Mixed Quantitative Aptitude Questions Set 152

Directions(1-5): What value will come in place of question mark ‘?’ in the following questions.

  1. 36% of 245 − 40% of 210 = 10 − ?
    4.4
    3.2
    6.5
    5.8
    2.9
    Option D
    36% of 245 − 40% of 210 = 10 − ?
    =>? = 10 – 88.2 + 84 = 5.8

     

  2. 3( 1/7 ) + 2( 3/5) + 𝟕( 1/5) – 5(3/7)− 18/35 = 35/?
    3
    7
    2
    5
    4
    Option D
    3( 1/7 ) + 2( 3/5) + 𝟕( 1/5) – 5(3/7)− 18/35 = 35/?
    35/? = 263/35 – 18/35
    => ? = 35×35/245 = 5

     

  3. √1225 ÷ (343)^1/3 × 45% of 760 = ?
    1727
    1820
    1893
    1989
    1710
    Option E
    √1225 ÷ (343)^1/3 × 45% of 760 = ?
    ? = 35 ÷ 7 × 342 = 1710

     

  4. 175% of 460 + 110% of 170 + 2^? = 1000
    7
    2
    1
    5
    3
    Option E
    175% of 460 + 110% of 170 + 2^? = 1000
    =>2^? = 1000 − 805 − 187 = 8
    => ? = 3

     

  5. 18^7.9 × 3^0.1 × 6^0.1 ÷ (3^4 × 6^4) = 18^?
    4
    2
    3
    1
    5
    Option A
    18^7.9 × 3^0.1 × 6^0.1 ÷ (3^4 × 6^4) = 18^?
    =>18^? = 18^7.9 × 18^0.1 ÷ 18^4
    => ? = 4

     

  6. Cost price of article A is double then that of article B and shopkeeper mark up both the article 20% more than the cost price. If at the time of sale shopkeeper gave Rs. 9 discount and earn 17% profit on total. Find the cost price of article A?
    263
    368
    289
    345
    200
    Option E
    Let C.P. of A = 2x
    C.P. of B = x
    Total cost price = 3x
    Mark up price = 3x × 12/10 = 3.6x
    ATQ, 3.6x – 9 = 3x × 1.17
    ⇒ 3.6x – 3.51x = 9
    ⇒ 0.09x = 9
    ⇒ x = 100
    C.P. of article A = 200

     

  7. Ravi invested Rs 18000 in scheme ‘A’ which offers 15% p.a. at simple interest and Rs 15000 in scheme ‘B’ which offers 18% p.a at compound interest. Find the difference between the interest earn from these two schemes after two years?
    400
    440
    450
    452
    486
    Option E
    Interest earn from scheme ‘A’ = 18000 × 15 × 2/100 = 5400
    Interest earn from Scheme ‘B’ = 15000 [(1 + 18/100)^2 − 1] = 15000 [ 3924/10000] = 5886
    Required difference = 5886 – 5400 = 486

     

  8. A tank can be filled with water by two pipes A and B together in 36 minutes. If the pipe B was closed after 30 minutes, the tank is filled in 40 minutes. The pipe B can alone fill the tank in?
    50
    70
    60
    80
    90
    Option E
    In 30 min the part of the tank will be filled by both tap = 30/36 = 5/6
    Required tap = 1 – 5/6 = 1/6
    1/ 6 part of the tank will be filled by tank A in 10 min.
    ∴ tap A will take 60 min.
    ∴ tap B will take time to fill the tank = 1/36 – 1/60 = 1/90
    Required time = 90 min.

     

  9. 40 men, working 8 hours a day can do a piece of work in 15 days. Find the number of days in which second group of 60 men working 4 hrs a day can do twice the work. Assume that 3 men of the first group do as much work in 2 hour as 4 men of the second group do in 3 hrs.
    70
    60
    80
    50
    100
    Option C
    Let efficiency of men of first group is M1 and second group is M2
    3M1 × 2 = 4M2 × 3
    M1 = 2M2
    work = 40M1 × 8 × 15
    According to question,
    40M1 × 8 × 15 × 2 = 60M2 × 4 × d
    d = 80 days

     

  10. An alloy of copper and aluminum has 40% copper. Another alloy of Copper and Zinc has Copper and Zinc in the ratio 2: 7. These two alloys are mixed in ratio 5:3. Quantity of aluminum is what percent more/less than the quantity of copper in final alloy.
    14.4%
    13.8%
    12.5%
    11.6%
    10.9%
    Option C
    Let quantity → 5x and 3x
    Quantity of copper in final alloy = 2/5 × 5x + 2/9 × 3x = 8x/3
    Quantity of Aluminium = 3/5 × 5x = 3x
    Required percentage = [3x – 8x/3]/ 8x/3 × 100 = 12.5%

     


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