Quant Test for NIACL 2018 Prelim Exam Set – 15

  1. (27)^2 × 6 ÷ 9 + (7)^3 + 71 = (?)^3 – 431
    12
    16
    11
    14
    18
    Option C
    (27)^2 × 6 ÷ 9 + (7)^3 + 71 = (?)^3 – 431 =>(729 × 6 ÷ 9) + 343 + 71 + 431 = x^3 => 486 + 343 + 71 + 431 = x^3 => x ^3 = 1331 =>x = 11

     

  2. 87.5% of 3888 – 462 × 6 = ? % of 4200
    15
    23
    20
    10
    12
    Option A
    87.5% of 3888 – 462 × 6 = ? % of 4200 =>87.5% of 3888 – 462 × 6 = ? % of 4200 => 3402–2772 = x/100 × 4200 =>630 = 42x =>x = 15

     

  3. 12.5% of 9600 – 16.67% of 3240 = 33% of ?
    2000
    1110
    2250
    2010
    2550
    Option A
    12.5% of 9600 – 16.67% of 3240 = 33% of x =>33% of x = 9600/8 – 3240/6 => 33% of x = 1200–540 =>x = 660×100/33 => x = 2000

     

  4. 150% of 5/8 of x = 75% of 1250
    1250
    1320
    1100
    1440
    1000
    Option E
    150% of 5/8 of x = 75% of 1250 =>150% of 5/8 of x = 75% of 1250 => x = 1000

     

  5. 24.92% of 1504 + 44.88% of 804 = ?
    777
    735
    720
    700
    715
    Option B
    24.92% of 1504 + 44.88% of 804 = ? => 25/100 ×1500 + 45/100 ×800 = 375 + 360 = 735

     


  6. Directions(6-10):
    Following graph shows the percentage growth of population of six cities (A, B, C, D, E and F) in three decades.

  7. If the population of City D is 2087250 in the the year 2000, what was its population in the year 1970?
    20 lakh
    5 lakh
    15 lakh
    11 lakh
    10 lakh
    Option D
    Population(1970) =2087250* 100/115* 100/125* 100/132 = 11 lakh

     

  8. If the population of City E and City F in the year 1970 was 12.5 lakh and 10 lakh respectively, what is the difference between the population of City E and the population of City F in the year 2000?
    4.102 lakh
    2.115 lakh
    3.303lakh
    4.805 lakh
    2.105 lakh
    Option D
    E(2000) = 12.5* 125/100* 116/100* 140/100 = 25.375 lakh F(2000) = 10* 121/100* 125/100* 136/100 = 20.57 lakh Difference = 25.375 – 20.57 = 4.805 lakh

     

  9. If the population of City C and that of City D were equal in the year 1970, what is the ratio of the population of City C to that of City D in 1990?
    21:23
    22:25
    18:19
    17:21
    19:22
    Option B
    Let the population of City C and City D be x at the beginning of 1970. Population-C1990 = x *110/100* 115/100 Population-D1990 = x *115/100* 125/100 Ratio = 110/125 = 22/25

     

  10. If the population of City C was 8.5 lakh in the year 1970, what is the population of City C in the year 2000?
    12.903 lakh
    10.812 lakh
    14.145 lakh
    11.503 lakh
    10.905 lakh
    Option A
    Population = 8.5* 110/100* 115/100* 120/100 = 12.903 lakh

     

  11. If, in the year 2000, the populations of City A and B are 1388800 and 1302912 respectively, the population of City B in the year 1970 was what percentage of the population of City A in the year 1970?
    100%
    60%
    90%
    70%
    80%
    Option C
    Population-A1970 1388800* 100/112* 100/124* 100/125 = 8 lakh Population-B1970 1302912* 100/120* 100/116* 100/130 = 7.2 lakh Required percentage = 7.2/8 × 100 = 90%

     


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