Quant Test for SBI PO 2018 Prelim Exam Set – 33

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

Directions(1-5): Find the relation between x and y and choose a correct option.

1. I. 4x + 7y = 209
   II. 12x – 14y = -38
   x>=y
   y>x
   x>y
   x=y or relation cannot be established.
   y>=x
   Option D
   I. 4x + 7y = 209
   II. 12x – 14y = -38
   By equation I × 2 + equation II,
   8x + 14y = 418
   12x -14y = -38
   20x = 380
   => x = 380/20 = 19
   From equation I, 4 × 19 + 7y = 209
   =>7y = 209 – 76 = 133
   => y = 133/7 = 19
   x=y

    

2. I. 10x² – 7x + 1 = 0
   II. 35y² – 12y + 1 = 0
   y>x
   y>=x
   x=y or relation cannot be established.
   x>=y
   x>y
   Option D
   I. 10x² – 7x + 1 = 0
   II. 35y² – 12y + 1 = 0
   I. 10x² – 7x + 1 = 0
   => 10x² – 5x – 2x + 1 = 0
   => 5x (2x – 1) – 1 (2x – 1) = 0
   => (5x – 1) (2x – 1) = 0
   => x = 1/5 or 1/2
   II. 35y² – 12y + 1 = 0
   => 35y² – 7y – 5y + 1 = 0
   =>7y (5y – 1) – 1 (5y – 1) = 0
   => (7y – 1) (5y – 1) = 0
   => y = 1/7 or 1/5
   x>= y

    

3. 1. 4x² – 32x + 63 = 0
   II. 2y² – 11y + 15 = 0
   y>=x
   x=y or relation cannot be established.
   x>=y
   y>x
   x>y
   Option E
   I. 4x² – 32x + 63 = 0
   II. 2y² – 11y + 15 = 0
   I. 4x² – 32x + 63 = 0
   => 4x² – 14x – 18x + 63 = 0
   => 2x (2x – 7) – 9 (2x – 7) = 0
   => (2x – 7) (2x – 9) = 0
   => x = 7/2 or 9/2
   II. 2y² – 11y + 15 = 0
   => 2y² – 6y – 5y + 15 = 0
   => 2y (y – 3) – 5 (y – 3) = 0
   => (y – 3) (2y – 5) = 0
   => y = 3 or 5/2
   x > y

    

4. I. 16x² + 20x + 6 = 0
   II. 10y² + 38y + 24 = 0
   y>x
   x>y
   y>=x
   x>=y
   x=y or relation cannot be established.
   Option B
   I. 16x² + 20x + 6 = 0
   II. 10y² + 38y + 24 = 0
   I. 16x² + 20x + 6 = 0
   => 8x² + 10x + 3 = 0
   =>8x² + 6x + 4x + 3 = 0
   =>2x (4x + 3) + 1 (4x + 3) = 0
   =>(2x + 1) (4x + 3) = 0
   =>x = -1/2 or -3/4
   II. 10y² + 38y + 24 = 0
   =>5y² + 19y + 12 = 0
   =>5y² + 15y + 4y + 12 = 0
   =>5y (y + 3) + 4 (y + 3) = 0
   =>(y + 3) (5y + 4) = 0 4
   =>y = -3 or -4/5
   x > y

    

5. I. 18x² + 18x + 4 = 0
   II. 12y² + 29y +14 = 0
   x=y or relation cannot be established.
   y>x
   x>=y
   x>y
   y>=x
   Option C
   I. 18x² + 18x + 4 = 0
   II. 12y² + 29y +14 = 0
   I. 18x² + 18x + 4 = 0
   => 9x² + 9x + 2 = 0
   =>9x² + 6x + 3x + 2 = 0
   => 3x (3x + 2) + 1 (3x + 2) = 0
   => (3x + 1) (3x + 2) = 0
   => x = – 1/3 or – 2/3
   II. 12y² + 29y + 14 = 0
   =>12y² + 21y + 8y + 14 = 0
   =>3y (4y + 7) + 2 (4y + 7) = 0
   => (3y + 2) (4y + 7) = 0
   => y = -2/3 or -7/4
   x >= y

    

Directions(6-10): Following pie-chart shows the percentage distribution of the total population of six different cities and the table shows the percentage of adult population in them.
(Population of City A = 1287000)


6. What is the total non – adult population of City F?
   123055
   157080
   152450
   145899
   112450
   Option B
   In City F, adult population is 72%.
   So, population of non-adults is 28%.
   Required answer
   = 5500000 × 10.2/100 * 28/100
   = 157080

    

7. What is the total adult population of City C?
   350246
   301250
   255000
   337260
   332500
   Option D
   Population of A = 1287000
   Total population of all six cities= 1287000/23.4 × 100
   = 5500000
   Adult population in C = 5500000 × 8.4/100 × 73/100
   = 337260

    

8. The total population of City A is approximately what percentage of the total population of City D?
   123.8%
   112.5%
   110.5%
   100%
   90%
   Option A
   A = 55 × 23.4/100 lakh
   D = 55 × 18.9/100 lakh
   Required % = 23.4/18.9 × l00
   = 123.8%

    

9. The total adult population of City B and C together is approximately what percentage of the total population of all six cities together?
   15%
   21%
   10%
   25%
   5%
   Option B
   Adult of city B and C
   = 5500000 * (21.6 × 68 + 8.4 × 73)/100*100
   = 550 × (1468.8 + 613.2) = 550 × 2082
   Total population of all six cities = 5500000
   Required % = 550 * 2082/5500000 *100
   = 20.82% = 21%

    

10. The total population of City D is approximately what percentage more than the total population of City E?
    10%
    5%
    8%
    6%
    4%
    Option D
    Total population of D = 18.9% of 55 lakh
    Total population of E = 17.9% of 55 lakh
    Required% = (18.9 – 17.9)/17.9 * 100
    = 100/17.9 = 5.58% = 6%(approx.)