- Sum of A’s and B’s age 6 years ago is 88. A’s age 18 yrs ago is equal to B’s age 6 years ago. Find the age of A two year hence?
51 years62 years58 years44 years50 yearsOption C
A+B = 88+12 = 100 –(1)
A-18 = B-6 A-B = 12 –(2)
On solving these two equations, A = 56
After 2 years = A = 58 years - Train A of length 120 m can cross a platform of length 240 m in 18 second the ratio of speed of train A and Train B is 4 : 5. Then find the length of Train B if train B can cross a pole in 12 seconds.
700 m600 m500 m300 m400 mOption D
Let speed of train A be S
S × 18 = 360
S = 20 m/s
A : B = 4 : 5
Speed of B = 25 m/s
Length of train B = 25 × 12 = 300 m - Sum of volume of cylinder (S) and volume off cone (C) is 2190𝝅 cm² & height of both cylinder and cone is same i.e, 10 cm. If radius of cone is 15 cm then find the ratio of radius of S to radius of C?
4:52:35:61:23:1Option A
Pi*r*r*h + 1/3*pi*R*R*h = 2190*pi
=>r/R = 4:5 - In an alloy, zinc and copper are in the ratio 1 : 2. In the second alloy the same elements are in the ratio 2 : 3. In what ratio should these two alloys be mixed to form a new alloy in which the two elements are in ratio 5 : 8?
9/133/102/75/84/11Option B
Zinc = 5/13-1/3 = 1/65
Copper = 2/5-5/13 = 2/39
Required ratio = (1/ 65)/(2/39) = 3/10 - In a box there are 6 blue ball, x red balls & 10 green balls. Probability of choosing one red ball from the given box is 𝟏/𝟑 . Then find the sum of red and blue balls in the box?
1416101820117.5, 117, 119, 111, 143, ?Option A
x /(x + 16) = 1/3
=>3x = x + 16
=>x = 8
sum of red & blue balls = 8 + 6 = 14 - 117.5, 117, 119, 111, 143, ?
2010251530Option D
-0.5
+2
-8
+32
-128
? = 15 - 3, 11, 31, 69, 131, ?
200223274250291Option B
1^3+2
2^3+3
3^3+4
4^3+5
5^3+6
6^3+7
? = 223 - 12, 25, 48, 99, 194, 393, ?
666745780720851Option C
*2+1
*2-2
*2+3
*2-4
*2+5
*2-6
? = 780 - 1, 13, 83, 419, 1679, ?
63155522633541025039Option E
*7+6
*6+5
*5+4
*4+3
*3+2
? = 5039 - 15, 12, 31, 148, ?
14421330121010271120Option D
*1-3
*3-5
*5-7
*7-9
? = 1027
Directions(6-10): Find the missing term ‘?’ of the following series.
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