Hello Aspirants
State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.
Click here to know the details of the Examination
The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:
Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Â
Directions(1-5): What should come in place of the question mark (?) in the following number series?
- 57, 59 , 66 , 94, 157 , ?
250222225283211Option D
+1³+1, +2³ – 1, +3³ + 1, +4³ – 1………… - 15, 18, 16, 19, 17, 20, ?
132218118Option C
15 + 3 = 18
18 – 2 = 16
16 + 3 = 19
19 – 2 = 17
17 + 3 = 20
20 – 2 = 18 - 10, 14, 25, 55, 140,?
316388302350374Option B
14 – 10 = 4
25 – 14 = 11 = 4 × 3 -1
55 – 25 = 30 = 11 × 3 – 3
140 – 55 = 85 = 30 × 3 – 5
? = 140 + 85 × 3 – 7 = 140 + 248 = 388 - 1200, 480, 192, 76.8, 30.72, 12.288, ?
5.41003.11224.91524.08455.8102Option C
1200 / 2.5 = 480
480 / 2.5 = 192
192 / 2.5 =76.8
76.8 / 2.5 = 30.72
30.72 / 2.5 = 12.288
? = 12.288 / 2.5 = 4.9152 - 963, 927, 855, 747, 603, 423, ?
210215198200207Option E
963 – 1 × 36 = 963 – 36 = 927
927 – 2 × 36 = 927 – 72 = 855
855 – 3 × 36 = 855 – 108 = 747
747 – 4 × 36 = 747 – 144 = 603
603 – 5 × 36 = 603 – 180 = 423
? = 423 – 6 × 36 = 423 – 216 = 207 - The height of a room is 40% of its semiperimeter. It cost Rs 260 to paper the walls of the room with paper 50 cm wide at the rate of Rs 2 per m allowing an area of 15 m2 for doors and windows. What is the height of the room ?
10m6m4m12m9mOption C
Let the length, breadth and height of the room be l, b and h respectively.
Then, h = 0.4 ( l + b)
Area of the four walls = 2 (l + b) h = 2 (l + b) × 0.4 (l + b) = 0.8 (l + b)^2
Required area where paper has to be pasted = 4/5 (l + b)^2 – 15
Now, area of paper = area of wall Length × breadth = 4/5 (l + b)^2 – 15
Length = [4/5 (l + b)^2 – 15]/1/2
Given, 2*2[4/5 (l + b)^2 – 15] = 260
=> (l + b)^2 = 320
=> (l + b)^2 = 100
=> (l + b) = 10
=>h = 0.4 × 10 = 4 m - Kamya purchased an item of Rs 46,000 and sold it at a loss of 12 percent. With that amount she purchased another item and sold it at a gain of 12 percent. What was her overall gain/loss ?
Loss Rs.666.2Gain Rs.650.15Gain Rs.699.8Loss Rs.662.4Loss Rs.677.5Option D
First S.P. = 46000 * 88/100 = Rs. 40480
Second S.P. = 40480 * 112/100 = Rs. 45337.6
Loss = Rs. (46000 – 45337.6) = Rs. 662.4 - A grocer purchased 2 kg. of rice at the rate of Rs. 15 per kg. and 3 kg. of rice at the rate of Rs. 13 per kg. At what price per kg should he sell the mixture to earn 33(1/3)% profit on the cost price ?
Rs.17.4Rs.15.7Rs.20.2Rs.18.4Rs.10.5Option D
2 kg of rice at Rs. 15/kg + 3 kg of rice at Rs. 13/kg Total weight = 2 + 3 = 5 kg
Total cost price = (2 × 15) + (3 × 13) = 30 + 39 = Rs. 69
Cost price per kg of the mixture = 69/5 = Rs.13.80
Selling price to get 33(1/3) % profit = [10 + 33 (1/3)]/100× Rs 13.80
= 400× Rs 13.80/3*100
= 4/3 × Rs 13.80
= Rs 18.40 - A bus started its journey from Ramgarh and reached Devgarh in 44 minutes with its average speed of 50 km/hour. If the average speed of the bus is increased by 5 km/hour, how much time will it take to cover the same distance ?
60 mins.50 mins.70 mins.40 mins.20 mins.Option D
Distance between Ramgarh and Devgarh = 50 * 44/60
= 110/3 km
New speed = 55 kmph = 55/60 km/minute
Required time = Distance/Speed
= 110/3 × 60/55 = 40 minutes - In how many different ways can 4 blue beads and 3 red beads be arranged in a row such that all the blue beads are together and all the red beads are together.
288243205255278Option A
Required no. of ways = 4! x 3! x 2!
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