Quant Test for SBI PO 2018 Prelim Exam Set – 49

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

Directions(1-5): What approximate value will come in place of question mark ‘?’ in the given questions.

1. [(18)^2 /4] + (? – 40) = 79.96
   20
   17
   39
   41
   28
   Option C
   [(18)^2 /4] + (? – 40) = 79.96
   => [324/4] + (?-40) = 80
   => 81 + ? – 40 = 80
   => ? = 39

    

2. 14.98% of 1100 – 6.03^2 – ? = 299.88
   -100
   -111
   -75
   -171
   -90
   Option D
   14.98% of 1100 – 6.03^2 – ? = 299.88
   => 15% of 1100 – 36 – ? = 300
   => 165 – 36 – ? =300
   => ? = -171

    

3. [1024.23 /3.82 + (12.02)^1.88 ]^1/2 * 13.21 = ?
   260
   200
   244
   201
   274
   Option A
   [1024.23 /3.82 + (12.02)^1.88 ]^1/2 * 13.21 = ?
   => [1024/4 + 144]^1/2 * 13.21 = ?
   => (256 + 144)^1/2 * 13 = ?
   => (400)^1/2 * 13 =?
   => ? = 20*13 = 260

    

4. 812.16 – 126.99 * 5.002 + 89.56*2.02 = ?
   357
   450
   354
   225
   466
   Option A
   812.16 – 126.99 * 5.002 + 89.56*2.02 = ?
   => 812 – 127*5 + 90*2 = ?
   => 812 – 635 + 180 = ?
   => ? = 357

    

5. [33.89 * 20.01 + (527.92)^1/2 – (14.88)^2.04]/[(25.02)^1.8 – 384.77] = ?
   3
   7
   4
   5
   2
   Option E
   [33.89 * 20.01 + (527.92)^1/2 – (14.88)^2.04]/[(25.02)^1.8 – 384.77] = ?
   => [34*20 + 23 – 225]/[625 – 385] => [680 + 23 – 225 ]/240
   => 2

    

Directions(6-10): The following pie-chart shows the percentage distribution of total
population of six cities, and the table shows the percentage of males among them.
(Total population of City F = 1526000).


6. What is the difference between the male and the female population of City B?
   45000
   42560
   38995
   33550
   49280
   Option E
   TotalB = 7000000 × 11/100 = 770000
   Males are 53.2%,
   so females = 100 – 53.2 = 46.8%
   Diff = 53.2 – 46.8 = 6.4%
   Required answer = 770000 × 6.4/100 = 49280

    

7. What is the total number of females in City A?
   746214
   588900
   775500
   655255
   828900
   Option A
   Total number of people in all six cities
   =1526000 * 100/21 = 7266666.67
   Total population of City A = 7266666.67 × 21/100 = 1526000
   MaleA = 1526000 × 51.1/100 = 779786
   FemaleA = 1470000 – 779786= 746214

    

8. What is the total number of males in all six cities together?
   5227455
   4555500
   3560078
   4478250
   3606820
   Option E
   Total males
   = 7000000/100*100 {21 × 51.1 + 11 × 53.2 + 24 × 52.9 + 15 × 53.8 + 7 × 47.9 + 22 × 49.2}
   = 700 {1073.1 + 585.2 + 1269.6 + 807 + 335.3 + 1082.4}
   = 700 × 5151.08 = 3606820

    

9. The female population of City F is approximately what percentage of the female population of City E?
   199.8%
   222.2%
   148.9%
   322.32%
   233.4%
   Option D
   FemaleE = 7000000 *7/100* (100 – 49.2)/100
   = 700 × 7 × 50.8 = 248920
   FemaleF = 7000000 *22/100* (100-47.9)/100
   = 700 × 22 × 52.1 = 802340
   Required % = 802340/248920 ×100 = 322.32%

    

10. The total number of females in all six cities together is what percentage of the total population of all six cities together? (Answer in approximate value)
    72.2%
    55.5%
    60.5%
    48.5%
    54.4%
    Option D
    Total population in all six cities = 7000000
    Total females in all six cities = 7000000 – 3606820 = 3393180
    Required % = 3393180/7000000*100
    = 48.474 == 48.5%