Hello Aspirants
We are providing you with Quantitative Aptitude Section Mock for the upcoming IBPS Clerk and RBI Assistant 2017 Prelim Exam. It contains 35 questions and time limit is 22 minutes.
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Question 1 of 35
1. Question
1 pointsDirections (1-5): What value should come in place of x in the following questions?
1615 ÷ 19 – 12 × 27 + 45% of 1240 = x
Correct
Incorrect
Unattempted
-
Question 2 of 35
2. Question
1 pointsDirections (1-5): What value should come in place of x in the following questions?
532 – 65% of 1380 – 948 ÷ x = 1833
Correct
Incorrect
Unattempted
-
Question 3 of 35
3. Question
1 pointsDirections (1-5): What value should come in place of x in the following questions?
85% of 160 – 52% of 350 + 68 = x
Correct
Incorrect
Unattempted
-
Question 4 of 35
4. Question
1 pointsDirections (1-5): What value should come in place of x in the following questions?
26% of 650 + √784 – 16 × 13 = x
Correct
Incorrect
Unattempted
-
Question 5 of 35
5. Question
1 pointsDirections (1-5): What value should come in place of x in the following questions?
√2916 + 38% of 450 – 12 × x = 21
Correct
Incorrect
Unattempted
-
Question 6 of 35
6. Question
1 pointsA, B, C are three towns on a river which flows uniformly. B is equidistant from A and C. A man rows from A to B and back in 12 hrs. He can row from A to C (upstream) in 8 hrs. The ratio of speed of man in still water to the speed of the current is:
Correct
Let the river be flowing from A to C and AB= BC=a
a/(u+v)+a/(u-v)=12
2a/(u+v)=8
a/(u+v)=4
a/(u-v)=8.
Then (u-v)/(u+v)=1/2
u=3v
u/v=3/1==>3:1Incorrect
Let the river be flowing from A to C and AB= BC=a
a/(u+v)+a/(u-v)=12
2a/(u+v)=8
a/(u+v)=4
a/(u-v)=8.
Then (u-v)/(u+v)=1/2
u=3v
u/v=3/1==>3:1Unattempted
Let the river be flowing from A to C and AB= BC=a
a/(u+v)+a/(u-v)=12
2a/(u+v)=8
a/(u+v)=4
a/(u-v)=8.
Then (u-v)/(u+v)=1/2
u=3v
u/v=3/1==>3:1 -
Question 7 of 35
7. Question
1 pointsA and B enters into a partnership. A supplies whole of the capital amounting to Rs. 45000 with the condition that the profits are to be equally distributed and that B pays A interest on half of the capital at 10% per annum, but receives, Rs. 120 per month for carrying on the concern. When B’s income is 1/2 of A’s income, their total yearly profit is:
Correct
Let the total profit be Rs. x
Salary to B = (120 x 12) = Rs.1440
Share of each = (x-1440)/2
Interest paid by B =22500*10/100=Rs2250.
Total money received by B= (x-1440)/2+1440-2250 =(x-3060)/2
Total money received by A = (x-1440)/2 + 2250
=(x+3060/2)
Then 1/2 – (x+3060/2) – (x-3060)/2
x=Rs 9180.Incorrect
Let the total profit be Rs. x
Salary to B = (120 x 12) = Rs.1440
Share of each = (x-1440)/2
Interest paid by B =22500*10/100=Rs2250.
Total money received by B= (x-1440)/2+1440-2250 =(x-3060)/2
Total money received by A = (x-1440)/2 + 2250
=(x+3060/2)
Then 1/2 – (x+3060/2) – (x-3060)/2
x=Rs 9180.Unattempted
Let the total profit be Rs. x
Salary to B = (120 x 12) = Rs.1440
Share of each = (x-1440)/2
Interest paid by B =22500*10/100=Rs2250.
Total money received by B= (x-1440)/2+1440-2250 =(x-3060)/2
Total money received by A = (x-1440)/2 + 2250
=(x+3060/2)
Then 1/2 – (x+3060/2) – (x-3060)/2
x=Rs 9180. -
Question 8 of 35
8. Question
1 pointsAverage score of P, Q and R is 63. P’s score is 15 less than S and 10 more than Q. If S scored 30 marks more than the average scores of P, Q and R, what is the sum of Q’s and R’s scores?
Correct
S’s score = 63 + 30 = 93
P’s score = 93 – 15 = 78
Sum of Q’s and R’s scores
= 3 x 63 – 78 = 189 – 78 = 111Incorrect
S’s score = 63 + 30 = 93
P’s score = 93 – 15 = 78
Sum of Q’s and R’s scores
= 3 x 63 – 78 = 189 – 78 = 111Unattempted
S’s score = 63 + 30 = 93
P’s score = 93 – 15 = 78
Sum of Q’s and R’s scores
= 3 x 63 – 78 = 189 – 78 = 111 -
Question 9 of 35
9. Question
1 pointsA and B together can do a piece of work in 12 days which B and C together can do in 16 days. After A has been working at it for 5 days, and B for 7 days, C takes up and finishes it alone in 13 days. In how many days C alone finish the complete work?
Correct
AB ……….12……………………4
. LCM48
BC…………16……………………3
A=5days
B=7days(5+2)
C=13days(2+11)
1st AB 5 days 5*4=20work
BC 2days*3=6work
20+6=26work completed. Remaining 22work finished by C in 11days
Then 1day 2 work C finish
48 work =24 days.Incorrect
AB ……….12……………………4
. LCM48
BC…………16……………………3
A=5days
B=7days(5+2)
C=13days(2+11)
1st AB 5 days 5*4=20work
BC 2days*3=6work
20+6=26work completed. Remaining 22work finished by C in 11days
Then 1day 2 work C finish
48 work =24 days.Unattempted
AB ……….12……………………4
. LCM48
BC…………16……………………3
A=5days
B=7days(5+2)
C=13days(2+11)
1st AB 5 days 5*4=20work
BC 2days*3=6work
20+6=26work completed. Remaining 22work finished by C in 11days
Then 1day 2 work C finish
48 work =24 days. -
Question 10 of 35
10. Question
1 pointsDivide Rs. 3364 between A and B respectively, so that A’s Share at the end of 5 years may equal to B’s share at the end of 7 years, compound interest being at 5 percent.
Correct
A’s share after 5 yrs = B’s share after 7yrs
(1+5/100)5 =(1+5/100)7
A/B=(1+5/100) 7-5
=(1+5/100)2
=(21/22) 2=441/400
A’s share : B’s share =441 : 400
A’s 3364* 441/(441+400)=Rs1764.
B’s 3364-1764=Rs1600.Incorrect
A’s share after 5 yrs = B’s share after 7yrs
(1+5/100)5 =(1+5/100)7
A/B=(1+5/100) 7-5
=(1+5/100)2
=(21/22) 2=441/400
A’s share : B’s share =441 : 400
A’s 3364* 441/(441+400)=Rs1764.
B’s 3364-1764=Rs1600.Unattempted
A’s share after 5 yrs = B’s share after 7yrs
(1+5/100)5 =(1+5/100)7
A/B=(1+5/100) 7-5
=(1+5/100)2
=(21/22) 2=441/400
A’s share : B’s share =441 : 400
A’s 3364* 441/(441+400)=Rs1764.
B’s 3364-1764=Rs1600. -
Question 11 of 35
11. Question
1 pointsDirections (11-15): The following number series are based on a certain pattern. Identify the next number in series marked by (?) and mark your answer accordingly.
1.4, 2.6, 4.3, 6.6, 9.6, ?
Correct
……….+1.2 ……..+1.7………..+2.3………….+3.0………..+3.8
………………+0.5…….+0.6…………+0.7…………..+0.8Incorrect
……….+1.2 ……..+1.7………..+2.3………….+3.0………..+3.8
………………+0.5…….+0.6…………+0.7…………..+0.8Unattempted
……….+1.2 ……..+1.7………..+2.3………….+3.0………..+3.8
………………+0.5…….+0.6…………+0.7…………..+0.8 -
Question 12 of 35
12. Question
1 pointsDirections (11-15): The following number series are based on a certain pattern. Identify the next number in series marked by (?) and mark your answer accordingly.
98, 94, 101, 89, 108, ?
Correct
… -4…..+7…….-12……+19…..-28
…….+3…….+5…….+7…….+9Incorrect
… -4…..+7…….-12……+19…..-28
…….+3…….+5…….+7…….+9Unattempted
… -4…..+7…….-12……+19…..-28
…….+3…….+5…….+7…….+9 -
Question 13 of 35
13. Question
1 pointsDirections (11-15): The following number series are based on a certain pattern. Identify the next number in series marked by (?) and mark your answer accordingly.
10, 6, 8, 16, 40, ?
Correct
*0.5 + 1, *1 + 2, *1.5 + 4, *2 + 8, *2.5 + 16
Incorrect
*0.5 + 1, *1 + 2, *1.5 + 4, *2 + 8, *2.5 + 16
Unattempted
*0.5 + 1, *1 + 2, *1.5 + 4, *2 + 8, *2.5 + 16
-
Question 14 of 35
14. Question
1 pointsDirections (11-15): The following number series are based on a certain pattern. Identify the next number in series marked by (?) and mark your answer accordingly.
6, 7, 13, 40, ?, 796
Correct
*1 + 1, *2 – 1, *3 + 1, *4 – 1, *5 + 1
Incorrect
*1 + 1, *2 – 1, *3 + 1, *4 – 1, *5 + 1
Unattempted
*1 + 1, *2 – 1, *3 + 1, *4 – 1, *5 + 1
-
Question 15 of 35
15. Question
1 pointsDirections (11-15): The following number series are based on a certain pattern. Identify the next number in series marked by (?) and mark your answer accordingly.
54, 38, 16, 57, 70, ?
Correct
*0.5 + 11, *1 – 22, *1.5 + 33, *2 – 44, *2.5 + 55
Incorrect
*0.5 + 11, *1 – 22, *1.5 + 33, *2 – 44, *2.5 + 55
Unattempted
*0.5 + 11, *1 – 22, *1.5 + 33, *2 – 44, *2.5 + 55
-
Question 16 of 35
16. Question
1 pointsDirections (16-21): What approximate value will come in place of x in the following questions? (You are not expected to calculate the exact value)
49.89 % of 1999.91 – 28.98% of 3499.99 = ?
Correct
50 % of 2000 – 29% of 3500 = 1000 – 1015 = -15
Incorrect
50 % of 2000 – 29% of 3500 = 1000 – 1015 = -15
Unattempted
50 % of 2000 – 29% of 3500 = 1000 – 1015 = -15
-
Question 17 of 35
17. Question
1 pointsDirections (16-21): What approximate value will come in place of x in the following questions? (You are not expected to calculate the exact value)
(5/8) * 5665 + (2/11) * 6460 = x
Correct
= 5 * 708 + 2 * 587
= 3540 + 1174 = 4714Incorrect
= 5 * 708 + 2 * 587
= 3540 + 1174 = 4714Unattempted
= 5 * 708 + 2 * 587
= 3540 + 1174 = 4714 -
Question 18 of 35
18. Question
1 pointsDirections (16-21): What approximate value will come in place of x in the following questions? (You are not expected to calculate the exact value)
√8465 – 48.09% of 349.99 + 75.93% of 250.09 = x
Correct
Incorrect
Unattempted
-
Question 19 of 35
19. Question
1 pointsDirections (16-21): What approximate value will come in place of x in the following questions? (You are not expected to calculate the exact value)
18.09% of 649.99 – 945 ÷ 16 + 456.23 = x
Correct
Incorrect
Unattempted
-
Question 20 of 35
20. Question
1 pointsDirections (16-21): What approximate value will come in place of x in the following questions? (You are not expected to calculate the exact value)
√(36.01 × 40.98 – 24% of 750.09) = x
Correct
Incorrect
Unattempted
-
Question 21 of 35
21. Question
1 pointsDirections (16-21): What approximate value will come in place of x in the following questions? (You are not expected to calculate the exact value)
18.09 × 14.87 – 14 × 13 = x
Correct
Incorrect
Unattempted
-
Question 22 of 35
22. Question
1 pointsDirections (22- 26): Study the following chart carefully and answer the questions that follow:
The chart shows the number of students in six 6 classes of 2 different schools ABC and XYZ.
What is the difference between the students of class II and IV in school ABC and the students of class I and V in school XYZ?
Correct
Explanation:
II and IV in ABC = 280+620 = 900
I and V in XYZ = 320+660 = 980Incorrect
Explanation:
II and IV in ABC = 280+620 = 900
I and V in XYZ = 320+660 = 980Unattempted
Explanation:
II and IV in ABC = 280+620 = 900
I and V in XYZ = 320+660 = 980 -
Question 23 of 35
23. Question
1 pointsDirections (22- 26): Study the following chart carefully and answer the questions that follow:
The chart shows the number of students in six 6 classes of 2 different schools ABC and XYZ.What is the ratio of number of students in classes I and IV in school ABC to number of students in classes II and VI in school XYZ?
Correct
Explanation:
24+62 : 36+74
86 : 110
43: 55Incorrect
Explanation:
24+62 : 36+74
86 : 110
43: 55Unattempted
Explanation:
24+62 : 36+74
86 : 110
43: 55 -
Question 24 of 35
24. Question
1 pointsDirections (22- 26): Study the following chart carefully and answer the questions that follow:
The chart shows the number of students in six 6 classes of 2 different schools ABC and XYZ.Students in school ABC are approximately what percent lesser than students in school XYZ?
Correct
Explanation:
In ABC = 2280
In XYZ = 2920
Required % = (2920-2280)/2920 * 100Incorrect
Explanation:
In ABC = 2280
In XYZ = 2920
Required % = (2920-2280)/2920 * 100Unattempted
Explanation:
In ABC = 2280
In XYZ = 2920
Required % = (2920-2280)/2920 * 100 -
Question 25 of 35
25. Question
1 pointsDirections (22- 26): Study the following chart carefully and answer the questions that follow:
The chart shows the number of students in six 6 classes of 2 different schools ABC and XYZ.If from school ABC, 5% and 10% of students of classes IV and I respectively gets shifted to same respective classes in school XYZ, then find the average number of students in classes I and IV in school XYZ.
Correct
Explanation:
From D = 5/100 * 620 = 31
From A = 10/100 * 240 = 24
So now in A and D in XYZ = 320+24 + 560+31 = 935
So average = 935/2 = 467.5Incorrect
Explanation:
From D = 5/100 * 620 = 31
From A = 10/100 * 240 = 24
So now in A and D in XYZ = 320+24 + 560+31 = 935
So average = 935/2 = 467.5Unattempted
Explanation:
From D = 5/100 * 620 = 31
From A = 10/100 * 240 = 24
So now in A and D in XYZ = 320+24 + 560+31 = 935
So average = 935/2 = 467.5 -
Question 26 of 35
26. Question
1 pointsDirections (22- 26): Study the following chart carefully and answer the questions that follow:
The chart shows the number of students in six 6 classes of 2 different schools ABC and XYZ.Students in class V in school ABC is what percent of the number of students in classes II and III together in school XYZ?
Correct
Explanation:
440/(360+280) * 100Incorrect
Explanation:
440/(360+280) * 100Unattempted
Explanation:
440/(360+280) * 100 -
Question 27 of 35
27. Question
1 pointsA group of students prepared stuffed toys as part of their group activity. They spent Rs. 100 on velvet, Rs 5 on thread and needle and Rs. 27 on miscellaneous items. They made 30 toys, 50% of which were purchased by force by some senior students causing them a loss of 50%. At what % profit should they sell the remaining toys so as to gain 50% on their total cost?
Correct
CP of 1 toy= 100+5+27=Rs 132.
CP of 50toy =132*50
SP of 25 toy = 132*25/2
Required %ge is
135*25/2 + (100+x/100) * (25*132) = 150/100*132*50
1650+3300+33x= 9900
33x=4950
x=150%Incorrect
CP of 1 toy= 100+5+27=Rs 132.
CP of 50toy =132*50
SP of 25 toy = 132*25/2
Required %ge is
135*25/2 + (100+x/100) * (25*132) = 150/100*132*50
1650+3300+33x= 9900
33x=4950
x=150%Unattempted
CP of 1 toy= 100+5+27=Rs 132.
CP of 50toy =132*50
SP of 25 toy = 132*25/2
Required %ge is
135*25/2 + (100+x/100) * (25*132) = 150/100*132*50
1650+3300+33x= 9900
33x=4950
x=150% -
Question 28 of 35
28. Question
1 pointsThe circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel?
Correct
The circumference of the front wheel is 30 ft and that of the rear wheel is 36 feet.
Let the rear wheel make n revolutions. At this time, the front wheel should have made n+5 revolutions.
As both the wheels would have covered the same distance, n*36 = (n+5)*30
36n = 30n + 150
6n = 150
n = 25.
Distance covered = 25*36 = 900 ft.Incorrect
The circumference of the front wheel is 30 ft and that of the rear wheel is 36 feet.
Let the rear wheel make n revolutions. At this time, the front wheel should have made n+5 revolutions.
As both the wheels would have covered the same distance, n*36 = (n+5)*30
36n = 30n + 150
6n = 150
n = 25.
Distance covered = 25*36 = 900 ft.Unattempted
The circumference of the front wheel is 30 ft and that of the rear wheel is 36 feet.
Let the rear wheel make n revolutions. At this time, the front wheel should have made n+5 revolutions.
As both the wheels would have covered the same distance, n*36 = (n+5)*30
36n = 30n + 150
6n = 150
n = 25.
Distance covered = 25*36 = 900 ft. -
Question 29 of 35
29. Question
1 pointsA can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
Correct
Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively
Quantity of A in mixture left= 7x-7/12*9=7x-21/4litre.
Quantity of B in mixture left= 5x-5/12*9=5x-15/4litre.
(7x-21/4)/( 5x-15/4+9) = 7/9.
28x-21/20x+21=7/9
252x-189=140x+147
X=3.
So, the can contained 21 litres of AIncorrect
Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively
Quantity of A in mixture left= 7x-7/12*9=7x-21/4litre.
Quantity of B in mixture left= 5x-5/12*9=5x-15/4litre.
(7x-21/4)/( 5x-15/4+9) = 7/9.
28x-21/20x+21=7/9
252x-189=140x+147
X=3.
So, the can contained 21 litres of AUnattempted
Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively
Quantity of A in mixture left= 7x-7/12*9=7x-21/4litre.
Quantity of B in mixture left= 5x-5/12*9=5x-15/4litre.
(7x-21/4)/( 5x-15/4+9) = 7/9.
28x-21/20x+21=7/9
252x-189=140x+147
X=3.
So, the can contained 21 litres of A -
Question 30 of 35
30. Question
1 pointsRamya had to do a multiplication. Instead of taking 35 as one of the multipliers, she took 53. As a result, the product went up by 540. What is the new product?
Correct
Let the number that Ramya wanted to multiply be ‘X’.
She was expected to find the value of 35X.
Instead, she found the value of 53X.
The difference between them is 540.
i.e., 53X – 35X = 540
or (53 – 35) * X = 540
X = 30
Therefore, the correct product = 53 * 30 = 1590Incorrect
Let the number that Ramya wanted to multiply be ‘X’.
She was expected to find the value of 35X.
Instead, she found the value of 53X.
The difference between them is 540.
i.e., 53X – 35X = 540
or (53 – 35) * X = 540
X = 30
Therefore, the correct product = 53 * 30 = 1590Unattempted
Let the number that Ramya wanted to multiply be ‘X’.
She was expected to find the value of 35X.
Instead, she found the value of 53X.
The difference between them is 540.
i.e., 53X – 35X = 540
or (53 – 35) * X = 540
X = 30
Therefore, the correct product = 53 * 30 = 1590 -
Question 31 of 35
31. Question
1 points5 years ago, sister’s age was 5 times the age of her brother and the sum of present ages of sister and brother is 34 years. What will be the age of her brother after 6 years?
Correct
(34 – x) – 5 = 5 (x – 5)
34 – x – 5 = 5x – 25
5x + x = 34 – 5 +25
6x = 54
x = 9
Future age (after 6 yrs) = (x + 6) = (9 + 6) = 15 yearsIncorrect
(34 – x) – 5 = 5 (x – 5)
34 – x – 5 = 5x – 25
5x + x = 34 – 5 +25
6x = 54
x = 9
Future age (after 6 yrs) = (x + 6) = (9 + 6) = 15 yearsUnattempted
(34 – x) – 5 = 5 (x – 5)
34 – x – 5 = 5x – 25
5x + x = 34 – 5 +25
6x = 54
x = 9
Future age (after 6 yrs) = (x + 6) = (9 + 6) = 15 years -
Question 32 of 35
32. Question
1 pointsDirections (32-35): What value will come in place of x in following questions?
√6561 + 12 × 29 – 1248 ÷ 13 = x
Correct
Incorrect
Unattempted
-
Question 33 of 35
33. Question
1 pointsDirections (32-35): What value will come in place of x in following questions?
2 (1/3) + 4 (2/5) – 5 (4/15) = x
Correct
Incorrect
Unattempted
-
Question 34 of 35
34. Question
1 pointsDirections (32-35): What value will come in place of x in following questions?
√x % of 350 + 52% of 450 – 391 = 130
Correct
Incorrect
Unattempted
-
Question 35 of 35
35. Question
1 pointsDirections (32-35): What value will come in place of x in following questions?
32% of x – 204 – 546 ÷ 14 = -35
Correct
Incorrect
Unattempted
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mam 35th qustn ans wrong..its should be 650..thank u.!
@shubra mam check q 35
how to solve q no 2 ??
53^2 – 65% of 1380 – 948 ÷ x = 1833
2809 – 897 – (948 ÷ x) = 1833
2809 – 897 – 1833 = (948 ÷ x)
79 = 948 ÷ x
x = 948 ÷ 79 = 12
thanku mam or sir provide more sectional test like this
You have reached 10 of 35 points, (28.57%)
:((
mod mam??
yes ?
18.09 × 14.87 – 14 × 13 = x
mam ans should be 96 naa??
18*15 – 14*13 = 270 – 182 = 88
ohhh my mistake..tq mam…silly mistake 🙁
after approximtaion
18*15 = 278
mam i got only 10 marks in 22 min,,,,,,m vry tensed,,,,,:(
You should choose questions first. The ones which seem to be easy should be solved first.
Like u could have solved DI, number series, simplifications (which carry less calculation), and then others
thank you mam….
i will keep n mind nxt tym 🙂
16/16 thnx az:))
25/26
please check question no 6. it is impossible to go A to C in 8 hours Upstream. Please check
AC down 4 hour, AC Up 8 hour.
Speed of down , up 8 , 4.
speed of boat 8+ 4/2 = 6
speed of river 8-4/2 = 2
boat : river = 3:1
It is my try.