Hello Aspirants

**State Bank of India (SBI)** is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled onÂ **1st, 7th & 8th of July 2018. **Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam.Â

**Directions(1-5):** Find the relation between x and y and choose a correct option.

- I. 4x + 7y = 209

II. 12x – 14y = -38x>=yy>xx>yx=y or relation cannot be established.y>=xOption D

I. 4x + 7y = 209

II. 12x – 14y = -38

By equation I Ã— 2 + equation II,

8x + 14y = 418

12x -14y = -38

20x = 380

=> x = 380/20 = 19

From equation I, 4 Ã— 19 + 7y = 209

=>7y = 209 – 76 = 133

=> y = 133/7 = 19

x=y - I. 10x
^{2}– 7x + 1 = 0

II. 35y^{2}– 12y + 1 = 0y>xy>=xx=y or relation cannot be established.x>=yx>yOption D

I. 10x^{2}– 7x + 1 = 0

II. 35y^{2}– 12y + 1 = 0

I. 10x^{2}– 7x + 1 = 0

=> 10x^{2}– 5x – 2x + 1 = 0

=> 5x (2x – 1) – 1 (2x – 1) = 0

=> (5x – 1) (2x – 1) = 0

=> x = 1/5 or 1/2

II. 35y^{2}– 12y + 1 = 0

=> 35y^{2}– 7y – 5y + 1 = 0

=>7y (5y – 1) – 1 (5y – 1) = 0

=> (7y – 1) (5y – 1) = 0

=> y = 1/7 or 1/5

x>= y - 1. 4x
^{2}– 32x + 63 = 0

II. 2y^{2}– 11y + 15 = 0y>=xx=y or relation cannot be established.x>=yy>xx>yOption E

I. 4x^{2}– 32x + 63 = 0

II. 2y^{2}– 11y + 15 = 0

I. 4x^{2}– 32x + 63 = 0

=> 4x^{2}– 14x – 18x + 63 = 0

=> 2x (2x – 7) – 9 (2x – 7) = 0

=> (2x – 7) (2x – 9) = 0

=> x = 7/2 or 9/2

II. 2y^{2}– 11y + 15 = 0

=> 2y^{2}– 6y – 5y + 15 = 0

=> 2y (y – 3) – 5 (y – 3) = 0

=> (y – 3) (2y – 5) = 0

=> y = 3 or 5/2

x > y - I. 16x
^{2}+ 20x + 6 = 0

II. 10y^{2}+ 38y + 24 = 0y>xx>yy>=xx>=yx=y or relation cannot be established.Option B

I. 16x^{2}+ 20x + 6 = 0

II. 10y^{2}+ 38y + 24 = 0

I. 16x^{2}+ 20x + 6 = 0

=> 8x^{2}+ 10x + 3 = 0

=>8x^{2}+ 6x + 4x + 3 = 0

=>2x (4x + 3) + 1 (4x + 3) = 0

=>(2x + 1) (4x + 3) = 0

=>x = -1/2 or -3/4

II. 10y^{2}+ 38y + 24 = 0

=>5y^{2}+ 19y + 12 = 0

=>5y^{2}+ 15y + 4y + 12 = 0

=>5y (y + 3) + 4 (y + 3) = 0

=>(y + 3) (5y + 4) = 0 4

=>y = -3 or -4/5

x > y - I. 18x
^{2}+ 18x + 4 = 0

II. 12y^{2}+ 29y +14 = 0x=y or relation cannot be established.y>xx>=yx>yy>=xOption C

I. 18x^{2}+ 18x + 4 = 0

II. 12y^{2}+ 29y +14 = 0

I. 18x^{2}+ 18x + 4 = 0

=> 9x^{2}+ 9x + 2 = 0

=>9x^{2}+ 6x + 3x + 2 = 0

=> 3x (3x + 2) + 1 (3x + 2) = 0

=> (3x + 1) (3x + 2) = 0

=> x = – 1/3 or – 2/3

II. 12y^{2}+ 29y + 14 = 0

=>12y^{2}+ 21y + 8y + 14 = 0

=>3y (4y + 7) + 2 (4y + 7) = 0

=> (3y + 2) (4y + 7) = 0

=> y = -2/3 or -7/4

x >= y - What is the total non – adult population of City F?
123055157080152450145899112450Option B

In City F, adult population is 72%.

So, population of non-adults is 28%.

Required answer

= 5500000 Ã— 10.2/100 * 28/100

= 157080 - What is the total adult population of City C?
350246301250255000337260332500Option D

Population of A = 1287000

Total population of all six cities= 1287000/23.4 Ã— 100

= 5500000

Adult population in C = 5500000 Ã— 8.4/100 Ã— 73/100

= 337260 - The total population of City A is approximately what percentage of the total population of City D?
123.8%112.5%110.5%100%90%Option A

A = 55 Ã— 23.4/100 lakh

D = 55 Ã— 18.9/100 lakh

Required % = 23.4/18.9 Ã— l00

= 123.8% - The total adult population of City B and C together is approximately what percentage of the total population of all six cities together?
15%21%10%25%5%Option B

Adult of city B and C

= 5500000 * (21.6 Ã— 68 + 8.4 Ã— 73)/100*100

= 550 Ã— (1468.8 + 613.2) = 550 Ã— 2082

Total population of all six cities = 5500000

Required % = 550 * 2082/5500000 *100

= 20.82% = 21% - The total population of City D is approximately what percentage more than the total population of City E?
10%5%8%6%4%Option D

Total population of D = 18.9% of 55 lakh

Total population of E = 17.9% of 55 lakh

Required% = (18.9 – 17.9)/17.9 * 100

= 100/17.9 = 5.58% = 6%(approx.)

**Directions(6-10):** Following pie-chart shows the percentage distribution of the total population of six different cities and the table shows the percentage of adult population in them.

(Population of City A = 1287000)

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