Hello Aspirants
State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.
Click here to know the details of the Examination
The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:
Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Â
Directions(1-5): In the following questions, two equations numbered are given in variables x and y. You have to solve both the equations and find out the relationship between x and y.
- I. x2 + √5x – 10 = 0
II. 2y2 + 9√5y + 50 = 0x=y or relation cannot be established.x>=yx>yy>xy>=xOption
I. x2 + √5x – 10 = 0
x2 + √5x – 10 = 0
x2 + 2√5x – √5x – 10 = 0
x = -2√5, √5
II. 2y2 + 9√5y + 50 = 0
2y2 + 9√5y + 50 = 0
2y2 + 4√5y + 5√5y + 50 = 0
y = -2√5, -5√5/2
x ≥ y - I. 3x2 + 16x + 20 = 0
II. 3y2 – 14y – 5 = 0y>xx>yy>=xx>=yx=y or relation cannot be established.Option A
I. 3x2 + 16x + 20 = 0
3x2 + 16x + 20 = 0
3x2 + 6x + 10x + 20 = 0
x = -2, -10/3
II. 3y2 – 14y – 5 = 0
3y2 – 14y – 5 = 0
3y2 – 15y + y – 5 = 0
y = -1/3, 5
x < y - I. 4x2 + 19x + 21 = 0
II. 2y2 – 25y – 27 = 0x>=yy>=xx>yy>xx=y or relation cannot be established.Option D
I. 4x2 + 19x + 21 = 0
4x2 + 19x + 21 = 0
4x2 + 12x + 7x + 21 = 0
x = -3, – 1.75
I. 4x2 + 19x + 21 = 0
2y2 – 25y – 27 = 0
2y2 – 27y + 2y – 27 = 0
y = 13.5, -1
x < y - I. 2x2 – 9x + 4 = 0
II. 2y2 + 7y – 4 = 0y>=xx>=yx=y or relation cannot be established.y>xx>yOption B
I. 2x2 – 9x + 4 = 0
2x2 – 9x + 4 = 0
2x2 – 8x – x + 4 = 0
x = 4 , 1/2
II. 2y2 + 7y – 4 = 0
2y2 + 7y – 4 = 0
2y2 + 8y – y – 4 = 0
y = -4, ½
x ≥ y - I. 3x2 + 16x + 20 = 0
II. 3y2 + 8y + 4 = 0x>yx=y or relation cannot be established.y>xy>=xx>=yOption D
I. 3x2 + 16x + 20 = 0
3x2 + 16x + 20 = 0
3x2 + 6x + 10x + 20 = 0
x = -10/3, -2
II. 3y2 + 8y + 4 = 0
3y2 + 8y + 4 = 0
3y2 + 6y + 2y + 4 = 0
y = -2, -2/3
x ≤ y - The cost of one kg of guava in Jalandhar is approximatelywhat per cent of the cost of two kg of grapes in Chandigarh?
42%25%40%30%34%Option E
Cost of one kg of guava in Jalandhar = 60
Cost of two kg of grapes in Chandigarh = 90 × 2 = 180
Required % = 60/180 × l00 =1/3 × l00
= 33.33 = 34% (approx.) - In which city is the difference between the cost of one kg of apple and the cost of one kg of guava the second lowest?
JalandharHoshiarpurDelhiJalandharRoparOption C
Cost of one kg apple in Jalandhar = 160 Cost of one kg guava in Jalandhar = 60
Difference = 160 – 60 = 100
Similarly, in Delhi = (130 – 90) = 40
In Chandigarh = (180 – 120) = 60
In Hoshiarpur = (90 – 30) = 60
In Ropar = `(40 – 20) = 20
Hence, the second lowest difference between price of one kg apple and one kg guava is in Delhi. - What is the ratio of the cost of one kg of apples from Ropar to the cost of one kg of grapes from Chandigarh?
1:35:72:34:92:5Option D
Required ratio = 40/90 = 4/9 - What total amount will Ram pay to the shopkeeper for purchasing 3 kg of apples and 2 kg of guavas in Delhi?
440570510405400Option B
Total amount = 3 × 130 + 90 × 2
= 390 + 180
= 570 - Ravinder had to purchase 45 kg of grapes from Hoshiarpur. The shopkeeper gave him a discount of 4% per kg. What amount did he pay to the shopkeeper after the discount?
80008208770080088200Option B
Cost of 45 kg grapes in Hoshiarpur = 45 × 190
= 8550
After 4% discount, cost price of grapes = 8550 – 8550 × 4 /100
= 8550 – 342
= 8208
Hence, Ravindar had to pay 8208
Directions(6-10): Study the following graph carefully to answer the questions that follow: