Quant Test for IBPS PO Prelims Exam set – 3

  1. A starts a business with Rs 20,000 and after 4 months B also joins with some capital. After a year, the profit is divided between them in the ratio 5 : 3. How much did B invested?
    Option C
    Let B invests Rs x, then ratio of their profits
    20000*12 : x*8 = 30,000 : x
    So, 30,000/x = 5/3
    x = 18,000


  2. In a business, A in invests 1/4th of the total capital for 1/4th of the time. B invests 1/5th of the total capital for half of the time and C invests the remaining capital for the whole time. What is the share of C in the total profit of Rs 7410?
    Option B
    Let the whole time is 1.
    A invests for 1/4, B invests for 1/2 and C for whole 1.
    Contribution of C = 1 – (1/4 + 1/5) = 11/20
    A’s share : B’s share : C’s share
    1/4 * 1/4 : 1/5 * 1/2 : 11/20 * 1
    1/16 : 1/10 : 11/20
    5 : 8 : 44
    Share of C in profit = 44/(5+8+44) * 7410 = 5720


  3. The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is:
    Option D
    Let the required mean score be x.
    Then, 20 * 80 + 25 * 31 + 55 * x = 52 * 100
    1600 + 775 + 55x = 5200
    55x = 2825
    x = 51.4


  4. A Cistern can be filled by an inlet pipe at the rate of 4 litres per minute. A leak in the bottom of a cistern can empty the full tank in 8 hours. When the cistern is full, the inlet is opened and due to the leak, the cistern is empty in 40 hours. How many litres does the cistern hold?
    2500 litre
    2700 litre
    2100 litre
    2000 litre
    2400 litre
    Option E
    Part emptied by the leak in 1 hour = 1/8
    part filled by (leak & inlet open) in 1 hour = 1/40
    Part filled by the inlet pipe in 1 hour = 1/8 – 1/40 = 1/10
    Inlet pipe fills the tank in = 10 hours
    Inlet pipe fills water at the rate of 4 litres a minute.
    Capacity of Cistern = 10 * 60 * 4 = 2400 litre


  5. Two roads each 10m wide has been made running perpendicularly to each other inside a rectangular field of dimension 90m X 50m. What is the cost of spreading pebbles over them at the rate of Rs.8 per m².?
    Option B
    Area of Roads = (l + b – w) * w
    Area of Roads = (90 + 50 – 10) * 10 = 1300m²
    Cost = 1300 * 8 = Rs.10400


  6. Directions(6-10): Find the missing term ‘?’ of the following number series.

  7. 6, 8, 16, 38, ?, 319
    Option A
    6 * 1 + 2 = 8
    8* 1.5 + 4 = 16
    16 * 2 + 6 = 38
    38 * 2.5 + 8 = 103
    103 * 3 + 10 = 319


  8. 2,3,12,?,86,167
    Option D
    +1^2, +3^2, +5^2, +7^2, +9^2
    ? = 37


  9. 107,123,155,?,267,347
    Option C
    ? = 203


  10. 23,12,13,21,44,?
    Option D
    ? = 112.5


  11. 5,16,37,?,109,160
    Option B
    +11, +21, +31, +41, +51
    ? = 68


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