ratio of their speed = 130:120 = 13:12.
   
2. Two buses start from a bus terminal with a speed of 20 km/h at interval of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at interval of 8 minutes?
   8km/hr
   6km/hr
   5km/hr
   4km/hr
   None
   Option C
   Solution:
   Let Speed of the man is x km/hr.
   Distance covered in 10 minutes at 20 km/hr = distance covered in 8 minutes at (20+x) km/hr.
   20*10/60 = 8/60(20+x)
   200 = 160+8x
   8x = 40
   x = 5km/hr.
   
3. P and Q start simultaneously from a place A towards B 60 km apart. P’s speed is 5km/h less than that of Q. Q, after reaching B, turns back and meets P at a places 20 km away from B. Q’s speed is:
   8km/hr
   12km/hr
   6km/hr
   10km/hr
   None
   Option D
   Solution:
   Let the speed of P be x km/hr
   then Q’s speed = (x+5) km/hr
   Distance covered by Ajay = 60 + 20 = 80 km
   Distance covered by Ravi = 60 – 20 = 40 km.
   According to question,
   80/(x+5) = 40/x
   x = 5 km/hr.
   then Q’s speed=5+5=10km/hr.
   
4. A man starts climbing a 25 m high wall at 7 am. In each minute he climbs up 1 m but slips down 50 cm. At what time will he climb the wall?
   8.12am
   7.49am
   7.50am
   8.19am
   None
   Option B
   Solution:
   In 1minutes 1m climb and 50 cm slip down . then in 1min he climb 50cm only.
   50cm 1min
   2500cm(25m) ? ===> 50min.
   In last 1min after climb the wall no slip is there so 50-1=49min.
   At 7.49am he climb the wall.
   
5. The ratio between the speed of a train and a car is 16 : 15 respectively. Also, a bus covered a distance of 480 km in 8 hr. The speed of the bus is three-fourth the speed of the train. How much distance will the car cover in 6 hr?
   300km
   290km
   360km
   450km
   None
   Option D
   Solution:
   Speed of bus = 480/8 = 60km/ h
   Speed of train = (60*4)/3=80 km / h
   Speed of train : Speed of car = 16 : 1
   Speed of car =80/16 * 15 = 75 km/ h
   Distance covered by car in 6 hr = 75 × 6 = 450 km
   
6. A train takes 6 seconds to pass an electric pole. If the length of the train is 180 metres, the time taken by it to cross a railway platform 150 metres long is
   11sec
   12.5sec
   10sec
   11.5sec
   None
   Option A
   Solution:
   Speed of the train = 180/6 = 30 m/s
   Time taken by the train to pass the platform
   =(180+150)/30=11 seconds.
   
7. In eleven hours C walks 12.5 km less than what D does in twelve hrs; and in five hrs D walks 3.25 km less than what C does in seven hrs. How many km does each walk per hour ?
   4 and 4.5
   3.25 and 4
   3.5 and 4.25
   4.5 and 3.5
   None
   Option C
   Solution:
   Let the speed of C be x km/hr and D be y km/hr.
   Then 12y-11x=12.5—–1
   And 7x-5y=3.25——2
   By solving 1 and 2
   We get x=3.5km/hr and y=4.25km/hr.
   
8. Two trains are running at 60 km/hr and 30 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 9 seconds. What is the length of the fast train?
   75m
   80m
   88m
   92m
   None
   Option A
   Solution:
   Relative speed = (60 – 30) km/hr =30*5/18=25/3m/sec
   Length of Train= Speed * Time
   =25/3*9=75m.
   
9. Two, trains, one from A to B and the other from B to A, start simultaneously. After they meet, the trains reach their destinations after 16 hours and 25 hours respectively. The ratio of their speeds is:
   4:5
   5:4
   3:7
   7:3
   None
   Option B
   Solution:
   Let the trains be A and B.
   Then, (A’s speed) : (B’s speed) = √b : √a = √25 : √16 = 5 : 4.
   
10. A man can row 15 km/h in still water and he finds that it takes him twice as much time to row up than as to row down the same distance in the river. The speed of current (in km/h) :
    7km/hr
    6km/hr
    8km/hr
    5km/hr
    None
    Option D
    Solution:
    Let the speed of the current be x km/h. Now, according to the question,
    (15+x)/(15-x) = 2/1.
    15+x = 30-2x
    3x = 30-15
    3x = 15
    x = 5 km/hr.