Quant Test for NIACL 2018 Prelim Exam Set – 4

Directions(1-5): What will come in place of question mark in the following questions.

1. 2418.065 + 88 ÷ 14.2 × 6 = ?
   2875
   2000
   2456
   2252
   2404
   Option C
   2418 + 88 ÷ 14 × 6 = ?
   => ? = 2418 + 6.3 × 6
   => ? = 2418 + 38
   => ? = 2456

    

2. (19.97% of 781) + ? + (30% of 87) = 252
   40
   70
   60
   80
   50
   Option B
   (19.97% of 781) + ? + (30% of 87) = 252
   => (20% of 780) + ? + (30 % of 87) = 252
   => 156 + ? + 26 = 252
   => 182 + ? = 252
   => ? = 252 – 182
   => ? = 70

    

3. ? × 1.3 × 6.5 = 1.17 × 24.7
   3.05
   2.15
   3.42
   4.44
   2.40
   Option C
   ? × 1.3 × 6.5 = 1.17 × 24.7
   => ? = (117×247)/(13×65×10) = 3.42

    

4. 55% of 320 + 30% of 1080 = 20 × ?
   10
   18
   25
   22
   30
   Option C
   55/100 × 320 + 30/100 × 1080 = 20 ×?
   => 176 + 324 = 20 × ?
   => ? = 500/20 = 25

    

5. 72% of 420 – 22% of 270 = ?
   278
   243
   255
   205
   222
   Option B
   72% of 420 – 22% of 270 = ?
   =>302.4 – 59.4 = ?
   =>? = 243

    

6. Annual salary of Arun is 7.68 lac. In a month if he spends 12000 on his children, 1/13th of rest on food and 8000 in mutual funds from his monthly salary, then find the monthly saving he is left with.
   55,000
   48,000
   40,000
   35,000
   52,000
   Option C
   Monthly salary = 7.68/12 Lacs = 64000
   Saving = Income – Expenditure
   = 64000 – 12000 – 4000 – 8000
   = 40,000

    

7. Two different amounts are invested in two schemes. In scheme A, amount X is invested at 8 % per annum and in scheme B amount (X+1400) is invested at 12% per annum.After 2 years difference between both interests is 880, then find value of X?
   7400
   6800
   5400
   7800
   6600
   Option B
   In scheme A Interest = (X×8×2)/100
   In scheme B Interest =[(X + 1400)×12×2]/100
   ATQ, [ (X + 1400)×12×2]/100 – [X×8×2]/ 100 = 880
   =>X = 6800

    

8. Ratio of speed of boat in down stream and speed of stream is 9:1, if speed of current is 3 km per hr, then find distance travelled(in km) upstream in 5 hours.
   75 km
   82 km
   98 km
   105 km
   110 km
   Option D
   speed of current = y = 3
   Down stream speed = 9 × 3 = 27 km/h
   Speed of boat = x => x + y = 27
   x = 24
   y= 3
   Distance travelled upstream in 5 hr = speed × Time
   = (x – y) ×5 = (24 – 3) × 5
   = 21 × 5 = 105 km

    

9. Harshan took a loan at a rate of simple interest 7% in the year with an increase of 0.25% in each subsequent year. He paid interest of Rs. 4425 after 4 years. How much loan did he take?
   Rs. 20000
   Rs. 15000
   Rs. 25000
   Rs. 12500
   Rs. 10000
   Option B
   Total interest = Rs. 4425
   Rate = 7% and increasing by 0.25% every year
   Let total Loan Amount = P
   P = (4425 × 100)/( 7 × 1 + 7.25 × 1 + 7.5 × 1 + 7.75 × 1)
   = 442500/29.5
   = Rs. 15000

    

10. Chance that Sheela tells truth is 35% and for Ramesh is 75%. In what percent they likely to contradict each other in the same question?
    21/34
    27/31
    23/42
    22/43
    23/40
    Option E
    P(A) = 35/100 = 7/20 and P(B) = 75/100=3/4.
    Now, they are contradicting means one lies and other speaks truth.
    So, Probability = 7/20*1/4 + 13/20 * 3/4
    = 7/80 + 39/80
    = 46/80
    = 23/40