**Directions(1-5): **Find the missing term ‘?’ of the following series.

- 17, 52, 158, 477, ?, 4310
13301200143515451660Option C

17 × 3 + 1 = 51 + 1 = 52

52 × 3 + 2 = 156 + 2 = 158

158 × 3 + 3 = 474 + 3 = 477

477 × 3 + 4 = 1431 + 4 = 1435 - 3, 22, ?, 673, 2696, 8093
110134122150142Option B

3 × 7 + 1 = 21 + 1= 22

22 × 6 + 2 = 132 + 2 = 134

134 × 5 + 3 = 670 + 3 = 673

673 × 4 + 4 = 2692 + 4 = 2696 - 6, 13, 38, ?, 532, 2675
124144111132129Option E

6 × 1 + 1 × 7 = 6 + 7 = 13

13 × 2 + 2 × 6 = 26 + 12 = 38

38 × 3 + 3 × 5 = 114 + 15 = 129

129 × 4 + 4 × 4 = 516 + 16 = 532 - 286, 142, ?, 34, 16, 7
7485705466Option C

286/2 – 1 = 143 – 1 = 142

142/2 – l = 71 – l = 70

70/2 – 1 = 35 – 1 = 34

34/2 – 1 = 17- 1 = 16 - 17, 9, ? ,16.5, 35, 90
81061214Option B

17 × 0.5 + 0.5 = 9

9 × 1 + 1 = 10

10 × 1.5 + 1.5 = 16.5

16.5 × 2 + 2 = 35 - The average age of mother,father and son was 42 years at the time of the marriage of son. After one year, an infant was born in the family and after 6 years of the marriage of son, the average age of the family is 36 years. What was the age of the bride at the time of marriage?
18 years25 years14 years33 years21 yearsOption B

Sum of the present age of Mother, Father and Son = 42*3+6*3 = 144 years

Sum of present age of the family = 36*5 = 180

Present age of the bride = 180 – 144 – 5 = 31 years

Age of the bride at the time of marriage = 31 – 6 = 25 years - The total number of men, women and children working in a factory is 18. They earn Rs.4000 in a day. If the sum of the wages of all men, all women and all children is in the ratio of 18:10:12 and if the wages of an individual man , woman and child is in the ratio 6:5:3. How much a women earn in a day?
Rs.174Rs.155Rs.250Rs.189Rs.200Option C

Ratio of number of men, women and children

= 18/6:10/5:2/3 = 3x:2x:4x

Now, 3x+2x+4x = 18

=>x = 2

Number of women = 4

Share of all women = 10/40*4000 = Rs.1000

Share of each women = 1000/4 = Rs.250 - The interest earned on Rs.4800 at rate of R% compounded annually is Rs.1008 after 2 years. What would be the simple interest earned on the same amount at the rate of (R+5)% per annum after 3 years?
Rs.1995Rs.1774Rs.1845Rs.2160Rs.2000Option D

Equivalent interest rate for 2 years = (1008/4800)*100

= 21%

R% + R% + (R^2/100)% = 21%

=>R = 10

Required interest = 4800*(10+5)% *3 = Rs.2160 - Mahi bought a second-hand scanner and sold it to Kavi for Rs.2160 thereby making a profit of 20%. At what price Mahi must sell the printer to earn a profit of 40%?
Rs.2520Rs.2386Rs.2445Rs.2120Rs.2200Option A

CP of the scanner be x. x*1.2 = 2160

=>x = 1800

CP = Rs.1800

Required amount = 1800*1.4 = Rs.2520 - Tap A is 50% more efficient than Tap B. Both tap together can fill the tank in (96/5) hours. Find the time taken by tap A to fill the tank alone.
27 hours32 hours20 hours25 hours36 hoursOption B

Let the time taken by tap B to fill the tank be

x hours.

Time taken by tap A to fill the tank = x/1.5 hours

Now, 1/x+1/(x/1.5) = 1/(96/5)

=> 1+1.5 = 5x/96

=>x = 48

Time taken by tap A to fill the tank = 48/1.5 = 32 hours

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