Directions (1 – 5): Study the following bar graph and answer the questions that follow.
Votes are polled in 10 constituencies of Haryana. After the polls, some votes were declared invalid.
The bar chart shows the % of votes received by the winning and the losing candidates (Suppose there are only 2 candidates) out of the “valid votes”, which is “total votes” polled minus the “invalid votes”. The one which got the highest number of votes from the “valid votes” was declared the winner.
The total number of invalid votes in each constituency – Karnal, Faridabad, Gurgaon, Hisar, Sirsa, Bhiwani, Ambala, Rohtak, Panipat and Kurukshetra are 3800, 2000, 11400, 0, 2700, 150, 4200, 360, 320, 6800 respectively.
- What is the total number of voters in the given 10 constituencies of Haryana?
A) 217000
B) 234000
C) 276000
D) 211000
E) Cannot be determined
- What is the difference between the number of votes received by the winning and the losing candidate from Sirsa?
A) 5400
B) 5700
C) 6600
D) 4500
E) 5900
- What is the total number of valid votes received by winning candidates from Panipat, Ambala and Karnal together?
A) 26540
B) 21760
C) 23780
D) 26340
E) Cannot be determined
- In the last elections, there was a total of 3,00,000 voters in these 10 constituencies. If this time, there is an increase by 10%, thhen what is eth total number of voters from Hisar?
A) 1,28,000
B) 1,23,000
C) 1,32,000
D) 1,34,000
E) 1,25,000
- What is the total number of valid votes from Bhiwani and Kurukshetra together?
A) 32,030
B) 38,400
C) 23,760
D) 45,550
E) 48,050
Directions (6 – 10): Study the following bar graph and answer the questions that follow.
The bar graph shows the percentage of students passing in various standards in a school. Maximum marks for each subject of every class is same.
- If the number of boys and girls passing in class 5 are same, then what is the ratio between the number of boys and girls in class 5?
A) 4 : 3
B) 5 : 3
C) 4 : 9
D) 3 : 4
E) 3 : 8
- In class 7, 44% of the total students got passed. If total number of boys in class 7 is 200, then what is the total number of girls in class 7?
A) 50
B) 52
C) 59
D) 66
E) 60
- If the total number of boys and girls in each class is 150 and 120 respectively, then what is overall pass percentage of the school?
A) 64%
B) 69%
C) 72%
D) 81%
E) 54%
- If the ratio between the number of boys and the number of girls in class 9 is 4 : 1, then what is the ratio between number of boys passed and number of girls passed in class 9?
A) 9 : 4
B) 9 : 5
C) 4 : 1
D) 6 : 7
E) 7 : 2
- Assuming the data of question 8, if the overall average marks of boys is 50% and that of girls is 60%, then what is the average marks of the students in the school?
A) 42%
B) 54%
C) 58%
D) 65%
E) 63%
mam 10q explan plz
see the explanation now
100 gets cancelled so did not use before,
now u will get it
i skip que no 1 :p
itna long calculation 🙁
question 10 ka explanation kuch alg hi hai que se..
how ??? i think it is correct
its correct
I dint use 100 for percent – cz it gets cancelled
see the explanation now
ye 100 ki baat nahi hai ma’am
que ne boy ka 50% avg bola hai per ye nahi clear kia ki total boy ki strength ka 50% same as in girl
Question 8 me given hai ki in each class 150 boys n 120 girls.
So ek class ka lo ya sari classes ka. Answer same hi aega.
Sari classes ka lenge to 6 se multiply hga in numerator n denominator and that 6 will be cancelled.
Overall Average of boys is 50%.
Means total jitne b boys hai
bhai yaarr allegation se karloo would be easy
allegation se kaise hoga?
thank you mam
bro q.no. 4 btao
ty 🙂
In Q5. Total no. of valid votes asked, why the options are in %?
Yes. Answer is a number
in the bar graph of 1st one, how to measure % of the cities easily?… because its too difficult..plz help me
Q7. B—————G
——40————–60
————–44———–
—–16——————-4
—-4————————1
4——>200
1——->50
thank u…
mam please explain q.no. 4
From 1st q add the voters from constituencies
Hisar k to 1st q me find nhi ho sakte
Or constituencies k add karo
That iis 207000
bt mam 10% se increase kar rahe voters toh hum purana kyu lenge
different constituencies k bhi increase honge na
mam 3 no. qstn pls explain kar do……..
What is the total number of valid votes received by winning candidates from Panipat, Ambala and Karnal together?
panipath total votes= 4000
valid votes=4000-320=3680
total nmber of valid votes received by winning candidate from panipath=3680*(81/100)
aisa kyun nhi hua mam?
mam, in the 7th question:
Let total number of girls in class 7 = x
total number of boys passing = 200 * 0.4 = 80
Total number of girls passing = x*0.6 = 0.6x
=>So passed percentage of students = (80+0.6x)/(200+x) here in this step
//” (80+.6x)/(200+x) * 100″// but without taking 100, % is possible if i am wrong plz correct me…
So 44/100 = (80+0.6x)/(200+x)
ty mam
819385 738055I dont agree with this specific post. However, I did researched in Google and Ive found out which you are correct and I had been thinking inside the incorrect way. Continue producing quality material similar to this. 674933
I am really loving the theme/design of your weblog.
Do you ever run into any browser compatibility issues?
A few of my blog readers have complained about my blog not
operating correctly in Explorer but looks great in Chrome.
Do you have any recommendations to help fix this issue?
Hi to every body, it’s my first visit of this weblog; this blog carries amazing and in fact fine material
in favor of visitors.