# Quant Test for IBPS PO Prelims Exam set – 3

1. A starts a business with Rs 20,000 and after 4 months B also joins with some capital. After a year, the profit is divided between them in the ratio 5 : 3. How much did B invested?
16,000
15,000
18,000
12,000
17,000
Option C
Let B invests Rs x, then ratio of their profits
20000*12 : x*8 = 30,000 : x
So, 30,000/x = 5/3
x = 18,000

2. In a business, A in invests 1/4th of the total capital for 1/4th of the time. B invests 1/5th of the total capital for half of the time and C invests the remaining capital for the whole time. What is the share of C in the total profit of Rs 7410?
5002
5720
5547
5834
5649
Option B
Let the whole time is 1.
A invests for 1/4, B invests for 1/2 and C for whole 1.
Contribution of C = 1 – (1/4 + 1/5) = 11/20
A’s share : B’s share : C’s share
1/4 * 1/4 : 1/5 * 1/2 : 11/20 * 1
1/16 : 1/10 : 11/20
5 : 8 : 44
Share of C in profit = 44/(5+8+44) * 7410 = 5720

3. The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is:
56.2
37.8
39.2
51.4
49.4
Option D
Let the required mean score be x.
Then, 20 * 80 + 25 * 31 + 55 * x = 52 * 100
1600 + 775 + 55x = 5200
55x = 2825
x = 51.4

4. A Cistern can be filled by an inlet pipe at the rate of 4 litres per minute. A leak in the bottom of a cistern can empty the full tank in 8 hours. When the cistern is full, the inlet is opened and due to the leak, the cistern is empty in 40 hours. How many litres does the cistern hold?
2500 litre
2700 litre
2100 litre
2000 litre
2400 litre
Option E
Part emptied by the leak in 1 hour = 1/8
part filled by (leak & inlet open) in 1 hour = 1/40
Part filled by the inlet pipe in 1 hour = 1/8 – 1/40 = 1/10
Inlet pipe fills the tank in = 10 hours
Inlet pipe fills water at the rate of 4 litres a minute.
Capacity of Cistern = 10 * 60 * 4 = 2400 litre

5. Two roads each 10m wide has been made running perpendicularly to each other inside a rectangular field of dimension 90m X 50m. What is the cost of spreading pebbles over them at the rate of Rs.8 per m².?
Rs.14400
Rs.10400
Rs.15300
Rs.11000
Rs.13700
Option B
Area of Roads = (l + b – w) * w
Area of Roads = (90 + 50 – 10) * 10 = 1300m²
Cost = 1300 * 8 = Rs.10400

6. Directions(6-10): Find the missing term ‘?’ of the following number series.

7. 6, 8, 16, 38, ?, 319
103
98
100
113
109
Option A
6 * 1 + 2 = 8
8* 1.5 + 4 = 16
16 * 2 + 6 = 38
38 * 2.5 + 8 = 103
103 * 3 + 10 = 319

8. 2,3,12,?,86,167
35
20
28
37
30
Option D
+1^2, +3^2, +5^2, +7^2, +9^2
? = 37

9. 107,123,155,?,267,347
200
202
203
210
212
Option C
+8*2
+8*4
+8*6
+8*8
+8*10
? = 203

10. 23,12,13,21,44,?
101.7
118.8
120.6
112.5
100.2
Option D
*0.5+0.5
*1+1
*1.5+1.5
*2+2
*2.5+2.5
? = 112.5

11. 5,16,37,?,109,160
50
68
60
55
66
Option B
+11, +21, +31, +41, +51
? = 68