Quantitative Aptitude: Data Interpretation Set 12

Direction (1-5): Refer to the table and answer the following questions.
The table shows the performance of 6 batsmen.

Name of Batsman Number of matches played by batsman in the tournament Average run scored by batsman in the tournament Total balls faced in the tournament Strike Rate
Virat 20 160
Rohit 16 55
Rahane 60 400 120
Dhoni 80
Shikhar 10 70 800
Pujara 70

(i) Strike Rate= (Total Runs Scored/Total balls faced)*100
(ii) All the batsman could bat in all the matches played
(iii) You have to calculate the missing value and give the answer accordingly.

 

  1. If the respective ratio between the balls faced by Dhoni and Pujara is 4:5, then by what percent did Pujara score more than Dhoni?
    A) 5.27%
    B) 9.67%
    C) 8.57%
    D) 9.37%
    E) Cannot be determined
    View Answer
      Option D
    Explanation
    :
    Strike rate = (Run/Ball)*100=> Run= (S.R * Ball)/100
    Let ball Dhoni:Pujara =4x:5x
    Run by Dhoni(D)=80*4x/100=32x/10
    Run by Pujara=70*5x/100=35x/10
    Required %=(35x-32x)/32x *100=9.375%
  2. If the runs scored by Shikhar in the last 3 matches of the tournament are not considered, his average decreases by 15. If the runs scored by Shikhar in 8th and 9th match are below 100 and no two scores among these 3 scores are equal , what is the minimum possible run scored by Shikhar in the 10th match?
    A) 115
    B) 116
    C) 117
    D) 118
    E) Cannot be determined
    View Answer
      Option D
    Explanation
    :
    Total runs scored by Shikhar in 10 matches = 10*70= 700
    Runs scored in 1st seven matches =7*(70-15)=385 (as avg reduces by 15)
    Runs scored in last 3 matches=700-385=315(8th , 9th and 10th match)
    Minimum run in 10th match means maximum runs in 8th and 9th match.
    But run in 8th and 9th matches are below 100, => one is 99 other is 98 (as no run is equal)
    Hence run in 10th match=315-(99+98)=118
  3. Total balls faced by Virat is 600 less than the total runs made by him. What is the average of Virat in the tournament?
    A) 70
    B) 75
    C) 80
    D) 85
    E) Cannot be determined
    View Answer
      Option C
    Explanation
    :
    Let average=x =>Total run=20x
    Balls=20x -600
    =>(20x/(20x-600))*100=160 [Strike Rate]
    Solve x=80
  4. Rohit faces equal number of balls in first 8 matches he played in the tournament and the last 8 matches he played in the tournament. If his strike rate in first 8 and last 8 matches of the tournament are 80 and 96 respectively, What is the total number of balls faced by him in the tournament?
    A) 500
    B) 400
    C) 1000
    D) 800
    E) 1200
    View Answer
      Option C
    Explanation
    :
     Let he played x balls in 1st 8 matches and x balls in last 8 matches.
    S.R = Run/Ball *100 => Run=(S.R * Ball*100)
    For 1st 8 matches => Run= 80x/100
    For last 8 matches=> Run = 96x/100
    Total run=16*55=880
    => 80x/100 + 96x/100 =880
    x=500
    Total balls =2x=1000
  5. What is the number of match played by Rahane in the tournament?
    A) 10
    B) 12
    C) 8
    D) 6
    E) 9
    View Answer
      Option C
    Explanation
    :
    60x/400 *100 =120
    x=8

 

Direction (6-10): A test cricket match is played between Team X and Team Y. Both teams have only 5 players. The following bar graph shows the runs scored by different players of both the teams in the two innings of the test match.

  1. What is the margin in team Y′s win?
    A) 105
    B) 107
    C) 110
    D) 112
    E) 114
    View Answer
      Option C
    Explanation
    :

      Inning 1 Inning 2 Total
    Player 1 25 50 75
    Player 2 35 2 37
    Player 3 70 80 150
    Player 4 25 70 95
    Player 5 2 6 8
    Total 157 208 365
           
      Inning 1 Inning 2 Total
    Player 1 80 10 90
    Player 2 70 35 105
    Player 3 20 90 110
    Player 4 80 5 85
    Player 5 65 20 85
    Total 315 160 475


    Y-X=110
  2. If the man of the match is given on the basis of highest average run in a match, then who gets the man of the match?
    A) Player 3 of Team Y
    B) Player 2 of Team Y
    C) Player 2 of Team X
    D) Player 3 of Team X
    E) None of these
    View Answer
      Option D
    Explanation
    :
    Player 3 of Team X has the highest total score= 150 hence his average is also highest.
  3. The total runs scored by the highest run scorer of team X is by what percent greater/lower than the total runs scored by the highest run scorer from Team Y?
    A) 15.67%
    B) 36.36%
    C) 26.66%
    D) 18.88%
    E) None of these
    View Answer
      Option B
    Explanation
    :
    Highest run scorer in Team X= Player 3=150
    Highest run scorer in Team Y= Player 3= 110
    required %=(150-110)/110 *100=36.36%
  4. Run rate is calculated as runs scored per over. Team X played 35 and 46 overs in Inning 1 and Inning 2 respectively. Team Y played 65 and 48 overs in Inning 1 and Inning 2 respectively. Which of the following has the highest run rate?
    A) Team X in Inning 1
    B) Team X in Inning 2
    C) Team Y in Inning 1
    D) Team Y in Inning 2
    E) Cannot be Determined
    View Answer
      Option C
    Explanation
    :
    X(1) =157/35=4.48
    X(2)=208/46=4.52
    Y(1)=315/65=4.84
    Y(2)=160/46=3.47
    Hence run rate of team Y in inning 1 is highest =4.84
  5. What is the respective ratio between the total runs scored by Team X and Team Y?
    A) 71:95
    B) 73:95
    C) 71:105
    D) 73:105
    E) None of these
    View Answer
      Option B
    Explanation
    :
    365:475 =73:95

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5 Thoughts to “Quantitative Aptitude: Data Interpretation Set 12”

  1. mst electrifying da phenomenal

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  2. sTrike Like a Puma

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