Quant Test for IBPS PO 2018 Prelim Exam Set – 18

Directions(1-5): Find the relation between x and y and choose a correct option.

1. I. x^2 − 6x + 9 = 0
   II. y^2 − 11y + 24 = 0
   y>x
   x>y
   y>=x
   x=y or relation cannot be established.
   x>=y
   Option C
   I. x^2 − 6x + 9 = 0
   => x = 3, 3
   II. y^2 − 11y + 24 = 0
   => y = 8, 3
   y ≥ x

    

2. I. 18x² + 18x + 4 = 0
   II. 12y² + 29y + 14 = 0
   x>y
   x>=y
   y>x
   y>=x
   x=y or relation cannot be established.
   Option B
   I.18x² + 18x + 4 = 0
   => 18x² + 12x + 6x + 4 = 0
   =>6x (3x + 2) +2 (3x + 2) = 0
   => (3x + 2) (6x + 2) = 0
   x = −2/3, −1/3
   II. 12y² + 29y + 14 = 0
   =>12y² + 21y + 8y + 14 = 0
   =>3y(4y + 7) +2 (4y + 7) = 0
   => (4y+ 7) (3y +2) = 0
   y = −7/4, −2/3
   x ≥ y

    

3. I. y² + 2y – 3 = 0
   II. 2x² – 7x + 6 = 0
   y>=x
   y>x
   x>y
   x=y or relation cannot be established.
   x>=y
   Option C
   I. y² + 2y – 3 = 0
   =>y² +3y – y – 3 = 0
   => (y + 3) (y- 1) = 0
   y = -3, 1
   II. 2x² -7x + 6 = 0
   => 2x² – 4x -3x + 6= 0
   =>2x(x – 2) – 3 (x- 2) = 0
   => (x – 2) (2x – 3) = 0
   x = 2, 3/2
   x > y

    

4. I. x^2−5x−14 = 0
   II.y^2+7y+10 = 0
   x>y
   y>=x
   x=y or relation cannot be established.
   x>=y
   y>x
   Option D
   I. x^2 − 7x + 2x − 14 = 0
   => x(x − 7) + 2(x − 7) = 0
   x = 7, −2
   II.y^2 + 5y + 2y + 10 = 0
   y = −2, −5
   x ≥ y

    

5. I. 7x^2 – 21x – 33x + 99 = 0
   II. 4y^2 – 10y – 6y + 15 = 0
   x=y or relation cannot be established.
   x>=y
   y>x
   y>=x
   x>y
   Option E
   I. 7x^2 – 21x – 33x + 99 = 0
   => 7x(x − 3) − 33(x − 3) = 0
   => x = 3, 33/7
   II. 4y^2 – 10y – 6y + 15 = 0
   => 2y(2y − 5) − 3(2y − 5) = 0
   => y = 3/2 , 5/2
   x>y

    


Directions(6-10): Study the following table shows the percentage of marks scored by 6 students in different subjects :


6. What is the ratio of marks obtained by students B and C in Maths together to marks obtained by D and E together in History ?
   13:28
   14:29
   14:27
   11:29
   15:22
   Option B
   Required ratio = (72+68)*3/4 : (85+60)*3/2 = 14:29

    

7. What is the total marks obtained by B in all subjects together ?
   590
   578
   620
   581
   500
   Option D
   Total Marks
   = 44*3/4 + 72*3/4 + 58 + 80*3/2 + 95*200% + 72*7/4
   = 33 + 54 + 58 + 120 + 190 + 126
   = 581

    

8. The marks obtained by student C in Chemistry is what per cent of the total marks obtained by C in Maths ?
   140%
   160%
   150%
   100%
   120%
   Option A
   Required% = 72/51*100 == 140%

    

9. What is the average marks obtained by E in all subjects together ?
   66%
   84%
   77%
   95%
   88%
   Option D
   Required average marks = (108* 75% + 82* 100% + 60* 150% + 88 * 200% + 80 *175%) = 95%

    

10. The marks obtained by student D in Science is approximately what percent of the mark obtained by the students B in Maths ?
    250%
    222%
    308%
    200%
    278%
    Option E
    Required% = (200%*75)/(72*75%)*100 = 150/54*100 == 278%