# Quantitative Aptitude: Problems on Ages Set 8

Problem on Ages for SBI PO, IBPS PO/Clerk, IBPS RRB, OICL, NIACL, NICL, LIC, Bank of Baroda and other competitive exams.

1. A person’s present age is two-ninth of the age of his mother. After 10 years, he will be four-eleventh of the age of his mother. How old is the mother after 15 years?
A) 48yrs
B) 60yrs
C) 55yrs
D) 53yrs
E) None
Option B
Solution:

Present ratio P:M ==>2:9
After 10years P:M=4:11
Then
(2x+10)/(9x+10) = 4/11
22x+110=36x+40
X=5.
Then Mother’s present age=9*5=45yrs.
After 15 yrs Mother’s age is=60yrs.
2. Ratio of the ages of A and B is 5 : x. A is 18 years younger to C. After nine years C will be 47 years old. If the difference between the ages of A and B is same as the age of C, what is the value of x?
A) 13
B) 12
C) 14.5
D) 13.25
E) None
Option C
Solution:

Given
A:B=5:x –1
A = C – 18 —2
C + 9 = 47 =>C=47-9=38yrs.
A – B = C —3
From 2 A=38-18=20yrs.
From 1 20/B=5/x==> B=4x
From 3 4x-20=38
X=14.5.
3. 16 years ago, my Uncle was 8 times older than me. After 8 years from today, my uncle will be thrice as old as I will be at that time. Eight years ago, what was the ratio of my age and my uncle’s age?
A) 11:53
B) 13:45
C) 8:29
D) 5:32
E) None
Option A
Solution:

Let 16 yrs ago the age of mine was=x
(x+24)/(8x+24)=1/3
X=48/5=9.6
My present age is 9.6+16=25.6
Present age of my Uncle =8*9.6+16=92.8
Required ratio =(25.6-8)/(92.8-8) =17.6/84.8=11:53.
4. The sum of present ages of A and B is 11 times the difference of their ages. 5 years hence, their total ages will be 13 times the difference of their ages. What is the present age of elder one?
A) 35yrs
B) 20yrs
C) 25yrs
D) 30yrs
E) None
Option D
Solution:

A+B=11(A-B)
A:B=6:5
According to 2nd condition
6x+5x+10=13(6x-5x)=5
A’s age =6*5=30.
5. The average age of a husband-wife and their son was 42 years. The son got married and exactly after 1 year a child was born to them. When the child became 5 years old, the average age of the family became 36 years. What was the age of bride at the time of marriage?
A) 30yrs
B) 27yrs
C) 25yrs
D) 22yrs
E) None
Option C
Solution:

F+M+S=42*3=126
The age of family after 6 years =36*5=180
The age of bride after 6 years=180-(126+18+5)
=180-149==>31yrs
Age of bride at the time of marriage=31-6=25yrs.
6. A says, “If you reverse my own age, the figures represent my Brother’s age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum.” Then A’s brother’s age is ?
A) 45
B) 54
C) 25
D) 52
E) None
Option B
Solution:

From option 54-45=1/11(45+54)
9=9
Condition satisfied.
7. L is as much younger than M as he is older than N. If the sum of the ages of M and N is 60 years, what is definitely the difference between M and L’s age?
A) 3yrs
B) 2yrs
C) 5yrs
D) Can’t be determined
E) None
Option D
Solution:

M – L = L – N
(M + N) = 2L
Given (M + N) = 60
then 2L=60==>L=30
But can’t able to find M value
Therefore, cannot be determined.
8. If three times of the son’s age in years is included to the mother’s age, the total is 75 and if two times of the mother’s age is included to the son’s age, the total is 80. So the son’s age is?
A) 15yrs
B) 18yrs
C) 14yrs
D) 22yrs
E) None
Option C
Solution:

Let daughter’s age = A and mother’s age = B
Given: 3A+B = 75 and A+2B = 80
Solving A, we will get A = 14.
9. The ages of P, Q and R together are 57 years. Sis thrice as old as P and R is 12 years older than P. Then, the difference between ages Q and R is?
A) 11yrs
B) 6yrs
C) 8yrs
D) 4yrs
E) None
Option B
Solution:
Let P’s age = X
R 12 yrs older than P so R’s age = x+12
Q is thrice as old as P so Q’s age = 3x
x + (x+12) + 3x = 57
=> 5x = 45
x = 9
P’s age = 9
Q’s age = 3x = 27
R’s age = x+12 = 21
Q-R=27-21=6yrs.
10. If 10 years are subtracted from the present age of Sharmi and the remainder is divided by 6, then the present age of his grandson Epsi is obtained. If Epsi is 2 years younger to Nove whose age is 7 years, then what is Sharmi’s present age?
A) 40yrs
B) 35yrs
C) 52yrs
D) 55yrs
E) None
Option A
Solution:

Epsi age =7-2=5yrs
Let Sharmi age be x years.
Then (x-10)/6=5
X=40.

## 2 Thoughts to “Quantitative Aptitude: Problems on Ages Set 8”

1. CASIMIRO

TQ MAM

2. Dhmn Hinty

in qus no. 3rd
me : uncle me : uncle

1 : 8 ==> 2 : 16
1 : 3 ==> 7 : 21
differce 5= 24 (16 yr ago+ 8 yr after)
5= 4.5
plz correct me