The perimeter of an equilateral triangle is equal to the perimeter of a square whose diagonal is 9√2 cm. Find out the area of the equilateral triangle ?
48√3
60√3
30√3
36√3
20√3
Option D side of square=9√2/√2=9 let the side of equilateral triangle be x cm. 3x=4*9 x=12 area of equilateral triangle= √3/4*12*12=36√3
If ratio of height and radius of a cone is 5:6. Volume of cone is 480π cm^3, then find slant height of cone (in cm) ?
2√61
4√61
8√50
9√68
10√52
Option A let height and radius of cone be 5x and 6x. volume of cone =480π 1/3*π*6x^2*5x=480π x^3=8 x=2 cm height=10cm , radius=12 cm so, slant height of cone =√(r^2+h^2) = √(144+100)=√244=2√61
Circumference of a circle A is 2 times perimeter of a square. Area of the square is 484 cm^2. What is the area of another circle B whose radius is half the radius of the circle A ?
530
640
590
616
none of these
Option D Area of the square =484cm side of square =22cm. perimeter of square =22*4=88cm. ATQ, circumference of a circle A=88*2 =176cm. 2πr =176 r=176*7/44 =28 Radius of circle B= 28/2 =14cm. Area of circle B=22/7*14*14 =616cm^2
If the length of a rectangular field is increased by 20% and the breadth is reduced by 20%, the area of the rectangle will be 288 m^2 . What is the area of the original rectangle ?
400
300
520
220
none of these
Option B Percentage change in area = +20-20-(20*20)/100 =-4% 96%= 288 100%=288/96*100= 300 m^2
Side of a rhombus is 20cm and the ratio of diagonals of a rhombus is 3:4, then find the area of the rhombus .
384
264
544
288
484
Option A Side of rhombus =20cm. Let, two diagonals of a rhombus be 3x and 4x. side =√(3x)^2+(4x)^2 = 9x^2+16x^2 =5x 5x=20 x=4 two diagonals =(4*3*2) and (4*4*2) =24 and 32 Area =1/2*24*32 =384 cm^2.
The side of a square is 20% more than the side of an equilateral triangle whose perimeter is 75m. Find the ratio between perimeter of square to area of triangle.
96:125√3
48:55√3
32:58
96:130√3
32:42
Option A perimeter of triangle=75 side of triangle=75/3=25m side of square=25*120/100=30 m perimeter of square=4*30=120 m area of triangle=√3/4*25*25=625√3/4 m^2 ratio=120:625√3/4=480:625√3=96:125√3
Radius of circular field is 40% more than length of a rectangular field, having the area 80 m^2. If circumference of a circle is 88m, then radius of circular field is what percent more than breadth of rectangular field ?
60
50
120
75
100
Option D let radius of circle =7x and length of rectangular field=10m area of rectangular field=80 m^2 10*breadth=80 breadth=8m required percentage=14-8?8*100=6/8*100=75%
Perimeter of a circle is 88cm. Find volume of a cylindrical vessel whose radius is equal to the radius of circle and height of cylindrical vessel is 20 cm.
15000
12320
14220
16780
20400
Option B Perimeter of circle =88 r=88*7/44=14 cm radius of cylindrical vessel =22/7*14*14*20 = 12320 cm^2
The ratio between length and breadth of a rectangular field is 5:4 . If area of rectangular field is 320 m^2, then find the perimeter of rectangular field.
64
40
100
72
84
Option D Let length of field =5x breadth of field =4x ATQ, 5x*4x =320 20x^2=320 x^2 =320/20 =16 x=4 Perimeter =2(5x+4x) =18x =18*4= 72
The total area of a circle and a square is equal to 1241 cm^2. The diameter of the circle is 28cm. What is the sum of the circumference of the circle and the perimeter of the square ?
132
188
192
288
196
Option B diameter of circle=28cm radius=14cm area of circle=22/7*14*14=616 ATQ,πr^2+a^2=1241 a^2=1241-616=625 a=25 circumference of the circle=2*22/7*14=88 perimeter of square=4a=4*25=100 sum=88+100=188
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Thanks for your fascinating article. One other problem is that mesothelioma cancer is generally a result of the breathing of material from mesothelioma, which is a very toxic material. It really is commonly observed among individuals in the engineering industry who definitely have long experience of asbestos. It can be caused by living in asbestos protected buildings for long periods of time, Genetics plays a huge role, and some persons are more vulnerable to the risk when compared with others.