Quant Test for SBI PO 2018 Prelim Exam Set – 24

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

Directions(1-5): Find the relation between x and y and choose a correct option.

1. I. 3x² + 13x + 14 = 0
   II. 4y² + 9y + 2 = 0
   x>y
   y>=x
   x=y or relation cannot be established.
   y>x
   x>=y
   Option B
   I. 3x² + 13x + 14 = 0
   3x² + 13x + 14 = 0
   3x² + 6x + 7x + 14 = 0
   x = -7/3, -2
   II. 4y² + 9y + 2 = 0
   4y² + 9y + 2 = 0
   4y² + 8y + y + 2 = 0
   y = -2, -1/4
   x ≤ y

    

2. I. 16x² + 20x + 6 = 0
   II. 10y² + 38y + 24 = 0
   y>x
   x>=y
   x>y
   y>=x
   x=y or relation cannot be established.
   Option C
   I. 16x² + 20x + 6 = 0
   Divide both equations by 2
   8x² + 10x + 3 = 0
   8x² + 4x + 6x + 3 = 0
   x = -1/2, -3/4
   II. 10y² + 38y + 24 = 0
   5y² + 19y + 12 = 0
   5y² + 15y + 4y + 12 = 0
   y = -4, -4/5
   x > y

    

3. I. 3x² + 4x – 39 = 0
   II. 3y² – 5y – 78 = 0
   x=y or relation cannot be established.
   y>=x
   x>=y
   y>x
   x>y
   Option A
   I. 3x² + 4x – 39 = 0
   3x² + 4x – 39 = 0
   3x² – 9x + 13x – 39 = 0
   x = -13/3, 3
   II. 3y² – 5y – 78 = 0
   3y² – 5y – 78 = 0
   3y² – 18y + 13y – 78 = 0
   y = -13/3, 6
   x = y or relation cannot be established

    

4. I. 4x² + 19x + 21 = 0
   II. 2y² – 25y – 27 = 0
   y>=x
   x=y or relation cannot be established.
   y>x
   x>y
   x>=y
   Option C
   I. 4x² + 19x + 21 = 0
   4x² + 19x + 21 = 0
   4x² + 12x + 7x + 21 = 0
   x = -3, – 1.75
   II. 2y² – 25y – 27 = 0
   2y² – 25y – 27 = 0
   2y² – 27y + 2y – 27 = 0
   y = 13.5, -1
   x < y

    

5. I. x² – 6x – 91 = 0
   II. y² – 32y + 247 = 0
   x=y or relation cannot be established.
   x>y
   x>=y
   y>x
   y>=x
   Option E
   I. x² – 6x – 91 = 0
   x² – 13x + 7x – 91 = 0
   x = 13, -7
   II. y² – 32y + 247 = 0
   y² – 19y -13y + 247 = 0
   y = 19, 13
   x ≤ y

    

Directions(6-10): The bar graph shown below depicts the number of appeared candidates and passed candidates (in hundreds) in a test from seven different institutions.


6. What is the average number of candidates passed from all the institutions together ?
   500
   900
   600
   700
   400
   Option D
   Required average = 4900/7 = 700

    

7. From which institution is the difference between the appeared candidates and passed candidates the maximum ?
   D
   E
   A
   F
   C
   Option A
   Difference between the appeared and passed candidates from institution A = 1300 – 1200 = 100
   from B = 1400 – 1000 = 400
   from C = 700 – 300 = 400
   from D = 1200 – 400 = 800
   from E = 1500 – 1200 = 300
   from F = 600 – 400 = 200
   from G = 1100 – 500 = 600
   Hence, from the above calculation , it is institution D .

    

8. What is the respective ratio of the number of candidates who have failed from institution B to the number of candidates who have appeared from institution F ?
   4:7
   5:1
   1:9
   2:3
   3:4
   Option D
   The number of candidates who have failed from institution B = 400
   The number of candidates who have appeared from institution F = 600
   Required ratio = 2:3

    

9. The number of candidates passed from institutions C and E together is approximate what percent of the total number of candidates appeared from institutions A and E together ?
   60%
   54%
   75%
   55%
   57%
   Option E
   Required % = 1600/2800 * 100 = 57% approx.

    

10. What is the difference between the number of candidates appeared from institutes B,C,D and F together and candidates passed from institutions A,E and G together?
    900
    1000
    1200
    1500
    800
    Option B
    Total number of students appearing from B,C,D and F together = 39 hundred
    candidates passed from institutes A,E and G together = 29 hundred
    Required difference = 1000