Quant Test for SBI PO 2018 Prelim Exam Set – 24

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 


 

Directions(1-5): Find the relation between x and y and choose a correct option.

  1. I. 3x2 + 13x + 14 = 0
    II. 4y2 + 9y + 2 = 0

    x>y
    y>=x
    x=y or relation cannot be established.
    y>x
    x>=y
    Option B
    I. 3x2 + 13x + 14 = 0
    3x2 + 13x + 14 = 0
    3x2 + 6x + 7x + 14 = 0
    x = -7/3, -2
    II. 4y2 + 9y + 2 = 0
    4y2 + 9y + 2 = 0
    4y2 + 8y + y + 2 = 0
    y = -2, -1/4
    x ≤ y

     

  2. I. 16x2 + 20x + 6 = 0
    II. 10y2 + 38y + 24 = 0

    y>x
    x>=y
    x>y
    y>=x
    x=y or relation cannot be established.
    Option C
    I. 16x2 + 20x + 6 = 0
    Divide both equations by 2
    8x2 + 10x + 3 = 0
    8x2 + 4x + 6x + 3 = 0
    x = -1/2, -3/4
    II. 10y2 + 38y + 24 = 0
    5y2 + 19y + 12 = 0
    5y2 + 15y + 4y + 12 = 0
    y = -4, -4/5
    x > y

     

  3. I. 3x2 + 4x – 39 = 0
    II. 3y2 – 5y – 78 = 0

    x=y or relation cannot be established.
    y>=x
    x>=y
    y>x
    x>y
    Option A
    I. 3x2 + 4x – 39 = 0
    3x2 + 4x – 39 = 0
    3x2 – 9x + 13x – 39 = 0
    x = -13/3, 3
    II. 3y2 – 5y – 78 = 0
    3y2 – 5y – 78 = 0
    3y2 – 18y + 13y – 78 = 0
    y = -13/3, 6
    x = y or relation cannot be established

     

  4. I. 4x2 + 19x + 21 = 0
    II. 2y2 – 25y – 27 = 0

    y>=x
    x=y or relation cannot be established.
    y>x
    x>y
    x>=y
    Option C
    I. 4x2 + 19x + 21 = 0
    4x2 + 19x + 21 = 0
    4x2 + 12x + 7x + 21 = 0
    x = -3, – 1.75
    II. 2y2 – 25y – 27 = 0
    2y2 – 25y – 27 = 0
    2y2 – 27y + 2y – 27 = 0
    y = 13.5, -1
    x < y

     

  5. I. x2 – 6x – 91 = 0
    II. y2 – 32y + 247 = 0

    x=y or relation cannot be established.
    x>y
    x>=y
    y>x
    y>=x
    Option E
    I. x2 – 6x – 91 = 0
    x2 – 13x + 7x – 91 = 0
    x = 13, -7
    II. y2 – 32y + 247 = 0
    y2 – 19y -13y + 247 = 0
    y = 19, 13
    x ≤ y

     

  6. Directions(6-10): The bar graph shown below depicts the number of appeared candidates and passed candidates (in hundreds) in a test from seven different institutions.

  7. What is the average number of candidates passed from all the institutions together ?
    500
    900
    600
    700
    400
    Option D
    Required average = 4900/7 = 700

     

  8. From which institution is the difference between the appeared candidates and passed candidates the maximum ?
    D
    E
    A
    F
    C
    Option A
    Difference between the appeared and passed candidates from institution A = 1300 – 1200 = 100
    from B = 1400 – 1000 = 400
    from C = 700 – 300 = 400
    from D = 1200 – 400 = 800
    from E = 1500 – 1200 = 300
    from F = 600 – 400 = 200
    from G = 1100 – 500 = 600
    Hence, from the above calculation , it is institution D .

     

  9. What is the respective ratio of the number of candidates who have failed from institution B to the number of candidates who have appeared from institution F ?
    4:7
    5:1
    1:9
    2:3
    3:4
    Option D
    The number of candidates who have failed from institution B = 400
    The number of candidates who have appeared from institution F = 600
    Required ratio = 2:3

     

  10. The number of candidates passed from institutions C and E together is approximate what percent of the total number of candidates appeared from institutions A and E together ?
    60%
    54%
    75%
    55%
    57%
    Option E
    Required % = 1600/2800 * 100 = 57% approx.

     

  11. What is the difference between the number of candidates appeared from institutes B,C,D and F together and candidates passed from institutions A,E and G together?
    900
    1000
    1200
    1500
    800
    Option B
    Total number of students appearing from B,C,D and F together = 39 hundred
    candidates passed from institutes A,E and G together = 29 hundred
    Required difference = 1000

     


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