Quantitative Aptitude: Data Interpretation Set 9

Directions (1 – 5):
A company makes a target of producing 1250 each of its 6 products A, B, C, D, E, and F in a month for selling to its distributors. But after a month it was found that company could manufacture each product more than the target value
The bar graph shows the % increase in the productions of each of the products. The table shows the ratio of defective to non-defective products sold.
Study the bar graph and table to answer the questions that follow.

1. Find the total products D and E which are defective.
   A) 665
   B) 676
   C) 542
   D) 575
   E) 584
   
   View Answer

   Option D
   Solution:
   First find each of the total products
   A’s production is 10% above the target value of 1250.
   So
   A – 110/100 * 1250 = 1375
   B – 116/100 * 1250 = 1450
   C – 108/100 * 1250 = 1350
   D – 112/100 * 1250 = 1400
   E – 110/100 * 1250 = 1375
   F – 118/100 * 1250 = 1475
   Defective D products = 1/7 * 1400 = 200
   Defective E products = 3/11 * 1375 = 375
   So total = 200+375 = 575
2. Find the difference in production of products B and E together (non-defective) and production of products A and F together (defective).
   A) 1615
   B) 1461
   C) 1254
   D) 1358
   E) 1225
   
   View Answer

   Option A
   Solution:
   Non-Defective B products = 4/5 * 1450 = 1160
   Non-Defective E products = 8/11 * 1375 = 1000
   Defective A products = 2/11 * 1375 = 250
   Defective F products = 1/5 * 1475 = 295
   So required ans = (1160+1000) – (250+295) = 1615
3. Products A and B are sold for Rs 100 and Rs 120 respectively. The defective A and B products are returned to the company, how much worth of product are returned to the company?
   A) Rs 62200
   B) Rs 72700
   C) Rs 59800
   D) Rs 63100
   E) Rs 34800
   
   View Answer

   Option C
   Solution:
   Defective A products = 250
   Defective B products = 1/5 * 1450 = 290
   So loss = 250*100 + 290*120 = Rs (25000 + 34800) = Rs 59800
   
4. Production of products C and E costs Rs 50 and Rs 60 respectively. They are sold for Rs 60 and Rs 80 respectively. If the defective products are returned to the company, find the loss% incurred by the company because of these products (considering that defective products are a waste for the company).
   A) 4.57%
   B) 4.67%
   C) 5.93%
   D) 3.35%
   E) 5.28%
   
   View Answer

   Option B
   Solution:
   CP of C products = 1350 * 50 = Rs 67500
   CP of E products = 1375 * 60 = Rs 82500
   So total CP of C and E = 67500 + 82500 = Rs 1,50,000
   Non-Defective C products = 7/9 * 1350 = 1050
   So amount got by selling these Non-Defective C products = 1050*60 = Rs 63000
   Non-Defective E products = 8/11 * 1375 = 1000
   So amount got by selling these Non-Defective E products = 1000*80 = Rs 80000
   So total SP of Non-Defective C and E products = 63000 + 80000 = Rs 1,43000
   Defective C and E products are returned, so that is a loss.
   So Loss % = (150000 – 143000)/150000 * 100 = 4.67%
   
5. All defective products are returned to the company and also the company will have to give a penalty of Rs 5 on defective A, B and D products and Rs 6 on defective C, E and F products. Find the total penalty to be given by the company?
   A) Rs 9460
   B) Rs 9280
   C) Rs 9840
   D) Rs 9520
   E) Rs 9420
   
   View Answer

   Option D
   Solution:
   Defective A products = 250
   Defective B products = 290
   Defective C products = 300
   Defective D products = 200
   Defective E products = 375
   Defective F products = 295
   So penalty = (250+290+200)*5 + (300+375+295)*6 = 3700 + 5820 = Rs 9520

Directions (6 – 10):
Company ABC has 3480 employees in eight departments. The difference between the number of employees in the departments F and E is 472. The ratio of employees in departments F to C is 7:6. Ratio of employees in departments G to D is 4:3, while department H has 88 more employees than department A. Department B has 328 employees. Department D has 40 more employees than department E and Department A has 208 employees more than department G.

6. What is the difference between the number of employees in departments A and F?
   A) 134
   B) 187
   C) 165
   D) 144
   E) 128
   
   View Answer

   Option D
   Solution:
   Let the number of employees in department F and C be 7x and 6x respectively
   Let the number of employees in department E be y.
   Then, number of employees in department D = y + 40
   Department G = 4/3(y + 40)
   Department A = 4/3(y + 40) + 208
   Department H = 4/3(y + 40) + 296
   Department B = 328
   So, 7x + 6x + y + y + 40 + 4(y + 40) + 208 + 296 + 328 = 3480
   13x + 6y = 2448
   7x – y = 472
   Solve the equations we get x = 96 and y = 200
   So number of employees in departments
   A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
   So difference in A and F = 672 – 528 = 144
7. What is the difference between the number of employees in departments A and B together and the number of employees in departments C and E together?
   A) 89
   B) 96
   C) 73
   D) 75
   E) 80
   
   View Answer

   Option E
   Solution:
   A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
   (A + B) – (C + E) = (528 + 328) – (576 + 200) = 80
8. In there are 290 and 278 females in departments C and H respectively, then find the ratio of the number of male employees in these two departments respectively.
   A) 8 : 13
   B) 12 : 17
   C) 11 : 13
   D) 9 : 13
   E) 11 : 15
   
   View Answer

   Option C
   Solution:
   A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
   Employees in C = 576, females = 290, so males = 286
   Employees in H = 616, females = 278, so males = 338
   So ratio = 286 : 338 = 11 : 13
9. If 5% and 15% of employees in departments D and G are on a tour to a different city, how many employees from these two departments have come to office (it is mandatory to be on work on that particular day)?
   A) 500
   B) 534
   C) 564
   D) 487
   E) 465
   
   View Answer

   Option A
   Solution:
   A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
   Employees in D = 240. 95% have come, so 95/100 * 240 = 228
   Employees in G = 320. 85% have come, so 85/100 * 320 = 272
   So those have come to office from these 2 departments = 228 + 272 = 500
   
10. Ratio of males to females in departments C and F is 7 : 5 and 4 : 3 respectively. Find the percent of females in these two departments.
    A) 66%
    B) 42%
    C) 48%
    D) 55%
    E) Cannot be determined
    
    View Answer

    Option B
    Solution:
    A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
    Females in C = 5/12 * 576 = 240
    Females in F = 3/7 * 672 = 288
    So % of females = (240+288)/(576+672) * 100 = 42%