Directions(1-5): Find the odd one out of the following series.
- 78,90,110,144,182,233
9011018278144Option E
+4*3
+5*4
+6*5
+7*6
+8*7
140 should be in place of 144. - 4,6,10,16,23,34
64102316Option D
(1^2 – 2)+5
(2^2 – 3)+5
(3^2 – 4)+5
(4^2 – 5)+5
(5^2 – 6)+5
(6^2 – 7)+5
24 should be in place of 23. - 8,56,80,92,96,101
9288096101Option D
8+96/2
56+48/2
80+24/2
92+12/2
98+6/2
98 should be in place of 96. - 41,39,45,27,81,-69
45-69398141Option B
-2,+6,-18,+54,-162
-81 should be in place of -69. - 24,32,47,71,106,150
15047322471Option A
+(3^2 – 1)
+(4^2 – 1)
+(5^2 – 1)
+(6^2 – 1)
+(7^2 – 1)
154 should be in place of 150. - A company has 20 employees out of which “x” employees are clerks and rest are officers. Average salary of all the employees in a company is Rs. 5300. Salary of an officer in the company is 275% more than the salary of a clerk in the company. Find the salary of all the clerks together if the number of officers in the company is 50% more than the number of clerks in the company.
Rs.18000Rs.12500Rs.20000Rs.10000Rs.16000Option E
Number of officers in the company = 1.5x = 20 – x 2.5x = 20
=> x = 8
Let the salary of the clerk be Rs.y.
Salary of the officer = Rs.3.75y 8y + 3.75y * 12 = 2*5300
=> 8y + 45y = 106000
=> y = 2000
Salary of the clerk = 8*2000 = Rs.16000 - Ankita invested Rs.8000 in scheme A offering 20% compound interest for one and a half year compounded half yearly. She then invested the whole amount she has received in scheme B offering 15% simple interest for five years. Find the total amount received by her after six and a half years.
Rs.11,223Rs.12,010Rs.18,634Rs.15,250Rs.10,125Option C
Amount received by Ankita from scheme A = 8000*{1+20/(2*100)}^(1.5*2)
= 8000*1.1^3 = Rs.10648
Interest earned by Ankita from scheme B = 10648*5*0.15 = Rs.7986
Total amount received by her = Rs.18,634 - Present ages of P and Q are “4x+1” years and “5x-10” years resp. Present age of R is 70% more than the present age of Q. Find the age of R after 7 years if the present average age of P,Q and R is 38 years.
40 years44 years32 years58 years50 yearsOption D
Present age of R = 1.7*(5x – 10) = 8.5x – 17 years
Now,
4x + 1 + 5x – 10 + 8.5x – 17 = 3*38
=> x = 8
Present age of R = 8.5*8 – 17 = 51 years
Age of R after 7 years = 51+7 = 58 years - In an examination Ashok got 29% marks and failed by “x+28” marks. In the same examination Amar got 51% marks and thus was able to score “258 – x” marks above passing marks. Find the maximum marks of the examination.
10001250130015501478Option C
Let the maximum marks of the examination be y.
Marks scored by Ashok = 0.29y
Marks scored by Amar = 0.51y
Now, 0.29y +x+ 28 = 0.51y – 258 + x
=> y = 1300 - Height of the cylinder is 40% more than its radius. Find the curved surface area of the cylinder if the volume is 14175 cm^3.
1520 cm^21890 cm^21770 cm^21500 cm^21250 cm^2Option B
Radius of the cylinder be “r” cm.
Height = 1.4r cm
Volume of the cylinder = 3*r^2*1.4r = 14175
=> r^3 = 3375
=> r = 15 cm
Radius = 15 cm and height = 21 cm
CSA of the cylinder = 2*3*15*21 = 1890 cm^2
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