Directions (1 – 5):
A company makes a target of producing 1250 each of its 6 products A, B, C, D, E, and F in a month for selling to its distributors. But after a month it was found that company could manufacture each product more than the target value
The bar graph shows the % increase in the productions of each of the products. The table shows the ratio of defective to non-defective products sold.
Study the bar graph and table to answer the questions that follow.
- Find the total products D and E which are defective.
A) 665
B) 676
C) 542
D) 575
E) 584
View Answer
Option D
Solution:
First find each of the total products
A’s production is 10% above the target value of 1250.
So
A – 110/100 * 1250 = 1375
B – 116/100 * 1250 = 1450
C – 108/100 * 1250 = 1350
D – 112/100 * 1250 = 1400
E – 110/100 * 1250 = 1375
F – 118/100 * 1250 = 1475
Defective D products = 1/7 * 1400 = 200
Defective E products = 3/11 * 1375 = 375
So total = 200+375 = 575
- Find the difference in production of products B and E together (non-defective) and production of products A and F together (defective).
A) 1615
B) 1461
C) 1254
D) 1358
E) 1225
View Answer
Option A
Solution:
Non-Defective B products = 4/5 * 1450 = 1160
Non-Defective E products = 8/11 * 1375 = 1000
Defective A products = 2/11 * 1375 = 250
Defective F products = 1/5 * 1475 = 295
So required ans = (1160+1000) – (250+295) = 1615
- Products A and B are sold for Rs 100 and Rs 120 respectively. The defective A and B products are returned to the company, how much worth of product are returned to the company?
A) Rs 62200
B) Rs 72700
C) Rs 59800
D) Rs 63100
E) Rs 34800
View Answer
Option C
Solution:
Defective A products = 250
Defective B products = 1/5 * 1450 = 290
So loss = 250*100 + 290*120 = Rs (25000 + 34800) = Rs 59800
- Production of products C and E costs Rs 50 and Rs 60 respectively. They are sold for Rs 60 and Rs 80 respectively. If the defective products are returned to the company, find the loss% incurred by the company because of these products (considering that defective products are a waste for the company).
A) 4.57%
B) 4.67%
C) 5.93%
D) 3.35%
E) 5.28%
View Answer
Option B
Solution:
CP of C products = 1350 * 50 = Rs 67500
CP of E products = 1375 * 60 = Rs 82500
So total CP of C and E = 67500 + 82500 = Rs 1,50,000
Non-Defective C products = 7/9 * 1350 = 1050
So amount got by selling these Non-Defective C products = 1050*60 = Rs 63000
Non-Defective E products = 8/11 * 1375 = 1000
So amount got by selling these Non-Defective E products = 1000*80 = Rs 80000
So total SP of Non-Defective C and E products = 63000 + 80000 = Rs 1,43000
Defective C and E products are returned, so that is a loss.
So Loss % = (150000 – 143000)/150000 * 100 = 4.67%
- All defective products are returned to the company and also the company will have to give a penalty of Rs 5 on defective A, B and D products and Rs 6 on defective C, E and F products. Find the total penalty to be given by the company?
A) Rs 9460
B) Rs 9280
C) Rs 9840
D) Rs 9520
E) Rs 9420
View Answer
Option D
Solution:
Defective A products = 250
Defective B products = 290
Defective C products = 300
Defective D products = 200
Defective E products = 375
Defective F products = 295
So penalty = (250+290+200)*5 + (300+375+295)*6 = 3700 + 5820 = Rs 9520
Directions (6 – 10):
Company ABC has 3480 employees in eight departments. The difference between the number of employees in the departments F and E is 472. The ratio of employees in departments F to C is 7:6. Ratio of employees in departments G to D is 4:3, while department H has 88 more employees than department A. Department B has 328 employees. Department D has 40 more employees than department E and Department A has 208 employees more than department G.
- What is the difference between the number of employees in departments A and F?
A) 134
B) 187
C) 165
D) 144
E) 128
View Answer
Option D
Solution:
Let the number of employees in department F and C be 7x and 6x respectively
Let the number of employees in department E be y.
Then, number of employees in department D = y + 40
Department G = 4/3(y + 40)
Department A = 4/3(y + 40) + 208
Department H = 4/3(y + 40) + 296
Department B = 328
So, 7x + 6x + y + y + 40 + 4(y + 40) + 208 + 296 + 328 = 3480
13x + 6y = 2448
7x – y = 472
Solve the equations we get x = 96 and y = 200
So number of employees in departments
A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
So difference in A and F = 672 – 528 = 144
- What is the difference between the number of employees in departments A and B together and the number of employees in departments C and E together?
A) 89
B) 96
C) 73
D) 75
E) 80
View Answer
Option E
Solution:
A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
(A + B) – (C + E) = (528 + 328) – (576 + 200) = 80
- In there are 290 and 278 females in departments C and H respectively, then find the ratio of the number of male employees in these two departments respectively.
A) 8 : 13
B) 12 : 17
C) 11 : 13
D) 9 : 13
E) 11 : 15
View Answer
Option C
Solution:
A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
Employees in C = 576, females = 290, so males = 286
Employees in H = 616, females = 278, so males = 338
So ratio = 286 : 338 = 11 : 13
- If 5% and 15% of employees in departments D and G are on a tour to a different city, how many employees from these two departments have come to office (it is mandatory to be on work on that particular day)?
A) 500
B) 534
C) 564
D) 487
E) 465
View Answer
Option A
Solution:
A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
Employees in D = 240. 95% have come, so 95/100 * 240 = 228
Employees in G = 320. 85% have come, so 85/100 * 320 = 272
So those have come to office from these 2 departments = 228 + 272 = 500
- Ratio of males to females in departments C and F is 7 : 5 and 4 : 3 respectively. Find the percent of females in these two departments.
A) 66%
B) 42%
C) 48%
D) 55%
E) Cannot be determined
View Answer
Option B
Solution:
A – 528, B – 328, C – 576, D – 240, E – 200, F – 672, G – 320, H – 616
Females in C = 5/12 * 576 = 240
Females in F = 3/7 * 672 = 288
So % of females = (240+288)/(576+672) * 100 = 42%
2nd question is awesome… _/_
ty mam 🙂
MAM ISKA BTANA
Department G = 4/3(y + 40)
Department A = 4/3(y + 40) + 208
Department H = 4/3(y + 40) + 296
4(y + 40) + 208 + 296 + 328 = 3480
4/3 – 3 times hai na.
To 4 (y+40) aa gya
TY MAM
@Shubhra_AspirantsZone:disqus mam pls explain this step
7x – y = 472
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