Data Interpretation

New Pattern Data Interpretation Questions. SBI PO Mains chapter based Data Interpretation Questions – Time and Work, and Partnership.

Directions (1-5): The following table shows the number of days for which 4 individuals A, B, C and D worked on 5 different projects numbered 1 to 5. It also shows the part of respective project that could not be completed by individuals in time.
Some values are missing which are denoted by symbol (-). With the help of information in questions and table below answer the questions that follow.

New Pattern Data Interpretation Questions

  1. A and B started working on Project 1. They completed 1/3rd of work after which they left and C joined the project. C can complete the whole project in 12 days. After C worked for his assigned number of days, D joined the project and worked for his assigned number of days. Find the number of days in which D can complete the whole Project 1?
    A) 15 days
    B) 20 days
    C) 18 days
    D) 25 days
    E) 12 days
    View Answer
    Option C
    Solution
    :
    A and B complete 1/3rd, C completed 1/12 * 2 = 1/6
    Completed work before D joined is 1/3 + 1/6 = 1/2, so to be completed by D = 1 – 1/2 = 1/2 of work
    Now project uncompleted after D left = 1/3
    So D did = 1/2 – 1/3 = 1/6 of work
    He worked for 3 days, means he complete 1/6th of work in 3 days. so he can do complete project 1 in 6/1 * 3 = 18 days
  2. A who can complete project 2 in 20 days, worked for 6 days. The ratio of number of days in which B and C can complete Project 2 alone is 5 : 8. D could not come to work for project 2. Find the number of days in which B and C can complete 13/30 of project 2 together, given that if D who can complete work in 12 days had also joined the project for 4 days, the project would have been completed.
    A) 3 days
    B) 6 days
    C) 5 days
    D) 4 days
    E) 8 days
    View Answer
    Option D
    Solution
    :
    Number of days in which B and C can complete project 2 alone is 5x and 8x respectively.
    Now if D also joined for 4 days, project would have been completed, means
    6/20 + 3/5x + 4/8x + 4/12 = 1
    11/10x = 11/30
    x = 3
    So B can complete project in 5x = 15 days, and C in 8x = 24 days.
    So 13/30 work, B and C together – (1/15 + 1/24)*y = 13/30
    Solve, y = 4 days
  3. Project 3 was to be completed in 6 days. To complete project in time, all A, B, C and D decided to work in pairs in alternate days. A and C on 1st day, B and D on 2nd day, A and C on 3rd, and so on. But they could not complete project in time. What percent of project 3 remain uncompleted if A, B, C and D can complete whole project 3 in 12, 18, 20 and 15 days respectively?
    A) 27 3/4%
    B) 21 2/5%
    C) 25 1/4%
    D) 24 2/3%
    E) 23 1/3%
    View Answer
    Option E
    Solution
    :
    Project is to be completed in 6 days. They all worked in pairs on alternate means all worked for 3 days each.
    So
    On 1st day, work completed by A and C = 1/12 + 1/20 = 2/15
    On 2nd day, work completed by B and D = 1/18 + 1/25 = 11/90
    1st pair worked for 3 days, so work completed by them = 2/15 * 3 = 2/5
    Similarly, by B and D = 11/90 * 3 = 11/30
    So part of project uncompleted= 1 – (2/5 + 11/30) = 7/30
    So % = 7/30 * 100 = 70/3%
  4. B and C can complete the whole project 4 in 6 days working together. A is 20% more efficient than C and 40% less efficient that B. How many days did D work on project 4 if D can complete whole project 4 in 18 days?
    A) 5 days
    B) 4 days
    C) 2 days
    D) 1 day
    E) 6 days
    View Answer
    Option D
    Solution
    :
    Efficiency — A : C = 120 : 100 = 6 : 5
    So days ratio = 5 : 6
    Similarly, A : B = 60 : 100 = 3 : 5, so days 5 : 3
    B/A = 3/5, A/C = 5/6
    So ratio of days for B : A : C is 3 : 5 : 6 …………(1)
    Now — B and C can complete the whole project 4 in 6 days working together, and ratio of no. of days in which they can complete work alone is B and C from (1) is 3 : 6 = 1 : 2
    So
    1/x + 1/2x = 1/6
    Solve, x = 9
    So B can complete work in 8 days, C in 18 days and then A in 15 days
    Now, let D worked for ‘y’ days on project 4. So
    1/15 *5 + 1/9 * 3 + 1/18 * 2 + 1/18 * y = 1 – 1/6
    Solve, y = 1 day
  5. A, E and D worked on project numbered 5. B and C alone can complete whole project numbered 5 in 20 and 30 days respectively. E who is 3/2 times efficient than B and C together replaces both of them and worked for same number of days for which B and C had to work. A completed 1/12th of the work. Find in how many days all A, B, C, and D can complete the project 5 together.
    A) 3 days
    B) 6 days
    C) 8 days
    D) 11 days
    E) 9 days
    View Answer
    Option B
    Solution
    :
    B and C together can complete work in 12 days [1/20 + 1/30 = 5/60 — 12 days]
    Efficiency E : (B+C) = 3/2 : 1 = 3 : 2
    So, ratio of number days = 2 : 3
    3 == 12
    1 == 4
    So E can complete whole work in 2 == 8 days
    Now E worked for (2+3) = 5 days – total days for which B and C worked.
    So E completed 5/8 of work, A completed 1/12 of work. 1/12 is uncompleted work. Let x is no. of days in which D can complete whole work. So
    A’s work + E’s work + D’s work = 1 – uncompleted work
    1/12 + 5/8 + 5/x = 1 – 1/12
    Solve, x = 24 = no. of days in which D can alone complete project 5.
    A completed 1/12th work in 2 days, so he can complete whole project in 2*12 = 24 days
    A = 24, B = 20, C = 30, D = 24
    So together they can complete in – 1/24 + 1/20 + 1/30 + 1/24 = 1/6 — 6 days

Direction (6-7): Study the following charts and answer the questions that follow:

A, B and C enter into a partnership. They invest money 3 times in a year (12 months) in equal intervals. They start by investing money in ratio 4 : 2 : 3 for the first interval. For second interval, they invest money in ratio 3 : 4 : 3. And for the third interval, A invests double his previous investment, and B and C invest Rs 200 more than their respective previous investments. At the end of second interval, C’s total investment was Rs 200 less than that of A that time.

  1. If the ratio of total profit to B’s share in profit after a year is 34 : 11, find the total investment made by C?
    A) Rs 1400
    B) Rs 1800
    C) Rs 2400
    D) Rs 2200
    E) Rs 2000
    View Answer
    Option E
    Solution
    :
    3 equal intervals in 12 months = 4 months each
    A invests – 4x, 3y and 6y
    B invests – 2x, 4y and (4y+200)
    C invests – 3x, 3y and (3y+200)
    Now given that 3x + 3y = 4x + 3y – 200
    Solve, x = 200
    Ratio of profits of A : B : C is
    4x*4 + 3y*4 + 6y*4 : 2x*4 + 4y*4 + (4y+200)*4 : 3x*4 + 3y*4 + (3y+200)*4
    (4x + 9y) : (2x + 8y + 200) : (3x + 6y + 200)
    Put, x = 200
    (200+9y) : (600+8y) : (800+6y)
    Now:
    (600+8y)/(2200+23y) = 11/34
    Solve, y = 200
    So total investment of C = 3x +3y + (3y+200) = Rs 2000
  2. After 8 months, had all invested double the amount than their respective previous investment what would be the total profit at the end of year? Given that difference between the shares of profit of B and C from total profit is Rs 1300 and total of shares of profits of A and C is Rs 16250
    A) Rs 22650
    B) Rs 26250
    C) Rs 25350
    D) Rs 22850
    E) Rs 28450
    View Answer
    Option C
    Solution
    :
    Ratio of profits of A : B : C is
    4x*4 + 3y*4 + 6y*4 : 2x*4 + 4y*4 + 8y*4 : 3x*4 + 3y*4 + 6y*4
    x = 200
    So ratio becomes
    (800+9y) : (400+12y) : (600+9y)
    Now
    (400+12y-600-9y)/(1800+30y) * total profit = 1300
    and
    (800+9y+600+9y)/(1800+30y) * total profit = 16250
    Divide both equations and solve, y = 200
    So now ratio becomes
    (800+9y) : (400+12y) : (600+9y) [put y = 200]
    13 : 14 : 12
    and 2/39 * total profit = 1300
    Solve, total profit = Rs 25350

Direction (8-10): Read the following table to answer the following questions. Some values are missing in the table. Calculate the values as per given data in questions.

  1. If the total profit in 2014 is Rs 17,150, then find the ratio of the profit of B in 2015 to the profit of A in 2014.
    A) 22 : 15
    B) 25 : 16
    C) 11 : 21
    D) 20 : 13
    E) 21 : 16
    View Answer
    Option C
    Solution
    :
    Profit of A + B = (17150 – 5250) = Rs 11900
    So (A+3200) : 3000 = 11900 : 5250
    Solve A = A’s investment = Rs 3600
    So ratio of profits A : B is 3600 : 3200 = 9 : 8
    Divide their profit Rs 11900 in this ratio
    So A’s profit = 9/17 * 11900 = Rs 6300
    So required ratio = 3300 : 6300 = 11 : 21
  2. Total investment made by A, B and C in 2015 was Rs 8400. Profit earned by A in 2015 is approximate what % more than the investment made by C in 2015?
    A) 65%
    B) 57%
    C) 48%
    D) 42%
    E) 68%
    View Answer
    Option B
    Solution
    :
    Total investment of A and C is 8400 – 2400 = Rs 6000 ……….(1)
    So ratio in shares of profit of B : (A+C) is 24 : 60 = 2 : 5
    Now profit of B is Rs 3300
    So 2/(2+5) *x = 11550
    So x = total profit = Rs 11550
    So profit of A = (11550 – (3300+3850)) = Rs 4400
    Now profit ratio of A : C is 4400 : 3850 = 8 : 7 which is also investment ratio of A and C ………(2)
    From (1) and (2), investment 0f C = 7/15 * 6000 = 2800
    So required % = (4400-2800)/2800 * 100 = 57%
  3. Total profit earned by all in 2016 is Rs 17,400 and the ratio of investment made by A and B together and investment made by B and C together is 21 : 20. Then find the difference between the profit made by B and C in 2016.
    A) Rs 2200
    B) Rs 2800
    C) Rs 3000
    D) Rs 2400
    E) None of these
    View Answer
    Option D
    Solution
    :
    Profit earned by all in 2016 is Rs 17,400
    (1800+2400/(2400+C) = 21/20
    So, C’s investment is Rs 1600
    So ratio of their profit sharing is 9 : 12 : 8
    So difference in profits of B and C is (12-8)/(9+12+8) * 17400 = Rs 2400

Click here for Quantitative Aptitude Questions

 


Quantitative Aptitude: Data Interpretation Questions Set 154

Direction: Given below the table shows the total number of books shopkeeper and also given that the ratio of Math ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 153

Pie-chart given below shows number of persons come to watch films in five different malls. Study the data and answer ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 152

Study the following and answer the questions:There are two colleges,one is old and one is new.Both colleges have four different ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 151

Study the following and answer the questions:The ratio of male to female employees in a university is 5 : 7 ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 150

Study the information carefully to answer the questions:A college consisting of a total of 1560 students has males and females ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 149

Study the information to answer the given questions:In a university out of 600 candidates, males and females are in the ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 148

Directions (1-5): Study the following information carefully to answer the following: Rajaji college has five different types of groups, Maths, ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 147

Directions (1-5): Study the following information carefully and answer the questions that follow: The following bar graph shows the production ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 146

Directions (1-5): Study the following information carefully and answer the questions that follow:The following pie chart shows the percentage distribution ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 145

Directions (1-5): Study the following information carefully and answer the questions that follow: There are three garments A, B and ...
Read More

Chapter Based DI

 

Quantitative Aptitude: Data Interpretation Questions – Set 72

Direction (1-5): The following table shows the expenditure and income of a certain company in 5 years. Upon which its ...
Read More

Quantitative Aptitude: Data Interpretation Questions – Set 71

Direction (1-5): Study the following table and answer the questions that follow: What is the number of employees in Finance ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 67 (Chapter Based)

New Pattern Data Interpretation Questions. SBI PO Mains chapter based Data Interpretation Questions - Time and Work, and Partnership. Directions ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 59

Data Interpretation on Boats and Streams, Partnership. Chapter based DIs based on SBI PO 2017 Mains Pattern - for IBPS ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 43 (Missing DI)

Missing DI, Data Interpretation Questions for IBPS PO, IBPS Clerk, NIACL, NICL, SBI PO, RBI Grade B, Dena Bank PO ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 42

Data Interpretation Questions (DI) for IBPS PO 2017, IBPS Clerk, NIACL, NICL, SBI PO, RBI Grade B, Dena Bank PO ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 41

Data Interpretation Questions (DI) for IBPS PO 2017, IBPS PO, NIACL, NICL, SBI PO RBI Grade B, Dena Bank PO ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 40

Data Interpretation Questions (DI) for IBPS PO 2017, IBPS PO, NIACL, NICL, SBI PO RBI Grade B, Dena Bank PO ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 39

Data Interpretation Questions (DI) for IBPS PO 2017, IBPS PO, NIACL, NICL, SBI PO RBI Grade B, Dena Bank PO ...
Read More

Quantitative Aptitude: Data Interpretation Questions Set 38

Data Interpretation Questions (DI) for IBPS PO 2017, IBPS PO, NIACL, NICL, SBI PO RBI Grade B, Dena Bank PO ...
Read More
Loading...