Quant Test for SBI PO 2018 Prelim Exam Set – 53

Banya

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

 

Directions(1-5): What will come in place of question mark “?” in the following questions.

  1. ? = (12^2 + 44 – 8^ 2 ) ÷ (64)^1/3 × 6 ^2 – 11^2 + 28
    1010
    1500
    1225
    1023
    1225
    Option D
    ? = (12^2 + 44 – 8^ 2 ) ÷ (64)^1/3 × 6 ^2 – 11^2 + 28
    ? = [144 + 44 – 64]/ 4 × 36 − 121 + 28
    ? = 1116 − 121 + 28
    ?=1023

     

  2. ? = (324)^1/2 × (256)^1/2 ÷ (216)^1/3 × (512)^1/3
    300
    333
    384
    320
    313
    Option C
    ? = (324)^1/2 × (256)^1/2 ÷ (216)^1/3 × (512)^1/3
    ? = 18 × 16/ 6 × 8 = 384

     

  3. ? = 2(2/3) – 3( 5/ 6) + 5 (1/ 4) + 4( 3/ 8)
    2 (11/ 20)
    7 (13/ 21)
    3 (9/ 22)
    5(12/ 23)
    8 (11/ 24)
    Option E
    ? = 2(2/3) – 3( 5/ 6) + 5 (1/ 4) + 4( 3/ 8)
    ? =( 2 − 3 + 5 + 4) + (2/ 3 – 5/ 6 + 1/ 4 + 3 /8)
    ? = 8 + (80 − 100 + 30 + 45)/ 120
    ? = 8 + 55 /120 = 8 + 11 /24
    = 8 (11/ 24)

     

  4. (122 × 42 ÷ 12 + 72 ÷ 36 × 25) ÷ 3 =? +24
    111
    135
    122
    102
    140
    Option B
    (122 × 42 ÷ 12 + 72 ÷ 36 × 25) ÷ 3 =? +24
    (122 × 42 ÷ 12 + 72 ÷ 36 × 25) ÷ 3 =? +24
    ? +24 =[ 427 + 50]/ 3 ? +24 = 159
    ? = 159 – 24 = 135

     

  5. ? = 45% of 180 + 33% of 200 − 12% of 350 + 23% of 400
    155
    197
    123
    147
    110
    Option B
    ? = 45% of 180 + 33% of 200 − 12% of 350 + 23% of 400
    ? = 45% of 180 + 33% of 200 − 12% of 350 + 23% of 400
    ? = 81 + 66 − 42 + 92
    ? = 197

     


    6. Directions(6-10):     Study the following table and answer accordingly. The following table shows the information of different household items.

  6. Find the sum of selling price of Grinding Machine and Iron.
    Rs.5220
    Rs.4455
    Rs.5240
    Rs.3550
    Rs.4220
    Option D
    The S.P of Grinding Machine=2400
    The S.P of Iron=1150
    Sum= Rs.3550

     

  7. Find the sum of the selling prices of Fan and Grinding Machine.
    Rs. 4050
    Rs. 3210
    Rs. 4200
    Rs. 5000
    Rs. 3000
    Option A
    The selling price of Fan =1650
    The selling price of Grinding Machine =2400
    Total =Rs. 4050

     

  8. Find the approximate discount % of Iron.
    13.6%
    22.2%
    23.3%
    32.4%
    20.5%
    Option C
    The selling price for Iron =1150
    Discount=350
    Discount %= 350 /1500 × 100 = 23.3%

     

  9. Find the difference between the selling price for Grinding Machine and Refrigerator.
    250
    450
    550
    200
    350
    Option E
    The selling price for Grinding Machine =2400
    The selling price for Refrigerator =2750
    Difference=350

     

  10. The selling price of Cooler is 20% more than the Selling Price of Iron and the discount % is equal to the twice the profit % of Fan. Find the Marked price for Cooler.
    Rs. 1550
    Rs. 1725
    Rs. 1400
    Rs. 1120
    Rs. 1225
    Option B
    The S.P of Cooler =120/100 × 1150 = 1380
    Discount =20%
    M.P=1380 × 100/ 80 =Rs. 1725

     


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