Quantitative Aptitude: Data Interpretation Questions Set 41

Data Interpretation Questions (DI) for IBPS PO 2017, IBPS PO, NIACL, NICL, SBI PO RBI Grade B, Dena Bank PO PGDBF, BOI, Bank of Baroda and other competitive exams. 

Direction (1-5): Study the following charts and answer the questions that follow:

  1. A and B started doing the work. After 2 days they both left, and C joined the work. He completed his part of work. Now the remaining work was completed by F in 7 days. In how many days can F complete whole work?
    A) 18 days
    B) 16 days
    C) 12 days
    D) 20 days
    E) 10 days
    View Answer
    Option C
    Solution
    :
    A does 20% work in 4 days. so 100% work in 100*4/20 = 20 days
    Similarly B can complete 100% work in 100*3/10 = 30 days
    They worked for 2 days, so did [1/20 + 1/30]*2 = 1/6 work
    Now C completed 25% = 1/4 work
    So now remaining work = 1 – (1/6 + 1/4) = 7/12
    F complete 7/12 work in 7 days, so complete work in 12 days
  2. G who can complete whole work in 30 days replaced A and did A’s part of work. He left and then B also worked for same number of days as G. If remaining work was completed by M who can do complete work in one-fourth the number of days in which E can complete the work, then in how many days was the whole work completed?
    A) 22 days
    B) 14 days
    C) 21 days
    D) 18 days
    E) 12 days
    View Answer
    Option D
    Solution
    :
    A’s part of work = 20% = 1/5
    So G did 1/5 of work,
    Whole work in 30 days, s 1/5 work in 1/5 * 30 = 6 days
    Now B also worked for 6 days.
    B can complete whole work in 30 days, so In 6 days, completed 6/30 = 1/5 of work
    Now remaining work = 1 – (1/5 + 1/5) = 3/5 [After G and B did work]
    Now E can complete whole work in 40 days [100*6/15]
    So M can complete work in 10 days. So completed 3/5 work in 3/5 * 10 = 6 days
    So total number of days = 6+6+6 = 18 days
  3. All people decided to complete work in less number of days. So they divided the work equally among themselves. In how many days will the work be completed this way? (They all worked individually)
    A) 25 4/5 days
    B) 27 4/5 days
    C) 23 5/6 days
    D) 24 3/5 days
    E) None of these
    View Answer
    Option B
    Solution
    :
    5 people equally divided the work so each did 1/5 work now
    So A 1/5 work in 4 days as earlier
    B == 1/10 work in 3 days , so 1/5 work in 6 days
    C == 1/4 work in 6 days , so 1/5 work in 24/5 days
    D == 3/10 work in 7.5 days , so 1/5 work in 5 days
    E == 3/20 work in 6 days , so 1/5 work in 8 days
    So complete work in = 4 + 6 + 24/5 + 5 + 8 = 27.8 days
  4. P is 20% more efficient than B and Q is 60% more efficient than C. They worked together for 5 days and left the work, after which the remaining work was completed by C and E together. Had all worked together, in how many less days they could have completed the work?
    A) 6 3/13 days
    B) 5 days
    C) 4 3/5 days
    D) 7 days
    E) 8 4/11 days
    View Answer
    Option A
    Solution
    :
    P and B::
    P == 120 : 100 = 6 : 5. So days = 5 : 6
    6 = 30, so 1 = 5, so 5 = 25. P can complete work in 25 days
    Q and C::
    Q == 160 : 100 = 8 : 5. So days = 5 : 8
    8 = 24, so 1 = 3, so 5 = 15. Q can complete work in 15 days
    They worked for 5 days. So
    [1/25 + 1/15]*5 = 8/15 work
    Reaming 7/15 by C and E
    So [1/24 + 1/40]*x = 7/15
    x = 7 days
    Total = 5+7 = 12 days
    Now had they did work together::
    [1/25 + 1/15 + 1/24 + 1/40] = 13/75
    So 75/13 days
    So less days = 12 – 75/13 = 81/13 = 6 3/13 days
  5. J can complete the whole work in number of days equal to the average of number of days in which A and B can complete the work. J, C, D, and E all started the work and after 5 days they were replaced by A and B. A and B completed the remaining work in how many days?
    A) 3 1/5 days
    B) 2 2/3 days
    C) 1 2/3 days
    D) 2 3/5 days
    E) 4 2/5 days
    View Answer
    Option A
    Solution
    :
    A in 20 days, B in 30 days. So J in (20+30)/2 = 25 days
    J, C, D, and E started work::
    [1/25 + 1/24 + 1/25 + 1/40]= 11/75. Worked for 5 days so did 11/75 * 5 = 11/15 of work
    Remaining work = 4/15
    [1/20 + 1/130]*x = 4/15
    Solve. x = 48/15 days = 3 1/5 days

Direction (6-10): Study the following information and answer the questions that follow:

A person has total of 140 pens. The number of red pen is eight times the number of green pens. For every blue pen there are three yellow pens. Pens are available only in these four colours and the number of each of them is a positive integer number. Based on the information, answer the questions that follow.

  1. How many different values can the number of Blue pen have?
    A) 1
    B) 2
    C) 3
    D) 4
    E) 5
    View Answer
    Option C
    Solution
    :
    Let number of Green pen= G and Number of Blue Pen = B
    Red= 8 Green ; Hence Red = 8G
    Blue:Yellow= 1:3 => Yellow= 3B
    Also Red + Green + Blue + Yellow=140
    => 8G + G + 3B + B = 140
    => B= (140-9G)/4 ————- (i) [Keep this equation handy]
    Put positive value of G, till B is positive and is not a fraction.
    We have for G=4; B=26 — case 1
    G=8; B=17 – case 2
    G=12; B=8 – case 3
    So only 3 values
  2. What will be the number of Red pens if the sum of number of green pen and blue pen is maximum?
    A) 28
    B) 26
    C) 30
    D) 32
    E) 36
    View Answer
    Option D
    Solution
    :
    We have 3 values of G and B; and the sum is maximum when G=4 and B=26
    G+B=30 in case 1; G+B= 25 in case 2; G+B= 20 in case 3; so maximum in case 1
    R=8G= 8*4=32
  3. If the number of yellow pen lies between 60 and 70, then by what percentage is the number of yellow pen more than number of red pen?
    A) 16%
    B) 15.66%
    C) 16.66%
    D) 18.66%
    E) Condition not possible
    View Answer
    Option E
    Solution
    :
    Number of yellow pen = 3B
    possible value of B= 26, 17, 8
    hence number of yellow pen= 3*26, 3*17, 3*8= 84, 51, 24
    hence a range of 60-70 is not possible
  4. If it is fixed that the number of each colour of pen is a multiple of 4, then what would be the product of number of different colours of pen?
    A) 216788
    B) 216712
    C) 221378
    D) 221184
    E) 231356
    View Answer
    Option D
    Solution
    :
    Each pen can be a multiple of 4 when, G=12 and B=8
    R=8G=96 ; Y= 3*B=24
    Product= 12*96*8*24= 221184
  5. If it is given that the number of Red pen is 96, what will be the number of Blue pen?
    A) 6
    B) 8
    C) 10
    D) 12
    E) 14
    View Answer
    Option B
    Solution
    :
    96= 8G => G= 12
    B= (140-9*12)/4= B=8

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125 Thoughts to “Quantitative Aptitude: Data Interpretation Questions Set 41”

  1. Can you provide the idea on which it was based?

    I mean what info was given in table?

    1. suvajit Chakraborty

      ek line graph tha.. usme 5 inlet taps a,b,c,d,e ka time diya tha to fill the tank. ek table di thi usme 4 outlets ka time diya to empty the tank. v,x,y,z

      1. Thankyou. we will work on these

    2. Jeevan

      Line graph with mising DI (line graph me tank filled in different hour is given and in table tank is empty in different hours are giving with missing values.

      1. Jeevan

        Hmm inequality new pattern thi

      2. Thankyou. we will work on these .

    3. Jeevan

      Ek Di easy tha ratio wala
      And 3rd di caslet wala th
      Usme 4paragraph me info thi and ans find karna tha

    4. suvajit Chakraborty

      Double Pie-chart DI , It was based on Population and Literacy

        1. Ambika

          ohk..all the best :))

        2. $~$PrAdeEP$K$~$~$

          wow…:))) imagination di hehehehhehehe…:)))

          1. Ambika

            🙂
            kisi ne bnake bheji thi mujhe

    5. Jeevan

      Mam reas me
      Month based puzule
      North south wali
      An
      Floor puzule(8 floor, 8 people,8 sallary)
      And
      8 std 8 cities and unke class wali puzule thi

      1. 8 std and unke class means??

        3 parameters – cites, class and ??

        1. Jeevan

          City
          Clas
          And student A B C D like ths
          And pls english me 5 option and usme alag alag pharses use kiye to find karna hai ki kaunsa galat use kiya
          Ye the que eng me
          Ho sake to pls que dijiye mam

          1. Phrases like?

            Errors form or Idioms ??

          2. Jeevan

            4 sentence the idiom and pharses ke sath.
            An find sentence which is not go with meaning of idiom and pharses

          3. class 1 to 8 or different ?
            ya classes same b ho sakti thi students ki ??
            n conditions on classes like A’s class = 3 + B’s,…….like this ??

          4. Jeevan

            8 student
            8 city
            And
            3 5 7 10th ye classes thi unki

          5. Jeevan

            Mam 4 clas thi
            3 5 7 10th
            Same clas nai thi
            4 thi

          6. 2 people in same class?

      1. <>>>>>>>>>>>>>

        sir ,this was the question i remember ,which was asked in rbi grade b….
        plz provide more questions on this,,,

        1. Thankyou. we will work on these and provide

          1. AMAZON

            Please before Nicl cover all these topics.
            and mam and in Reasoning section too , Logical reasoning area always covers a lot of weightage please do focus on that too (cover topics like assumption , inference assumption ,course of action etc)

      2. Jellyfish

        1st ans 13/2=6*1/2
        2nd is 6

        1. <>>>>>>>>>>>>>

          explain 2nd one

          1. Jellyfish

            H/24+H/36=H+4/24
            H=6

          2. Jellyfish

            yaar 3rd me 24 aa raha hai Z a work but option menahi hai

          3. <>>>>>>>>>>>>>

            muje bhi 24 hi aahe thi….shyad option galat hoga..

          4. Jellyfish

            ha but real xam me kaise galat ho skta hai

          5. Ho sakta hai real exam me b wrong

          6. Jellyfish

            no mam they are very intelligent person.

          7. Yes they are absolutely. But aisa hota hai kabi kabi. Sbi po prelims me is bar hua tha. Banking k papers milte nhi to pta nhi chlta.
            But last to last year tak SSC offline hota tha.
            N unme answers hote the wrong

          8. <>>>>>>>>>>>>>

            explain your ans for 3rd one

          9. Jellyfish

            4)
            C-Y=40/3*(D-w)
            40/3*1/24=5/9
            5/9-1/8=39/72=72/39

          10. <>>>>>>>>>>>>>

            explain 4th one plz

  2. Player

    4)
    P and B::
    P == 120 : 100 = 6 : 5. So days = 5 : 6
    6 = 30, so 1 = 5, so 5 = 25. P can complete work in 25 days
    Q and C::
    Q == 160 : 100 = 8 : 5. So days = 5 : 8
    8 = 24, so 1 = 3, so 5 = 15. Q can complete work in 15 days
    They worked for 5 days. So
    [1/25 + 1/15]*5 = 8/15 work
    Reaming 7/15 by C and E
    So [1/24 + 1/40]*x = 7/15
    x = 7 days
    Total = 5+7 = 12 days
    Now had they did work together::
    [1/25 + 1/15 + 1/24 + 1/40] = 13/75
    So 75/13 days
    So less days = 12 – 75/13 = 81/13 = 6 3/13 days

    8 = 24, so 1 = 3, so 5 = 15. Q can complete work in 15 days….,……in this step how we put 8=24….

    1. C can complete whole work in 24 days

      so 8 = 24

      You got that how C can complete whole work in 24 days ?

      1. Player

        ok….mam thanku got it

    2. aayat

      Q………..C
      160………100
      8………….5………..E
      5:8..D
      C DONE IN 24 DAYS SO 8=24……1=3
      Q–3*5=15

      1. Player

        hlo ayat hw are u

        1. aayat

          Am good dear
          What about u ??

          1. Player

            m also :))

  3. Jeevan

    Suppeb DI
    Thanku

  4. _/_

    1 qs unit method se koi batana

  5. Trisha

    can anyone explain this question @Shubhra_AspirantsZone:disqus @surajskt:disqus @disqus_sqmL5JaJJZ:disqus
    Answer is B- 5 cm https://uploads.disquscdn.com/images/994c25b51c5cf4944f3890f7e08052479a2ccddbdaec4e34ecf90aea9040acd6.jpg

    1. 2 (l+b) = 120
      l+ b = 60
      so max area at 29*31

      Now suppose
      3 cm squares are cut
      so height of cuboid = 3 cm
      length = 31 – (3+3) = 25
      breadth = 29 – (3+3) = 23
      so volume = 3 * 25*23 = 1725

      if 10 cm square are cut
      volume = 10 * 11*9 = 990

      Find like this

    2. aspirant

      here maximum area should be 900.(i.e square)
      each side=120/4=30
      now putting values of x=3,5,7,10 cuboid has the max volume for x=5
      vol=(30-5*2)*(30-5*2)*5=2000cm^3
      forx=3,vol=24*24*3=1728
      forx=7,vol=16*16*7=1792
      forx=10,vol=10*10*10=1000
      u know differentiation??

  6. AVI™ (Sinchen loveR)

    Q 4 ans is I think Option B (5 days)
    rest 6 to 10 questions smj nhi aa rhe kese solve krne h bhut possibility bn rhi h How can be fix it mod help me

  7. aayat

    A…….B……..C
    20…..30………24
    ………120………
    6…………4………..5
    A+B=10*2= 20 WORK DONE
    C–120*25%=30
    A+B+C=20+30=50 WORK DONE
    REST=120-50=70
    F–70%=7
    120%=12

      1. aayat

        G30*20%=6
        Same b==6
        E==40
        M=40*1/4=10
        G…….B……..M
        30……..30….10
        ……..30….
        1…………1……..3
        G=6*1=6
        B=6*1=6
        G+B=6+6=12 WORK DONE
        30-12=18
        M==18/3=6
        TOTAL DAYS=6+6+6=18

        1. _/_

          4th last or bta do bn ni rha yaar

          1. aayat

            P………B
            120……..100
            E..6:5
            D..5:6
            B==6===30
            1=5 , P=5*5=25
            Same as==Q=15
            P……..Q
            25……….15
            ……..75
            3…………..5
            P+Q=8*5/75=8/15
            REST=7/15
            C…….E
            24……….40
            ……120
            5…………3
            120/8=15
            15X=7/15
            X=7
            TOTAL DAYS=7+5=12
            P……Q…..C…….E
            25….15….24…….40
            ……………600….
            24……40….25……15
            600/104==75/13
            12-75/13=81/13==6 3/13

          2. _/_

            hmm last me na ho paaya tha got it ty

          3. Ak$hita $inghal

            kaisi h sis?? konsa exam ab?

          4. aayat

            Am good
            Ibps

          5. Player

            P……..Q
            25……….15
            ……..75………………………75 kaise aya
            3…………..5
            P+Q=8*5/75=8/15

          6. aayat

            25 & 15 ka lcm 75
            P& Q 5 DAYS WORK KRTE H TOTAL WORK 75 HUA SO 8*5/75=8/15

          7. Player

            P+Q=8*5/75=8/15 ….ye bhi btao

          8. _/_

            Directions (Q.1-2): A is thrice as good a workman as B and therefore is able to finish a job in 60 days less than B. If A and B complete 2/3 rd of the job and then A is replaced by C, the remaining job is done by B and C in 10 days. If A and B complete 3/4th of the job and then B is replaced by D the remaining job is done by A and D in 5 days.

            Q1. How long will it take for A, B, C and D to complete the job working together?
            (a) 12 days
            (b) 20 days
            (c) 15 days
            (d) 14 days
            (e) None of these

            Q2. The job is completed in the following manner: A and B work on day 1, B and C work on day 2, C and D work on day 3, D and A work on day 4 and so on. How long will it take for the job to be completed in this manner?
            (a) 25 days
            (b) 24 days
            (c) 22 days
            (d) 30 days
            (e) None of these

          9. aayat

            A-3
            B-1
            C-2
            D-1.5
            TOTAL WORK=90
            A+B=4
            B+C=3
            C+D=3.5
            A+D=4.5
            4+3+3.5+4.5=15
            15 WORK DONE IN 4 DAYS
            90/15=6
            6*4=24
            AND 1ST SAME AS MEET

          10. _/_

            c=45 days
            d=60 days
            ??

          11. aayat

            effi samjh me ayi ???

          12. aayat

            A-B=2
            2=60
            1=30
            Total work=3*30=90
            C=90/2=45
            D=90/1.5=60

          13. $~$PrAdeEP$K$~$~$

            2)
            a =30
            b=90
            c =45
            d =60
            lcm =180
            =>a =6,b=2,c=4,d=3
            now
            (a+b)——-(b+c)—–(c+d)——-(d+a)
            8————–6————7———–9
            =>30 work =4 days
            =>180 work =24 days

          14. $~$PrAdeEP$K$~$~$

            ans 1
            eff ratio
            a———b
            3———1
            =>time ratio
            1———-3
            => 2ratio =60
            =>1 ratio =a=30 days
            =>3 ratio =b=90 days
            now b+c =1/30 =>c=45 days
            ||rly a+d =1/20 => d=60 days
            now lcm =180
            =>a =6,b=2,c=4,d =3
            =>15(a+b+c+d) =180 =>a+b+c+d =12 days

          15. _/_

            Directions (Q.3-4): Cities M and N are 600 km apart. Bus A starts from city M towards N at 9 am and bus B starts from city N towards M at the same time. Bus A travels the first 1/3rd of the distance at a speed of 40 kmph, the second 1/3rd at 60 kmph and the third 1/3rd at 50 km/hr. Bus B travels the first 1/3rd of the total distance at a speed of 60 kmph, the second 1/3 rd at 40 kmph and the third 1/3rd at 50 km/hr.

            Q3. When and where will the two buses cross each other?
            (a) 6 hrs, 320 kms from N
            (b) 5 hrs 20 minutes, 240 kms from N
            (c) 6 hrs 20 minutes, 280 kms from M
            (d) 4 hrs, 240 kms from M
            (e) None of these

            Q4. What are the approximately average speeds of Bus A and Bus B?
            (a) 48.64 km/hr , 48.64 km/hr
            (b) 50 kmph, 48.64 km/hr
            (c) 40 kmph, 50 kmph
            (d) 48.64 km/hr, 50 km,hr
            (e) None of these

          16. $~$PrAdeEP$K$~$~$

            time taken by a for 1/3 distance =>
            t(1/3) =200/40 =5hrs
            similarly for b
            t(1/3) =200/60 =10/3 hrs
            since frm abov v can say tht b is consuming less tym than a
            so v hav to make time equal
            =>time diff =5 -10/3 =5/3hr
            now distance tavelled by b in 5/3 hour will b counted in next 1/3rd which has spd =40kms/hr
            => dist(5/3 hr) =5/3*40 =200/3 km
            now total distance by b =200+200/3 =800/3
            totl dist by a=200
            remaining dist =600-(200+800/3) =400/3km
            now tym taken by both=(400/3)/(60+40)
            note : 60km/hr of a is next one thrid
            40km/hr of b is last one third
            =>t =4/3hr
            now total tym frm m =4/3+5 =19/3 =6(1/3) =6 hrs20m
            totl tym frm n =4/3 +10/3 =14/3 =4(2/3) =4hrs 40m
            distance frm m by a =200+4/3*60 =280kms
            distance frm n by b =200 + 200/3 +4/3*40 =320kms
            =>option no c

          17. $~$PrAdeEP$K$~$~$

            avg spd = total dist/total tym
            =>a(s) =600/(200/40)+(200/60)+(200/50)
            =600/(5+10/3+4)
            =1800/37 =48.64864~48.6km/hr
            similarly for b also b(s) =48.6km/hr

          18. _/_

            Q5. Quantity I: Overall profit percentage if the cost prices of two shirts are equal. One shirt is sold for 20% profit and the other is sold for 10% loss.
            Quantity II: Profit % made in selling each meter if the profit made in selling 20 m of a cloth equals the cost price of 5 m of that cloth.
            (a) Quantity I > Quantity II
            (b) Quantity I Quantity II
            (b) Quantity I Quantity II
            (b) Quantity I Quantity II
            (b) Quantity I < Quantity II
            (c) Quantity I ≥ Quantity II
            (d) Quantity I ≤ Quantity II
            (e) Quantity I = Quantity II or No relation

            5-BB
            6-BB
            7-EE
            8-BB

          19. $~$PrAdeEP$K$~$~$

            5th question
            by alligation
            +20————-(-10)

            ———x————

            x+10————-20-x
            now a/c
            (x+10)/(20-x) =1/1 =>x =5%
            now from second statement
            profit on 20m cloth =sp on 20 m cloth -cp on 20m cloth
            =>cp on 5 m cloth =sp on 20m cloth -cp on 20 m cloth
            =>cp on 25 mt cloth =sp on 20 mtr cloth
            => p% =5/20*100 =25%
            =>q(1)< q(2)

          20. $~$PrAdeEP$K$~$~$

            water milk ratio
            w——————m
            2.5—————-10=>ratio =1:4
            now 20% =>1/5
            w(r) =1/5*2.5 =0.5 => left =2
            m(r) =1/5*10 =2 =>left =8
            =>a/c(x+2)/8 =4/1
            =>x =30l
            now again
            (30+2)/(y+8) =1/4
            =>y =120
            =>totl milk =120l========(q1)
            frm given cond q(2) =120
            =>q(1)=q(2)

          21. $~$PrAdeEP$K$~$~$

            p =16
            q=32
            lcm =32
            =>p =2,q=1
            p——————–q—————p—————–q
            2——————–1—————2—————–1
            =>3 work =2 days
            =>30 work =20days
            now left work 2 is done by p
            =>2p =2 =>p=1
            =>tot days=21
            now
            q————–p————–q————p
            1————-2—————1————2
            =>3 work =2 days
            =>30 work =20 days
            now remaing work =2 which is done by q
            now q will do 1 work now left work =>2-1= 1
            now this 1 work is completed by p
            =>2p =1=>p =1/2
            tot days =21+(1/2) =21(1/2)days
            =>q2>q1

          22. $~$PrAdeEP$K$~$~$

            6th 1
            volume of the left figure = volume of cube -vol of cylinder
            =>v(f) =(7)^3 -(pi)(7/2)^2*7
            =>v(f) =343-269.5 =73.5cm3
            now surface area of left fig =SA of cube -SA of cylinder
            since largest possible cylinder is to b cut out so left figure has the surface area without base
            => SA(f) =6(7)^2 -2(pi)(3.5)^2 + 2(pi)(3.5)(7)
            =>SA(f) =294-77+154 =371cm2
            =>q2 < q1

          23. _/_

            Directions (Q.13-14): According to a plan, a team of woodcutters decided to harvest 216 cubic meters of wheat in several days. In the first three days, the team fulfilled the daily assignment, and then it harvested 8 cubic metre of wheat over and above the plan every day. Therefore, a day before the planned date, they had already harvested 232 cubic meters of wheat.

            Q13. How many cubic metres of wheat a day did the team have to cut according to the plan?
            (a) 24
            (b) 28
            (c) 26
            (d) Can’t be determined
            (e) None of these

            Q14. To harvest 216 cubic metre of wheat 2 days before the planned date, how many cubic metres of wheat must be harvested by team over and the above the plan every day after first three days?
            (a) 08 cubic metre
            (b) 12 cubic metre
            (c) 10 cubic metre
            (d) 16 cubic metre
            (e) None of these

        2. AMAZON

          @aa@disqus_DgWqVOyvM5:disqus Dear , i didn’t get the first step
          G did the whole work of A MEANT 20 percent why u multiplied it?

          1. ??????????||ꀸΞ౮ɿՆɿς||√乇刀り乇イイム™

            G who can complete whole work in 30 days replaced A and did A’s part of work
            A completes 20% wrk and this wrk is done by G
            G completes 1 work in 30 days
            in short you can write it as
            G30*20%
            20%= 1/5 work in 30*1/5 = 6 days

          2. aayat

            G who can complete whole work in 30 days replaced A and did A’s part of work
            A completes 20% wrk and this wrk is done by G
            G completes 1 work in 30 days
            in short you can write it as
            G30*20%
            20%= 1/5 work in 30*1/5 = 6 days

      2. Alice

        A completes 20% wrk i.e 1/5 nw this wrk is done by G
        G completes 1 wrk in 30 days
        therefore 1/5 wrk in 30*1/5 = 6 days
        B does wrk for same number of days as G i.e 6

        and M does wrk in 1/4(E)days
        E completes 15% wrk in 6 days therefore 100% wrk in 40days
        M does wrk in 10 days(1*40/4)

        G………B……M
        30…….30…..10
        lcm=30
        1*6…….1*6……..3(as G/B wrk for 6days)
        wrk completed 6+6=12
        remaining=30-12=18
        18 wrk done by M in 6days (18/3)
        total days=6+6+6=18

    1. AB

      mam qs no 5 ki ans sahi hai mujhe doubt hai plz batado

      1. aayat

        Mera 3 1/5 ans a raha h

        1. AB

          same mera v 3 1/5 a rha

  8. Jellyfish

    thx AZ team
    pls posted more DI like time work, partnership,speed dist

  9. Jellyfish

    mam que no 5 ans is
    5*1/3
    x/12=4/15
    x=16/5

  10. ??????????||ꀸΞ౮ɿՆɿς||√乇刀り乇イイム™

    RBI GRADE B Quant qos

    1–A & B started a partnership with Rs. 4,000 and Rs. 4,800 respectively. After 6 months B quit. After the 8th month C joined with Rs. 5,400. If the difference between the profits between A and C was Rs. 4,400, what was the profit?

    2–There are 2 schemes A and B. Money invested in A at 10% p.a. CI for 2 years is less than money invested in B at 20% p.a. for 2 years by Rs. 480. If the amount invested in B is Rs. 3,000, what was the amount invested in A?

    1. Gajni

      Grade b 2017???

    2. Jellyfish

      1st ans
      16400 total profit

    3. Karthi Civil

      where do you get this question

  11. Jatin

    ma’am plz chk 5 th question ..ans should be.. 16/5 days

  12. ??????????||ꀸΞ౮ɿՆɿς||√乇刀り乇イイム™

    5 th Qo —-16/5 is the correct ans

    J completed the whole work =Average of A+B work=20+30/2=25 days
    C completed the whole work=25%=6,it completes 100% work in 24 days
    D completed the whole work=30%=7.5 , it completes 100% work in 25 days
    E completed the whole work=15%=6 it completes 100% work in 40 days
    J,C,D,E 5 day work=[5/25 + 5/24 + 5/25 + 5/40]= [1/5+5/24+1/5+1/8]=11/15
    Remaining work = 4/15 -should be completed by A and B=
    [1/20 + 1/130]*D = 4/15
    D=48/15=16/5 days

    1. AMAZON

      mine too 16/5

  13. Alice

    much needed ques..cud nt solve 6-10 without taking help of solution
    need more ques for practice try posting a quiz daily DI based
    thank you_/_

    1. AMAZON

      @disqus_VdZ2es3ilU:disqus explain second dear by LCM method please

      1. Alice

        A completes 20% wrk i.e 1/5 nw this wrk is done by G
        G completes 1 wrk in 30 days
        therefore 1/5 wrk in 30*1/5 = 6 days
        B does wrk for same number of days as G i.e 6

        and M does wrk in 1/4(E)days
        E completes 15% wrk in 6 days therefore 100% wrk in 40days
        M does wrk in 10 days(1*40/4)

        G………B……M
        30…….30…..10
        lcm=30
        1*6…….1*6……..3(as G/B wrk for 6days)
        wrk completed 6+6=12
        remaining=30-12=18
        18 wrk done by M in 6days (18/3)
        total days=6+6+6=18

        1. AMAZON

          @disqus_VdZ2es3ilU:disqus , thankyou Dear , got it 😉

    2. AMAZON

      also in 5th my answer is coming 16/5
      what about yours?

  14. Destiny : Ultimate

    Thanku mam :)))

  15. $~$PrAdeEP$K$~$~$

    2(a+b) +6c +7f =1
    2*1/12 +6*1/24 +7f =1
    1/6+1/4+7f =1
    =>7f =14/24
    =>f =1/12 =>12 days

    1. $~$PrAdeEP$K$~$~$

      heehee..:)—/—

  16. $~$PrAdeEP$K$~$~$

    nice 2nd question….:)

    1. Player

      8)B= 26, 17, 8…………bhai ye value kaise ayi …smjh aya apko ??

      1. $~$PrAdeEP$K$~$~$

        yes linear equation bna k diffrent set of values rkni padegi jo rhs k equal ho then us cases mn 3 possiblities aayengi whi h…ans…:))) agr aapko pehle wale ka ans mil gya to bki k questions ussi se associated means linked h mne pehle wale ka step btaya h aapko….whi se aapko smj aayega bro…:)))

        1. Player

          If the number of yellow pen lies between 60 and 70,
          red :green =8:1
          yel :blu =3:1

          yellow = 3*21 ,3 *22 , 3 *23
          so
          blu =21,22,23……ye hogi na ???

          1. $~$PrAdeEP$K$~$~$

            nhi….hoga bro…:)))

        2. Player

          Number of yellow pen = 3B
          possible value of B= 26, 17, 8………………………………….ye value kha se aa gyi ?
          hence number of yellow pen= 3*26, 3*17, 3*8= 84, 51, 24
          hence a range of 60-70 is not possible

          1. $~$PrAdeEP$K$~$~$

            yes ans is 60-70 not possible….bro…first question mn apan ne blue ki value find ki thi naa wo lo….wha se ans aayega
            26 17 8

  17. KUCH B........

    6 se 10 nice

  18. Amit Kumar Singh

    4th question mein 63/13 kaise Aaya

  19. Prasoon Mishra

    di no 2 awsom

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