Quant Test for SBI PO 2018 Prelim Exam Set – 33

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 


 

Directions(1-5): Find the relation between x and y and choose a correct option.

  1. I. 4x + 7y = 209
    II. 12x – 14y = -38

    x>=y
    y>x
    x>y
    x=y or relation cannot be established.
    y>=x
    Option D
    I. 4x + 7y = 209
    II. 12x – 14y = -38
    By equation I × 2 + equation II,
    8x + 14y = 418
    12x -14y = -38
    20x = 380
    => x = 380/20 = 19
    From equation I, 4 × 19 + 7y = 209
    =>7y = 209 – 76 = 133
    => y = 133/7 = 19
    x=y

     

  2. I. 10x2 – 7x + 1 = 0
    II. 35y2 – 12y + 1 = 0

    y>x
    y>=x
    x=y or relation cannot be established.
    x>=y
    x>y
    Option D
    I. 10x2 – 7x + 1 = 0
    II. 35y2 – 12y + 1 = 0
    I. 10x2 – 7x + 1 = 0
    => 10x2 – 5x – 2x + 1 = 0
    => 5x (2x – 1) – 1 (2x – 1) = 0
    => (5x – 1) (2x – 1) = 0
    => x = 1/5 or 1/2
    II. 35y2 – 12y + 1 = 0
    => 35y2 – 7y – 5y + 1 = 0
    =>7y (5y – 1) – 1 (5y – 1) = 0
    => (7y – 1) (5y – 1) = 0
    => y = 1/7 or 1/5
    x>= y

     

  3. 1. 4x2 – 32x + 63 = 0
    II. 2y2 – 11y + 15 = 0

    y>=x
    x=y or relation cannot be established.
    x>=y
    y>x
    x>y
    Option E
    I. 4x2 – 32x + 63 = 0
    II. 2y2 – 11y + 15 = 0
    I. 4x2 – 32x + 63 = 0
    => 4x2 – 14x – 18x + 63 = 0
    => 2x (2x – 7) – 9 (2x – 7) = 0
    => (2x – 7) (2x – 9) = 0
    => x = 7/2 or 9/2
    II. 2y2 – 11y + 15 = 0
    => 2y2 – 6y – 5y + 15 = 0
    => 2y (y – 3) – 5 (y – 3) = 0
    => (y – 3) (2y – 5) = 0
    => y = 3 or 5/2
    x > y

     

  4. I. 16x2 + 20x + 6 = 0
    II. 10y2 + 38y + 24 = 0

    y>x
    x>y
    y>=x
    x>=y
    x=y or relation cannot be established.
    Option B
    I. 16x2 + 20x + 6 = 0
    II. 10y2 + 38y + 24 = 0
    I. 16x2 + 20x + 6 = 0
    => 8x2 + 10x + 3 = 0
    =>8x2 + 6x + 4x + 3 = 0
    =>2x (4x + 3) + 1 (4x + 3) = 0
    =>(2x + 1) (4x + 3) = 0
    =>x = -1/2 or -3/4
    II. 10y2 + 38y + 24 = 0
    =>5y2 + 19y + 12 = 0
    =>5y2 + 15y + 4y + 12 = 0
    =>5y (y + 3) + 4 (y + 3) = 0
    =>(y + 3) (5y + 4) = 0 4
    =>y = -3 or -4/5
    x > y

     

  5. I. 18x2 + 18x + 4 = 0
    II. 12y2 + 29y +14 = 0

    x=y or relation cannot be established.
    y>x
    x>=y
    x>y
    y>=x
    Option C
    I. 18x2 + 18x + 4 = 0
    II. 12y2 + 29y +14 = 0
    I. 18x2 + 18x + 4 = 0
    => 9x2 + 9x + 2 = 0
    =>9x2 + 6x + 3x + 2 = 0
    => 3x (3x + 2) + 1 (3x + 2) = 0
    => (3x + 1) (3x + 2) = 0
    => x = – 1/3 or – 2/3
    II. 12y2 + 29y + 14 = 0
    =>12y2 + 21y + 8y + 14 = 0
    =>3y (4y + 7) + 2 (4y + 7) = 0
    => (3y + 2) (4y + 7) = 0
    => y = -2/3 or -7/4
    x >= y

     

  6. Directions(6-10): Following pie-chart shows the percentage distribution of the total population of six different cities and the table shows the percentage of adult population in them.
    (Population of City A = 1287000)

  7. What is the total non – adult population of City F?
    123055
    157080
    152450
    145899
    112450
    Option B
    In City F, adult population is 72%.
    So, population of non-adults is 28%.
    Required answer
    = 5500000 × 10.2/100 * 28/100
    = 157080

     

  8. What is the total adult population of City C?
    350246
    301250
    255000
    337260
    332500
    Option D
    Population of A = 1287000
    Total population of all six cities= 1287000/23.4 × 100
    = 5500000
    Adult population in C = 5500000 × 8.4/100 × 73/100
    = 337260

     

  9. The total population of City A is approximately what percentage of the total population of City D?
    123.8%
    112.5%
    110.5%
    100%
    90%
    Option A
    A = 55 × 23.4/100 lakh
    D = 55 × 18.9/100 lakh
    Required % = 23.4/18.9 × l00
    = 123.8%

     

  10. The total adult population of City B and C together is approximately what percentage of the total population of all six cities together?
    15%
    21%
    10%
    25%
    5%
    Option B
    Adult of city B and C
    = 5500000 * (21.6 × 68 + 8.4 × 73)/100*100
    = 550 × (1468.8 + 613.2) = 550 × 2082
    Total population of all six cities = 5500000
    Required % = 550 * 2082/5500000 *100
    = 20.82% = 21%

     

  11. The total population of City D is approximately what percentage more than the total population of City E?
    10%
    5%
    8%
    6%
    4%
    Option D
    Total population of D = 18.9% of 55 lakh
    Total population of E = 17.9% of 55 lakh
    Required% = (18.9 – 17.9)/17.9 * 100
    = 100/17.9 = 5.58% = 6%(approx.)

     


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