Directions(1-5): What approximate value will come in place of questions mark ‘?’ in the following questions.
- (100.05% of 44.89)/14.98 = (?)^1/2 – (49)^1/2
899078100110Option D
(100.05% of 44.89)/14.98 = (?)^1/2 – (49)^1/2
=>(100% of 45)/15 = (?)^1/2 – 7
=>3+7 = (?)^1/2
=>? = 100 - (135/17)% of (136/15) of 500 = ?% of 800
3930475045Option E
(135/17)% of (136/15) of 500 = ?% of 800
=>(135/1700) * 136/15 * 500 = ?% of 800
=>72 * 500 = ?*800
=>? = 45 - (15.78)^2 + 220% of 20.11 = ?^2 * 74.88%
1410171220Option E
(15.78)^2 + 220% of 20.11 = ?^2 * 74.88%
=>(16)^2 + 44 = ?^2 * 75%
=>?^2 = (400)
=>? = 20 - 16% of 499.89 = 20% of ? + 11.99% of 201
255230280256267Option C
16% of 499.89 = 20% of ? + 11.99% of 201
=>16% of 500 = 20% of ? + 12% of 200
=>80 = 20% of ? + 24
=>? = 280 - ? + 521.88 – 392.44 = 14.94*24
220230210240250Option B
? + 521.88 – 392.44 = 14.94*24
=>? + 522 – 392 = 15*24
=>? + 130 = 360
=>? = 230 - Find the average number of girls who appeared for the exam from school A,B and C taken together.
3067453750Option C
Average = (45+50+40)/2 = 45 - The number of girls who appeared in exam from school D is what percent of number of students who appeared from school B?
10%24%16%20%22%Option D
Required% = (25/125)*100 = 20% - Find the ratio of the number of students appeared in exam from school D to the number of students appeared in exam from school A.
7:64:38:94:75:6Option E
Ratio = 125:150 = 5:6 - Find the difference between number of students who appeared in exam from school C and the number of girls who appeared in exam from school E.
8070906050Option B
Difference = 160-90 = 70 - The number of students who appeared in the exam from school C in 2015 is 25% more than the number of students who appeared in the exam from same school in 2012.The number of boys is 50% more than the number of girls appeared in the exam from school C in 2015. Find the difference between number of boys and number of girls who appeared in the exam from school C in 2015.
1050204030Option D
Number of students who appeared in the exam from school C in 2015=160*1.25 = 200
1.5x + x = 200
=>x = 80
Difference = 120 – 80 = 40
Directions(6-10): Answer the following questions based on given information.
The graph shows the number of boys and percentage of girls out of the total students who appeared for an exam in 2012 from different schools.
Number of students who appeared for exam = Number of boys + Number of girls
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