Quant Test for SBI PO 2018 Prelim Exam Set – 20

Hello Aspirants

State Bank of India (SBI) is going to conduct examination for its recruitment for the post of Probationary Officers (SBI PO 2018) for a total of 2000 vacancies.

Click here to know the details of the Examination

The examination will be held in three phases i.e. Preliminary Examination, Main Examination and Group Exercise & Interview. The Preliminary Exam is scheduled on 1st, 7th & 8th of July 2018. Details of the exam are as under:

Practice the questions so as to familiarize yourself with the pattern of questions to be asked in the exam. 

Directions(1-5): Find the relationship between x and y and choose a correct option accordingly.

1. I. 2x² – (2 + 2√5)x + 2√5 = 0
   II. 4y² – (6 + 2√2)y + 3√2 = 0
   x>y
   x>=y
   y>=x
   y>x
   x=y or relation cannot be established.
   Option E
   I. 2x² – (2 + 2√5)x + 2√5 = 0
   =>2x² – 2x – 2√5x + 2√5 = 0
   =>2x (x – 1) – 2√5 (x – 1) = 0
   x = 1, √5 (2.2)
   II. 4y² – (6 + 2√2)y + 3√2 = 0
   =>4y² – 6y – 2√2y + 3√2 = 0
   => 2y (2y – 3) – √2 (2y – 3) = 0
   y = 3/2, 1/√2 (0.7)
   x = y or relation cannot be established

    

2. I. 3x² + 22x + 24 = 0
   II. 3y² – 8y – 16 = 0
   y>=x
   y>x
   x>=y
   x>y
   x=y or relation cannot be established.
   Option A
   I. 3x² + 22x + 24 = 0
   =>3x² + 22 x + 24 = 0
   => 3x² + 18x + 4x + 24 = 0
   x = -4/3, -6
   II. 3y² – 8y – 16 = 0
   =>3y² – 8y – 16 = 0
   => 3y² – 12y + 4y – 16 = 0
   y = -4/3, 4 x ≤ y

    

3. I. 20x² – 31x + 12 = 0
   II. 3y² – 16y + 16 = 0
   y>x
   y>=x
   x>y
   x>=y
   x=y or relation cannot be established.
   Option A
   I. 20x² – 31x + 12 = 0
   =>20x² – 31x + 12 = 0
   =>20x² – 16x – 15x + 12 = 0
   x = 3/4, 4/5
   II. 3y² – 16y + 16 = 0
   =>3y² – 16y + 16 = 0
   =>3y² – 14y – 4y + 16 = 0
   y = 4, 4/3
   x < y

    

4. I. x² + √5x – 10 = 0
   II. 2y² + 9√5y + 50 = 0
   x>=y
   y>x
   y>=x
   x=y or relation cannot be established.
   x>y
   Option A
   I. x² + √5x – 10 = 0
   =>x² + √5x – 10 = 0
   =>x² + 2√5x – √5x – 10 = 0
   x = -2√5, √5
   II. 2y² + 9√5y + 50 = 0
   =>2y² + 9√5y + 50 = 0
   => 2y² + 4√5y + 5√5y + 50=0
   y = -2√5, -5√5/2
   x ≥ y

    

5. I. 8x² + 5x – 13 = 0
   II. 2y² + 23y + 63 = 0
   y>=x
   x>y
   x>=y
   y>x
   x=y or relation cannot be established.
   Option B
   I. 8x² + 5x – 13 = 0
   =>8x² + 5x – 13 = 0
   =>8x² + 13x – 8x – 13 = 0
   x = -1.625, 1
   II. 2y² + 23y + 63 = 0
   =>2y² + 23y + 63 = 0
   => 2y² + 14y + 9y + 63 = 0
   y = -7, -4.5
   x > y

    

Directions(6-10): Following pie-chart shows the percentage distribution of total items (Item A and Item B) produced by six companies (P,Q,R,S,T and U) and the table shows the ratio of A to B and percentage sale of A and B.
Total items = 16 lakh


6. What is the average number of A items sold by all six companies together?
   88500
   75080
   89680
   69950
   95000
   Option C
   A items sold by P = 16*(24/100)*(5/8)*(65/100)
   = 1.56 lakh
   Similarly,
   Total A items = 1.56 + 0.896 + 0.6912 + 1.44 + 0.4096 + 0.384
   = 5.3808 lakh
   Average = 5.3808/6
   = 0.8968 lakh
   = 89680

    

7. The number of items sold by Company P is what percentage of the number of A items sold by Company U?
   320.11%
   415.02%
   520.20%
   406.25%
   300.05%
   Option D
   A sold by P = 156000,
   A sold by U = 38400
   Reqd % = (156000/38400)*100
   = 406.25%

    

8. What is the difference between the total items produced by Company P and Q together and the total items produced by Company S?
   2.24 lakh
   3.23 lakh
   4.00 lakh
   3.52 lakh
   1.20 lakh
   Option A
   Total items = [(24+18) – 28]*16/100 = 2.24 lakh

    

9. What is the difference between the total number of A items and the total number of B items produced by Company U?
   15800
   34500
   15500
   25600
   26000
   Option D
   Total = 16 × (8/100) = 1.28 lakh,
   Item A = (1.28/5)* 3= 0.768
   Item B = (1.28/5)*2 = 0.512
   Diff = 0.768 – 0.512 = 0.256 lakh
   = 25600

    

10. What is the difference between the number of A items sold and the number of B items sold by Company T?
    12350 lakhs
    15600 lakhs
    32560 lakhs
    20000 lakhs
    14560 lakhs
    Option E
    Item A = 16*( 7/100)*( 4/7)* (64/100) = 0.4096
    Similary, Item B = 0.2640
    Diff = 0.4096 – 0.2640 = 0.1456 lakh
    = 14560 lakhs