Quantitative Aptitude: Time, Speed and Distance Set 23

1. A train running at the speed of 90 kmph passes a pole in 10 sec, in how much time the train can cross 350m long another train B, which running opposite direction with the speed of 180 kmph.
   10 sec
   8 sec
   12 sec
   15 sec
   20 sec
   Option B
   length of the train=90*5/18*10=250 m
   speed of train=90*5/18=25 m/sec
   speed of another train=180*5/18=50 m/sec
   required time=250+350/25+50=6000/75=8 sec

    

2. A bus can cover a certain distance in 5 hours and when same bus starts running with 20% less speed then it can cover 300 km in 5 hours. Find the distance of the journey.
   375
   400
   425
   500
   575
   Option A
   let the distance of the journey=D km
   original speed of the bus=5x
   decreased speed of the bus=4x
   4x=300/5
   x=15
   distance=15*5*5=375 km
   

    

3. A train running at the speed of 72 kmph cross pole in 18 sec. If same train cross a ‘x’ meters long platform in 30 sec, then find value of ‘x’ ?
   300
   360
   420
   240
   180
   Option D
   speed of train=72*5/18=20 m/sec
   length of train=72*5/18*18=360 m
   ATQ, (360+x)/20=30
   x=600-360=240 m
   length of platform=240 km

    

4. Train P having length of 200m crosses a platform twice of its length in 30 sec. Another train Q having speed of 180 kmph crosses a pole in 10 sec. Find time taken by both trains to cross each other when running in opposite direction.
   12 sec
   10 sec
   18 sec
   22 sec
   25 sec
   Option B
   speed of train P=200+400/30=600/30=20 m/sec
   length of train Q=180*5/18=50 m/sec
   required time=(500+200)/20+50=10 sec

    

5. Distance between A and B is 880 km and speed of car is 20% more than speed of a bike. If car starts from A towards B and at the same time bike starts from B towards A and they meet after 4 hours, then find total distance travelled by car.
   400
   480
   540
   600
   360
   Option B
   let speed of bike=5x
   speed of car=6x
   ATQ, 880/6x+5x=4
   880/11x=20 sec
   880/11x=4
   x=20 km
   speed of car=6*20=120 kmph
   distance travelled by car=120*4=480 km

    

6. ‘L’ meters of long train cross a 480 m long tunnel in 40 sec running at the speed of 108 kmph. If train cross a man running in opposite direction in 8 sec, find speed of man (in km/hour).
   108
   210
   110
   280
   300
   Option A
   speed of train=108*5/18=30 sec
   ATQ, L+480/40=30 sec
   L=1200-480=720
   let, the speed of man=’x’ sec
   720/30+x=12
   x=30m/sec
   sped of main =30*18/5=108 km/hr

    

7. A train can cross a tunnel of length 360m in 15sec, while a pole in 3 sec. In what time the train can cross a platform of length of 210 m.
   10 sec
   8 sec
   12 sec
   16 sec
   20 sec
   Option A
   let length of train be x meters
   (x+360)/15=x/3
   15x=3x+1080
   x=90 meters
   speed of train=90+360/15=450/15=30 m/sec
   required time=90+210/30=10 sec

    

8. Ritu goes to office at a speed of 7 kmph and returns to the home at a speed of 4 kmph. If he takes 5 hours 30 minutes in all, what is the distance between the office and his home ?
   24
   15
   18
   20
   14
   Option E
   let distance between office and Ritu’s home=D km
   D/7+D/4=11/2
   11D/28=11/2
   D=14 km

    

9. A train running at 11/15 of his own speed reached a place in 60 hours. How much time could be saved if the train would run at its own speed ?
   18
   16
   26
   18
   20
   Option B
   let the original speed of train=15x
   current speed of train=11x
   original time required=60*11x/15x=44
   time saved=60-44=16 hours

    

10. In covering a certain distance, the speed of A and B are in the ratio of 3:4. A takes 6 hours more than B to reach the destination. What is the time taken by A to reach the destination ?
    20
    32
    30
    24
    36
    Option D
    speed of A and B =3:4
    time ratio of A and B =4:3
    let time taken by A=4x
    time taken by=3x
    4x-3x=6
    x=6
    time take by A to reach the destination=4*6=24 hours

     

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