Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.

**Directions(1-5):** Find the relation between x and y and choose a correct option.

- I. 3x
^{2}+ 13x + 14 = 0

II. 4y^{2}+ 9y + 2 = 0x>yy>=xx=y or relation cannot be established.y>xx>=yOption B

I. 3x^{2}+ 13x + 14 = 0

3x^{2}+ 13x + 14 = 0

3x^{2}+ 6x + 7x + 14 = 0

x = -7/3, -2

II. 4y^{2}+ 9y + 2 = 0

4y^{2}+ 9y + 2 = 0

4y^{2}+ 8y + y + 2 = 0

y = -2, -1/4

x ≤ y - I. 16x
^{2}+ 20x + 6 = 0

II. 10y^{2}+ 38y + 24 = 0y>xx>=yx>yy>=xx=y or relation cannot be established.Option C

I. 16x^{2}+ 20x + 6 = 0

Divide both equations by 2

8x^{2}+ 10x + 3 = 0

8x^{2}+ 4x + 6x + 3 = 0

x = -1/2, -3/4

II. 10y^{2}+ 38y + 24 = 0

5y^{2}+ 19y + 12 = 0

5y^{2}+ 15y + 4y + 12 = 0

y = -4, -4/5

x > y - I. 3x
^{2}+ 4x – 39 = 0

II. 3y^{2}– 5y – 78 = 0x=y or relation cannot be established.y>=xx>=yy>xx>yOption A

I. 3x^{2}+ 4x – 39 = 0

3x^{2}+ 4x – 39 = 0

3x^{2}– 9x + 13x – 39 = 0

x = -13/3, 3

II. 3y^{2}– 5y – 78 = 0

3y^{2}– 5y – 78 = 0

3y^{2}– 18y + 13y – 78 = 0

y = -13/3, 6

x = y or relation cannot be established - I. 4x
^{2}+ 19x + 21 = 0

II. 2y^{2}– 25y – 27 = 0y>=xx=y or relation cannot be established.y>xx>yx>=yOption C

I. 4x^{2}+ 19x + 21 = 0

4x^{2}+ 19x + 21 = 0

4x^{2}+ 12x + 7x + 21 = 0

x = -3, – 1.75

II. 2y^{2}– 25y – 27 = 0

2y^{2}– 25y – 27 = 0

2y^{2}– 27y + 2y – 27 = 0

y = 13.5, -1

x < y - I. x
^{2}– 6x – 91 = 0

II. y^{2}– 32y + 247 = 0x=y or relation cannot be established.x>yx>=yy>xy>=xOption E

I. x^{2}– 6x – 91 = 0

x^{2}– 13x + 7x – 91 = 0

x = 13, -7

II. y^{2}– 32y + 247 = 0

y^{2}– 19y -13y + 247 = 0

y = 19, 13

x ≤ y - What is the average number of candidates passed from all the institutions together ?
500900600700400Option D

Required average = 4900/7 = 700 - From which institution is the difference between the appeared candidates and passed candidates the maximum ?
DEAFCOption A

Difference between the appeared and passed candidates from institution A = 1300 – 1200 = 100

from B = 1400 – 1000 = 400

from C = 700 – 300 = 400

from D = 1200 – 400 = 800

from E = 1500 – 1200 = 300

from F = 600 – 400 = 200

from G = 1100 – 500 = 600

Hence, from the above calculation , it is institution D . - What is the respective ratio of the number of candidates who have failed from institution B to the number of candidates who have appeared from institution F ?
4:75:11:92:33:4Option D

The number of candidates who have failed from institution B = 400

The number of candidates who have appeared from institution F = 600

Required ratio = 2:3 - The number of candidates passed from institutions C and E together is approximate what percent of the total number of candidates appeared from institutions A and E together ?
60%54%75%55%57%Option E

Required % = 1600/2800 * 100 = 57% approx. - What is the difference between the number of candidates appeared from institutes B,C,D and F together and candidates passed from institutions A,E and G together?
900100012001500800Option B

Total number of students appearing from B,C,D and F together = 39 hundred

candidates passed from institutes A,E and G together = 29 hundred

Required difference = 1000

**Directions(6-10):** The bar graph shown below depicts the number of appeared candidates and passed candidates (in hundreds) in a test from seven different institutions.