Mock Test SBI PO prelims 2017 free. Quant Section Mock

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We are providing you with Quant Section Mock for the upcoming SBI PO 2017 Prelim Exam. It contains 35 questions and time limit is 24 minutes.

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Question 1 of 35

1. Question
1 points
Directions (1 – 5): What approximate value should come in place of the question mark (?) in the following questions?

19.02 × 7.99 + 12.06% of 549.98 = 14.11 × 18.01 – √x
- 1067
- 1028
- 1266
- 1156
- 1138
Correct

Incorrect

Unattempted
Question 2 of 35

2. Question
1 points
Directions (1 – 5): What approximate value should come in place of the question mark (?) in the following questions?

27.03 × 523.93 ÷ 4 + 39.11 – 23.11 = ?
- 3444
- 3288
- 3553
- 3491
- 3388
Correct

Incorrect

Unattempted
Question 3 of 35

3. Question
1 points
Directions (1 – 5): What approximate value should come in place of the question mark (?) in the following questions?

2256.123 – 1864.986 + 567.09 – 258.89 = ?
- 655
- 723
- 700
- 681
- 709
Correct

Incorrect

Unattempted
Question 4 of 35

4. Question
1 points
Directions (1 – 5): What approximate value should come in place of the question mark (?) in the following questions?

16.06% of 250.05 + 24.99 * 15.09 = 45.05% of 1000 – √?
- 1296
- 1625
- 1156
- 1369
- 1225
Correct

Incorrect

Unattempted
Question 5 of 35

5. Question
1 points
Directions (1 – 5): What approximate value should come in place of the question mark (?) in the following questions?

25.09 × 7.01 + 23.92% of 249.93 – √492 = ?
- 198
- 213
- 202
- 234
- 182
Correct

Incorrect

Unattempted
Question 6 of 35

6. Question
1 points
There are 4 red, 3 black and 5 green balls in a box. 3 balls are chosen at random. What is the probability that at least 2 balls are green in color?
- 6/11
- 9/22
- 4/11
- 13/22
- 5/11
Correct

Case 1 : 2 green and 1 non-green
So probability = ⁵C₂* ⁷C₁/¹²C₃
Case 1 : all 3 green
So probability = ⁵C₃/¹²C₃
Add the two cases

Incorrect

Case 1 : 2 green and 1 non-green
So probability = ⁵C₂* ⁷C₁/¹²C₃
Case 1 : all 3 green
So probability = ⁵C₃/¹²C₃
Add the two cases

Unattempted

Case 1 : 2 green and 1 non-green
So probability = ⁵C₂* ⁷C₁/¹²C₃
Case 1 : all 3 green
So probability = ⁵C₃/¹²C₃
Add the two cases
Question 7 of 35

7. Question
1 points
Ratio of age of A 3 years hence and B 7 years ago is 4 : 3. The average of ages of B and C is 27 years. Twice the age of A 6 years ago is equal to the age of C 1 year hence. Find the sum of ages of all three A, B and C.
- 74
- 79
- 72
- 75
- 76
Correct

(A+3)/(B-7) = 4/3
B+C = 54
2(A-6) = C+1
Solve all equations
A = 21, B = 25, C = 29

Incorrect

(A+3)/(B-7) = 4/3
B+C = 54
2(A-6) = C+1
Solve all equations
A = 21, B = 25, C = 29

Unattempted

(A+3)/(B-7) = 4/3
B+C = 54
2(A-6) = C+1
Solve all equations
A = 21, B = 25, C = 29
Question 8 of 35

8. Question
1 points
There are two filling pipes A and B. If A fills bottom 3/4^th tank and B fills the rest tank, then they can fill the tank in 18 minutes. If B fills bottom 3/4^th tank and A fills the rest tank, then they can fill the tank in 22 minutes. What is the time taken by both the pipes to fill the tank together?
- 9 2/5 minutes
- 9 3/5 minutes
- 10 1/4 minutes
- 8 3/7 minutes
- None of these
Correct

Let A can fill complete tank in x minutes, then 3/4 in 3/4 * x minutes
Let B can fill tank in y minutes, so 1/4 in 1/4 * x minutes
So from given information:
3x/4 + y/4 = 18
and x/4 + 3y/4 = 22
Solve both the equations, x = 16, y = 24
So together they complete 1/16 + 1/24 = 5/48 tank in 1 minute or whole tank in 48/5 minutes

Incorrect

Let A can fill complete tank in x minutes, then 3/4 in 3/4 * x minutes
Let B can fill tank in y minutes, so 1/4 in 1/4 * x minutes
So from given information:
3x/4 + y/4 = 18
and x/4 + 3y/4 = 22
Solve both the equations, x = 16, y = 24
So together they complete 1/16 + 1/24 = 5/48 tank in 1 minute or whole tank in 48/5 minutes

Unattempted

Let A can fill complete tank in x minutes, then 3/4 in 3/4 * x minutes
Let B can fill tank in y minutes, so 1/4 in 1/4 * x minutes
So from given information:
3x/4 + y/4 = 18
and x/4 + 3y/4 = 22
Solve both the equations, x = 16, y = 24
So together they complete 1/16 + 1/24 = 5/48 tank in 1 minute or whole tank in 48/5 minutes
Question 9 of 35

9. Question
1 points
A boat can cover 24 km against the current of the stream in 4 hours and can cover 32 km along the current in 2 hours. How long will it take to go 5 km in still water?
- 6/13hours
- 2/11 hours
- 4/9 hours
- 5/11 hours
- 3/7 hours
Correct

Upstream speed = 24/4 = 6 km/hr
Upstream speed = 32/2 = 16 km/hr
So speed of boat in still water = 1/2 (6+16) = 11 km/hr
So time taken to travel 5km in still water = 5/11 hours

Incorrect

Upstream speed = 24/4 = 6 km/hr
Upstream speed = 32/2 = 16 km/hr
So speed of boat in still water = 1/2 (6+16) = 11 km/hr
So time taken to travel 5km in still water = 5/11 hours

Unattempted

Upstream speed = 24/4 = 6 km/hr
Upstream speed = 32/2 = 16 km/hr
So speed of boat in still water = 1/2 (6+16) = 11 km/hr
So time taken to travel 5km in still water = 5/11 hours
Question 10 of 35

10. Question
1 points
At simple interest, an amount increases by 60% in 5 years. What will be the compound interest obtained on Rs 25,000 after 2 years at same rate percent per annum?
- Rs 6460
- Rs 6300
- Rs 63600
- Rs 6360
- Rs 64500
Correct

Is x is principal amount, SI = 60% of x
SO 60% of x = x*5*r/100
Solve, r = 12%
So
CI = 25000 [1 + 12/100]² – 25000 = Rs 6360

Incorrect

Is x is principal amount, SI = 60% of x
SO 60% of x = x*5*r/100
Solve, r = 12%
So
CI = 25000 [1 + 12/100]² – 25000 = Rs 6360

Unattempted

Is x is principal amount, SI = 60% of x
SO 60% of x = x*5*r/100
Solve, r = 12%
So
CI = 25000 [1 + 12/100]² – 25000 = Rs 6360
Question 11 of 35

11. Question
1 points
Directions (11-15): Study the following pie-chart and table to answer the questions that follow:
Pie-chart shows the distribution of students from 6 different states who took part in a quiz.

Total number of boys from states B and C together is approximately what per cent of the total number of boys participated in quiz?
- 38%
- 41%
- 34%
- 30%
- 27%
Correct

Total boys from B = 5/8 * 16% of 4500 = 450
Total boys from C = 360
Similarly find the number of boys from all states and add so total number of boys = 2353
So required % = 810/2353 * 100 = 34%

Incorrect

Total boys from B = 5/8 * 16% of 4500 = 450
Total boys from C = 360
Similarly find the number of boys from all states and add so total number of boys = 2353
So required % = 810/2353 * 100 = 34%

Unattempted

Total boys from B = 5/8 * 16% of 4500 = 450
Total boys from C = 360
Similarly find the number of boys from all states and add so total number of boys = 2353
So required % = 810/2353 * 100 = 34%
Question 12 of 35

12. Question
1 points
Directions (11-15): Study the following pie-chart and table to answer the questions that follow:
Pie-chart shows the distribution of students from 6 different states who took part in a quiz.

What is the difference between total number of boys and total number of girls from all states together?
- 206
- 208
- 205
- 203
- 209
Correct

Total boys = 2353
So girls = 4500 – 2353 = 2147
So required difference = 2353 – 2147 = 206

Incorrect

Total boys = 2353
So girls = 4500 – 2353 = 2147
So required difference = 2353 – 2147 = 206

Unattempted

Total boys = 2353
So girls = 4500 – 2353 = 2147
So required difference = 2353 – 2147 = 206
Question 13 of 35

13. Question
1 points
Directions (11-15): Study the following pie-chart and table to answer the questions that follow:
Pie-chart shows the distribution of students from 6 different states who took part in a quiz.

What is the ratio between the total number of boys from states A and D together and the total number of girls from same states together?
- 14 : 15
- 17 : 16
- 18 : 17
- 16 : 15
- 19 : 18
Correct

4/9 * 18 + 3/5 * 15 : 5/9 * 18 + 2/5 * 15
17 : 16

Incorrect

4/9 * 18 + 3/5 * 15 : 5/9 * 18 + 2/5 * 15
17 : 16

Unattempted

4/9 * 18 + 3/5 * 15 : 5/9 * 18 + 2/5 * 15
17 : 16
Question 14 of 35

14. Question
1 points
Directions (11-15): Study the following pie-chart and table to answer the questions that follow:Pie-chart shows the distribution of students from 6 different states who took part in a quiz.

Total number of boys from states A and B together is approximately what percent of the total number of girls from states E and F together?
- 103%
- 125%
- 116%
- 108%
- 119%
Correct

boys from states A and B = 360+450 = 810
girls from states E and F = 320+432 = 752
So required % = 810*100/752= 108%

Incorrect

boys from states A and B = 360+450 = 810
girls from states E and F = 320+432 = 752
So required % = 810*100/752= 108%

Unattempted

boys from states A and B = 360+450 = 810
girls from states E and F = 320+432 = 752
So required % = 810*100/752= 108%
Question 15 of 35

15. Question
1 points
Directions (11-15): Study the following pie-chart and table to answer the questions that follow:
Pie-chart shows the distribution of students from 6 different states who took part in a quiz.

Total number of boys from states C and D is approximately what percent greater than the total number of girls from states B and D?
- 46%
- 42%
- 37%
- 32%
- 53%
Correct

number of boys from states C and D = 360+405 = 765
number of girls from states B and D = 270+270 = 540
So required% = (765-540)/540 * 100 = 42%

Incorrect

number of boys from states C and D = 360+405 = 765
number of girls from states B and D = 270+270 = 540
So required% = (765-540)/540 * 100 = 42%

Unattempted

number of boys from states C and D = 360+405 = 765
number of girls from states B and D = 270+270 = 540
So required% = (765-540)/540 * 100 = 42%
Question 16 of 35

16. Question
1 points
Directions (15-20): In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

I. 20x² – 31x + 12 = 0,
II. 6y² – 7y + 2 = 0
- If x = y or relation cannot be established
- If x < y
- If x > y
- If x ≤ y
- If x ≥ y
Correct

20x² – 31x + 12 = 0
20x² – 16x – 15x + 12 = 0
So x = 3/4, 4/5
6y² – 7y + 2 = 0
6y² – 3y – 4y + 2 = 0
So y = 1/2, 2/3
Put on number line
1/2… 2/3… 3/4… 4/5

Incorrect

20x² – 31x + 12 = 0
20x² – 16x – 15x + 12 = 0
So x = 3/4, 4/5
6y² – 7y + 2 = 0
6y² – 3y – 4y + 2 = 0
So y = 1/2, 2/3
Put on number line
1/2… 2/3… 3/4… 4/5

Unattempted

20x² – 31x + 12 = 0
20x² – 16x – 15x + 12 = 0
So x = 3/4, 4/5
6y² – 7y + 2 = 0
6y² – 3y – 4y + 2 = 0
So y = 1/2, 2/3
Put on number line
1/2… 2/3… 3/4… 4/5
Question 17 of 35

17. Question
1 points
Directions (15-20): In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

I. 6x² – x – 2 = 0,
II. 5y² – 18y + 9 = 0
- If x ≤ y
- If x = y or relation cannot be established
- If x < y
- If x ≥ y
- If x > y
Correct

6x² – x – 2 = 0
6x² + 3x – 4x – 2 = 0
So x = -1/2, 2/3
5y² – 18y + 9 = 0
5y² – 15y – 3y + 9 = 0
So y = 3/5, 3
Put on number line
-1/2 …. 3/5 ….2/3 …. 3

Incorrect

6x² – x – 2 = 0
6x² + 3x – 4x – 2 = 0
So x = -1/2, 2/3
5y² – 18y + 9 = 0
5y² – 15y – 3y + 9 = 0
So y = 3/5, 3
Put on number line
-1/2 …. 3/5 ….2/3 …. 3

Unattempted

6x² – x – 2 = 0
6x² + 3x – 4x – 2 = 0
So x = -1/2, 2/3
5y² – 18y + 9 = 0
5y² – 15y – 3y + 9 = 0
So y = 3/5, 3
Put on number line
-1/2 …. 3/5 ….2/3 …. 3
Question 18 of 35

18. Question
1 points
Directions (15-20): In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

I. 3x² – 10x + 8 = 0,
II. 3y² + 8y – 16 = 0
- If x ≥ y
- If x ≤ y
- If x = y or relation cannot be established
- If x > y
- If x < y
Correct

3x² – 10x + 8 = 0
3x² – 6x – 4x + 8 = 0
So x = 2, 4/3
3y² + 8y – 16 = 0
3y² + 12y – 4y – 16 = 0
So y = -4, 4/3
Put on number line
-4 …. 4/3…. 2

Incorrect

3x² – 10x + 8 = 0
3x² – 6x – 4x + 8 = 0
So x = 2, 4/3
3y² + 8y – 16 = 0
3y² + 12y – 4y – 16 = 0
So y = -4, 4/3
Put on number line
-4 …. 4/3…. 2

Unattempted

3x² – 10x + 8 = 0
3x² – 6x – 4x + 8 = 0
So x = 2, 4/3
3y² + 8y – 16 = 0
3y² + 12y – 4y – 16 = 0
So y = -4, 4/3
Put on number line
-4 …. 4/3…. 2
Question 19 of 35

19. Question
1 points
Directions (15-20): In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

I. 5x² – 7x – 6 = 0,
II. 5y² + 23y + 12 = 0
- If x > y
- If x ≤ y
- If x < y
- If x = y or relation cannot be established
- If x ≥ y
Correct

5x² – 7x – 6 = 0
5x² – 10x + 3x – 6 = 0
So x = -3/5, 2
5y² + 23y + 12 = 0
5y² + 20y + 3y + 12 = 0
So y = -4, -3/5
Put on number line
-4….. -3/5…. 2

Incorrect

5x² – 7x – 6 = 0
5x² – 10x + 3x – 6 = 0
So x = -3/5, 2
5y² + 23y + 12 = 0
5y² + 20y + 3y + 12 = 0
So y = -4, -3/5
Put on number line
-4….. -3/5…. 2

Unattempted

5x² – 7x – 6 = 0
5x² – 10x + 3x – 6 = 0
So x = -3/5, 2
5y² + 23y + 12 = 0
5y² + 20y + 3y + 12 = 0
So y = -4, -3/5
Put on number line
-4….. -3/5…. 2
Question 20 of 35

20. Question
1 points
Directions (15-20): In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y. Then give answer accordingly-

I. 3x² + 16x + 20 = 0
II. 3y² – 14y – 5 = 0
- If x = y or relation cannot be established
- If x < y
- If x ≥ y
- If x ≤ y
- If x > y
Correct

3x² + 16x + 20 = 0
3x² + 6x + 10x + 20 = 0
Gives x = -2, -10/3
3y² – 14y – 5 = 0
3y² – 15y + y – 5 = 0
Gives y = -1/3, 5
Put all values on number line and analyze the relationship
-10/3… -2…. -1/3…. 5

Incorrect

3x² + 16x + 20 = 0
3x² + 6x + 10x + 20 = 0
Gives x = -2, -10/3
3y² – 14y – 5 = 0
3y² – 15y + y – 5 = 0
Gives y = -1/3, 5
Put all values on number line and analyze the relationship
-10/3… -2…. -1/3…. 5

Unattempted

3x² + 16x + 20 = 0
3x² + 6x + 10x + 20 = 0
Gives x = -2, -10/3
3y² – 14y – 5 = 0
3y² – 15y + y – 5 = 0
Gives y = -1/3, 5
Put all values on number line and analyze the relationship
-10/3… -2…. -1/3…. 5
Question 21 of 35

21. Question
1 points
Price of 15 kg of wheat is Rs 450. Price of 20 kg of wheat is equal to price of 11 kg of rice. Price of 30 kg of rice is equal to price of 18 kg of pulses. Price of 16 kg of pulses is equal to price of 25 kg of barley. Find the price of 22 kg of barley.
- Rs 1250
- Rs 1280
- Rs 1420
- Rs 1330
- Rs 1210
Correct

Rs 450 = 15 kg of wheat
20 kg of wheat = 11 kg of rice
30 kg of rice = 18 kg of pulses
16 kg of pulses = 25 kg of barley
22 kg of barley = x
So
x = 450*20*30*16*22/15*11*18*25 = Rs 1280

Incorrect

Rs 450 = 15 kg of wheat
20 kg of wheat = 11 kg of rice
30 kg of rice = 18 kg of pulses
16 kg of pulses = 25 kg of barley
22 kg of barley = x
So
x = 450*20*30*16*22/15*11*18*25 = Rs 1280

Unattempted

Rs 450 = 15 kg of wheat
20 kg of wheat = 11 kg of rice
30 kg of rice = 18 kg of pulses
16 kg of pulses = 25 kg of barley
22 kg of barley = x
So
x = 450*20*30*16*22/15*11*18*25 = Rs 1280
Question 22 of 35

22. Question
1 points
A and B invested Rs 11200 and Rs 12600 respectively in a business. After 5 months A added Rs 1300 and added Rs 400 to their investments. If after a year share of B is Rs 11000, what is the total profit?
- Rs 23,850
- Rs 22,750
- Rs 21,250
- Rs 20,650
- Rs 21,450
Correct

Ratio of shares A : B
11200*5 + 12500*7 : 12600*5 + 13000*7
112*5 + 125*7 : 126*5 + 130*7
112 + 25*7 : 126 + 26*7
16 + 25 : 18 + 26
41 : 44
So
44/85 * x = 11000
So x = Rs 21,250

Incorrect

Ratio of shares A : B
11200*5 + 12500*7 : 12600*5 + 13000*7
112*5 + 125*7 : 126*5 + 130*7
112 + 25*7 : 126 + 26*7
16 + 25 : 18 + 26
41 : 44
So
44/85 * x = 11000
So x = Rs 21,250

Unattempted

Ratio of shares A : B
11200*5 + 12500*7 : 12600*5 + 13000*7
112*5 + 125*7 : 126*5 + 130*7
112 + 25*7 : 126 + 26*7
16 + 25 : 18 + 26
41 : 44
So
44/85 * x = 11000
So x = Rs 21,250
Question 23 of 35

23. Question
1 points
A container contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained in the container initially?
- 21 l
- 24 l
- 18 l
- 23 l
- 19 l
Correct

7x and 5x
Let total mixture = 7x+5x+9 = 12x + 9
Now 9 l drawn and container filled again (with Q) so 9 l added
So
7x/(5x+9) = 7/9
Solve, x = 9/4
So total mixture = 12 * 9/4 + 9 = 36
So A = 7/12 * 36 = 21 l

Incorrect

7x and 5x
Let total mixture = 7x+5x+9 = 12x + 9
Now 9 l drawn and container filled again (with Q) so 9 l added
So
7x/(5x+9) = 7/9
Solve, x = 9/4
So total mixture = 12 * 9/4 + 9 = 36
So A = 7/12 * 36 = 21 l

Unattempted

7x and 5x
Let total mixture = 7x+5x+9 = 12x + 9
Now 9 l drawn and container filled again (with Q) so 9 l added
So
7x/(5x+9) = 7/9
Solve, x = 9/4
So total mixture = 12 * 9/4 + 9 = 36
So A = 7/12 * 36 = 21 l
Question 24 of 35

24. Question
1 points
A man bought an article and sold it at a gain of 10 %. If he had bought it at 5% less and sold it for Rs 16 more, he would have made a profit of 20%. The C.P. of the article was
- Rs 370
- Rs 410
- Rs 380
- Rs 440
- Rs 400
Correct

Let original Cost price is x
Its Selling price = 110/100 * x = 11x/10
New Cost price = 95/100 * x = 19x/20
New Selling price = 120/100 * 19x/20 = 209x/200
[(114x/100) – (11x/10)] = 116

Solve, x = Rs 400

Incorrect

Let original Cost price is x
Its Selling price = 110/100 * x = 11x/10
New Cost price = 95/100 * x = 19x/20
New Selling price = 120/100 * 19x/20 = 209x/200
[(114x/100) – (11x/10)] = 116

Solve, x = Rs 400

Unattempted

Let original Cost price is x
Its Selling price = 110/100 * x = 11x/10
New Cost price = 95/100 * x = 19x/20
New Selling price = 120/100 * 19x/20 = 209x/200
[(114x/100) – (11x/10)] = 116

Solve, x = Rs 400
Question 25 of 35

25. Question
1 points
Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.
- 285 cm^2
- 282 cm^2
- 295 cm^2
- 275 cm^2
- 278 cm^2
Correct

Area of a trapezium = 1/2 * (sum of parallel sides) * (perpendicular distance between them) = 1/2 * (20 + 18) * 15 = 285 cm²

Incorrect

Area of a trapezium = 1/2 * (sum of parallel sides) * (perpendicular distance between them) = 1/2 * (20 + 18) * 15 = 285 cm²

Unattempted

Area of a trapezium = 1/2 * (sum of parallel sides) * (perpendicular distance between them) = 1/2 * (20 + 18) * 15 = 285 cm²
Question 26 of 35

26. Question
1 points
Directions (26-30): Study the following table to answer the questions that follow:

What is the average amount of interest per year which the company had to pay during this period?
- Rs. 35.16 lakhs
- Rs. 36.66 lakhs
- Rs. 36.92 lakhs
- Rs. 32.26 lakhs
- Rs. 34.69 lakhs
Correct

Incorrect

Unattempted
Question 27 of 35

27. Question
1 points
Directions (26-30): Study the following table to answer the questions that follow:

The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?
- 2%
- 1%
- 0.5%
- 2.5%
- 1.5%
Correct

Incorrect

Unattempted
Question 28 of 35

28. Question
1 points
Directions (26-30): Study the following table to answer the questions that follow:

Total expenditure on all these items in 1998 was approximately what percent of the total expenditure in 2002?
- 70%
- 77%
- 68%
- 69%
- 66%
Correct

(288 + 98 + 3.00 + 23.4 + 83)/ (420 + 142 + 3.96 + 49.4 + 98) * 100 = 69%

Incorrect

(288 + 98 + 3.00 + 23.4 + 83)/ (420 + 142 + 3.96 + 49.4 + 98) * 100 = 69%

Unattempted

(288 + 98 + 3.00 + 23.4 + 83)/ (420 + 142 + 3.96 + 49.4 + 98) * 100 = 69%
Question 29 of 35

29. Question
1 points
Directions (26-30): Study the following table to answer the questions that follow:

The total expenditure of the company over these items during the year 2000 is?
- Rs. 538.49 lakhs
- Rs. 578.34 lakhs
- Rs. 541.23 lakhs
- Rs. 548.56 lakhs
- Rs. 544.44 lakhs
Correct

Incorrect

Unattempted
Question 30 of 35

30. Question
1 points
Directions (26-30): Study the following table to answer the questions that follow:

The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately?
- 5 : 8
- 10 : 13
- 9 : 14
- 6 : 11
- 13 : 15
Correct

(83 + 108 + 74 + 88 + 98)/ (98 + 112 + 101 + 133 + 142)

Incorrect

(83 + 108 + 74 + 88 + 98)/ (98 + 112 + 101 + 133 + 142)

Unattempted

(83 + 108 + 74 + 88 + 98)/ (98 + 112 + 101 + 133 + 142)
Question 31 of 35

31. Question
1 points
Directions (31-35): What will come in place of (?) in following series following a certain pattern?

20, 18, 21, 16, 23, 12, ?
- 25
- 27
- 30
- 31
- 33
Correct

-2, +3, -5, +7, -11, +13,

Incorrect

-2, +3, -5, +7, -11, +13,

Unattempted

-2, +3, -5, +7, -11, +13,
Question 32 of 35

32. Question
1 points
Directions (31-35): What will come in place of (?) in following series following a certain pattern?

4, 9, 23, 74, 301, ?
- 1340
- 1280
- 1510
- 1480
- 1620
Correct

4 × 1 + 5 = 9,
9 × 2 + 5 = 23,
23 × 3 + 5 = 74,
74 × 4 + 5 = 301,
301 × 5 + 5 = 1510

Incorrect

4 × 1 + 5 = 9,
9 × 2 + 5 = 23,
23 × 3 + 5 = 74,
74 × 4 + 5 = 301,
301 × 5 + 5 = 1510

Unattempted

4 × 1 + 5 = 9,
9 × 2 + 5 = 23,
23 × 3 + 5 = 74,
74 × 4 + 5 = 301,
301 × 5 + 5 = 1510
Question 33 of 35

33. Question
1 points
Directions (31-35): What will come in place of (?) in following series following a certain pattern?

8, 10, 17, 34, 66, ?
- 98
- 120
- 134
- 118
- None of these
Correct

Incorrect

Unattempted
Question 34 of 35

34. Question
1 points
Directions (31-35): What will come in place of (?) in following series following a certain pattern?

6, 17, 14, 41, 38, ?
- 113
- 102
- 129
- 135
- 109
Correct

×3 – 1, ×1 – 3, ×3 – 1, ×1 – 3, ×3 – 1

Incorrect

×3 – 1, ×1 – 3, ×3 – 1, ×1 – 3, ×3 – 1

Unattempted

×3 – 1, ×1 – 3, ×3 – 1, ×1 – 3, ×3 – 1
Question 35 of 35

35. Question
1 points
Directions (31-35): What will come in place of (?) in following series following a certain pattern?

12, 6, 10, 28, 104, ?
- 334
- 478
- 424
- 386
- 322
Correct

12*0.5 + 0 = 6
6*1.5 + (0+1) = 10
10*2.5 + (1+2) = 28
28*3.5 + (3+3) = 104
104*4.5 + (6+4) = 478

Incorrect

12*0.5 + 0 = 6
6*1.5 + (0+1) = 10
10*2.5 + (1+2) = 28
28*3.5 + (3+3) = 104
104*4.5 + (6+4) = 478

Unattempted

12*0.5 + 0 = 6
6*1.5 + (0+1) = 10
10*2.5 + (1+2) = 28
28*3.5 + (3+3) = 104
104*4.5 + (6+4) = 478

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12 Thoughts to “Quant Sectional Test 4 for SBI PO 2017 Prelim Exam”

Eng M AwesomE

March 27, 2017 at 12:57 pm

17 of 35 questions answered correctly

Your time: 00:24:00
Eng M AwesomE

March 27, 2017 at 1:26 pm

appx k ques m kuch prob h
1. Shubhra
  
  March 27, 2017 at 1:27 pm
  
  Which one ??
Pawan Kandpal

March 28, 2017 at 8:57 am

please check the 9 question’s solution it should b 5/11
1. Shubhra
  
  March 29, 2017 at 1:00 am
  
  Yes yes
•?((¯°·._.• ąʍβɨЌą •._.·°¯))؟•

March 28, 2017 at 1:00 pm

mam 30th question main to ratio ayegi hi nhi 10:13 …uska total 451 and 586 ban rha hai
1. Shubhra
  
  March 29, 2017 at 12:59 am
  
  Ques me approx is asked
  1. •?((¯°·._.• ąʍβɨЌą •._.·°¯))؟•
    
    March 29, 2017 at 1:44 am
    
    ok mam 🙂 thanku
achiever~Dreamer

March 28, 2017 at 9:44 pm

sir/mam i appreciate and grateful to ur work plz provide more and more quiz on DI ..
1. Shubhra
  
  March 29, 2017 at 12:57 am
  
  Yes we ll provide
come evitare l'essere coinvolti in un tradimento online

August 13, 2023 at 6:40 am

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they will take advantage from it I am sure.
conclusiones: ¿vale la pena salir con un soltero con nivel

August 14, 2023 at 7:59 am

Wow, marvelous blog structure! How long have you been blogging for?
you made running a blog look easy. The total glance of your web site is wonderful, let alone the content material!

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12 Thoughts to “Quant Sectional Test 4 for SBI PO 2017 Prelim Exam”